A surveyor is trying to find the length of a lake. He finds a baseline distance AB of 125 m. Angle A is measured to be 41.6° and angle B is measured at 124.3°. Find the length of the lake d. Please and Thank you.

Answers

Answer 1

Answer:

[tex]d = 340.7m[/tex]

Step-by-step explanation:

See attachment for question illustration

From the attachment, we have:

[tex]AB = 125m[/tex]

[tex]<A = 41.6[/tex]

[tex]<B = 124.3[/tex]

Required

Solve d

First, we need to calculate <C

[tex]<A + <B + <C = 180[/tex] --- angles in a triangle

[tex]41.6+ 124.3 + <C = 180[/tex]

[tex]165.9+ <C = 180[/tex]

Make <C the subject

[tex]<C = 180 - 165.9[/tex]

[tex]<C = 14.1[/tex]

Next, we apply Sine's law to solve for d

[tex]\frac{A}{Sin\ A} = \frac{B}{Sin\ B} =\frac{C}{Sin\ C}[/tex]

In this case:

[tex]\frac{d}{Sin\ 41.6} = \frac{125}{Sin\ 14.1}[/tex]

Make d the subject

[tex]d = \frac{125 * sin\ 41.6}{sin 14.1}[/tex]

[tex]d = \frac{125 * 0.66392621265}{0.24361501178}[/tex]

[tex]d = \frac{82.9907765812}{0.24361501178}[/tex]

[tex]d = 340.663639629[/tex]

[tex]d = 340.7m[/tex]

Hence, the base of the lake is approximately 340.7m

A Surveyor Is Trying To Find The Length Of A Lake. He Finds A Baseline Distance AB Of 125 M. Angle A

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Answers

Answer:

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Step-by-step explanation:

Answer: The initial value is 150 and the rate of change is 30

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Answers

Answer:

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Step-by-step explanation:

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To find total multiply 55 by number of hours (h) and then add 25:

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Answers

Answer:

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Step-by-step explanation:

Answer:

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Answers

Answer:

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Step-by-step explanation:

Given that :

Principal = 4000

Interest (r) = 6.25% compounded annually

Calculate time, t, if final amount A = 9600

Using the compound interest formula :

A = P(1 + r/n)^n*t

A = final amount

n = number of times interest is applied per period

9600 = 4000(1 + 0.0625)^t

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Answers

Answer:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

1) the probability that he wins the second game is 0.45

2) the probability he wins the first game given that he won the second game is 0.333  

3) Expected Value is $ 1.5 and the variance is 0.75

Step-by-step explanation:

Given the data in the question;

Let Win1 represent first game victory

and Loss1 represent first game loss

Let Win2 denote second game victory

and Loss2 denote second game loss

now from the Tree diagram of Daniel;

P ( Win1 ) = 0.6

P ( Loss1 ) = 0.4

P ( Win2 | Win1 ) = 0.25

P ( Loss2 | Win1 ) = 0.75

P ( Win2 | Loss1 ) = 0.75

P ( Loss2 | Loss1 ) = 0.25

1) probability that he wins the second game will be;

P ( Win2 )  =  [P ( Win1 ) × P ( Win2 | Win1 )] + [P ( Loss1 ) × P ( Win2 | Loss1 ) ]

we substitute

= [0.6 × 0.25] + [0.4 * 0.75] = 0.45

Therefore the probability that he wins the second game is 0.45

2)

If he wins the second game, what is the probability that he also won the first game  will be;

{From Bayes' Theorem}

P ( Win1 | Win2 )  =  P ( Win1 ) × P ( Win2 | Win1 ) / P ( Win2 )

= 0.6 × 0.25 / 0.45 = 0.333  

Therefore the probability he wins the first game given that he won the second game is 0.333  

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winnings       probability

$0                  0.4 × 0.25 = 0.1

$1                   0.6 × 0.75 = 0.45

$2                  0.4 × 0.75 = 0.3

$3                  0.6 × 0.25 = 0.15

so Expected Value = ∑( winnings × individual win probability)

=  (0 × 0.1) + (1 × 0.45) + (2 × 0.3) + (3 × 0.15)

= 0 + 0.45 + 0.6 + 0.45

= $ 1.5

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so

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Step-by-step explanation:

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Step-by-step explanation:

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