Answer:
The new angular speed of both disks when they are rotating together is 2.311 revolutions per second.
Explanation:
This situation can be analyzed by the Principle of Conservation of Angular Momentum since there are no external forces and moments being exerted on the system, whose definition is presented below:
[tex]I_{o}\cdot \omega_{o} = I_{f}\cdot \omega_{f}[/tex] (1)
Where:
[tex]\omega_{o}[/tex], [tex]\omega_{f}[/tex] - Initial and final angular speeds, measured in revolutions per second.
[tex]I_{o}, I_{f}[/tex] - Initial and final moments of inertia, measured in kilograms per square meter.
The initial and final moments of inertia of the system are, respectively:
[tex]I_{o} = \frac{1}{2}\cdot m_{o}\cdot r_{o}^{2}[/tex] (2)
[tex]I_{f} = \frac{1}{2}\cdot \left[m_{o}\cdot r_{o}^{2}+\frac{1}{2}\cdot m_{o}\cdot \left(\frac{1}{2}\cdot r_{o} \right)^{2}\right][/tex]
[tex]I_{f} = \frac{1}{2}\cdot m_{o}\cdot r_{o}^{2}+\frac{1}{16}\cdot m_{o}\cdot r_{o}^{2}[/tex]
[tex]I_{f} = \frac{9}{16}\cdot m_{o}\cdot r_{o}^{2}[/tex] (3)
By applying (2) and (3) in (1), we obtain the following expression:
[tex]\frac{1}{2}\cdot m_{o}\cdot r_{o}^{2}\cdot \omega_{o} = \frac{9}{16}\cdot m_{o}\cdot r_{o}^{2}\cdot \omega_{f}[/tex]
[tex]\frac{1}{2}\cdot \omega_{o} = \frac{9}{16}\cdot \omega_{f}[/tex]
[tex]\omega_{f} = \frac{8}{9}\cdot \omega_{o}[/tex] (4)
If we know that [tex]\omega_{o} = 2.6\,\frac{rev}{s}[/tex], then the new angular speed of both disks when they are rotating together is:
[tex]\omega_{f} = \frac{8}{9}\cdot \left(2.6\,\frac{rev}{s} \right)[/tex]
[tex]\omega_{f} = 2.311\,\frac{rev}{s}[/tex]
The new angular speed of both disks when they are rotating together is 2.311 revolutions per second.
For a polymer that was maintained at constant strain, an initial stress of 2.76 MPa decreases to 1.72 MPa after 6 hr. Estimate the stress remaining after 30 hr.
Answer:
1.48 Mpa
Explanation:
Given that For a polymer that was maintained at constant strain, an initial stress of 2.76 MPa decreases to 1.72 MPa after 6 hr. To estimate the stress remaining after 30 hr, we must first find the decay constant by using the exponential equation.
Therefore, the estimate of the stress remaining after 30 hr, is 1.48Mpa.
Please find the attached file for the solution.
Match the scienntist with their accomplishment / discoveries
Answer:
newton - motion, gravity
kepler - orbital paths
brahe - the sun goes around the earth
Explanation:
im not sure about brahe but its the only one that makes sense
Through what angle in degrees does a 33 rpm record turn in 0.32 s?
63°
35°
46°
74°
Answer:
1 rev = 2(pi) rad pi(rad) = 180 degrees
so 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s = 63.36 degrees
Explanation:
63.36 estimated to 63 so 63
The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.
Calculation of the angle:Since we know that1 rev = 2(pi) rad
So here pi(rad) = 180 degrees
Now for 33 rpm it should be like
= 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s
= 63.36 degrees
= 63 degrees
hence, The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.
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what is mean by combination reaction ?
[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]
Those reaction in which two or more substances combine to form a one new substance are called Combination reaction
In this reaction, We can add :
Two or more elements can combine to form a compound.Two or more compounds can combine to from a one new compound.An element and a compound can combine to form a new compound.[tex] \underline{\green{\large \sf For\: example :}} [/tex]
[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]
In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.
Help me please..
Velocity is defined as a
and a?
A) speed, direction
B) change, direction
C) speed, acceleration
D) change, acceleration
Answer:
Speed and direction.....
What is the relationship in Newton's second law between force, mass and acceleration?
Answer:
Newton's second law of motion states that the acceleration of a system is directly proportional to and in the same direction as the net external force acting on the system, and inversely proportional to its mass. If the only force acting on an object is due to gravity, the object is in free fall.
The speed of sound in air is 10 times faster than the speed of a wave on a certain string. The density of the string is 0.002kg/m. The tension in the string is __________.
Answer:
The tension on the string is 2.353 N.
Explanation:
Given;
the speed of sound in air, v₀ = 343 m/s
then, the speed of sound on the string, v = 343 / 10 = 34.3 m/s
mass per unit length, m/l = μ = 0.002 kg/m
The speed of sound on the string is given as;
[tex]v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu} \\\\T = v^2 \mu[/tex]
where;
T is the tension on the string
T = (34.3)²(0.002)
T = 2.353 N
Therefore, the tension on the string is 2.353 N.
Help me please,
A ball is thrown straight up in the air. What is the velocity and acceleration at the top of the path?
A) v 0m/s, = 0m/s/s
B) v = 0m/s, a 10m/s/s
C) v = 10m/s, a 10m/s/s
D) v = 10m/s, a = 0m/s/s
E) None of the above
Option B
Explanation:
no distance was given only the acceleration due to the fact that it went up (10m/s/s)
s0 it is
0 m/s and 10m/s/s (option B)
A popular ride at an amusment park lifts
customers up to a height of 50 m and then
drops them threw a displacement of 50 m
before slowing them to a stop. How fast
are the customers going at the 50 m
mark?
Answer:
[tex]31.32\ m/s[/tex]
Explanation:
[tex]We\ are\ given\ that:\\Height\ to\ which\ there're\ lifted=50m\\Displacement\ during\ the\ descent=50m\\Now,\\In\ order\ to\ find\ the\ velocity\ of\ the\ customers\ at\ 50\ m,\\We\ can\ use\ the\ Third\ Equation\ Of\ Motion,\ which is:\\2as=v^2-u^2\\As\ we\ know\ that,\\Acceleration\ due\ to\ gravity=9.81\ m/s^2\ or\ roughly\ 10\ m/s^2\\Displacement=50\ m\\Initial\ velocity=0\ m/s^2\\ [As\ they\ stop\ when\ they\ reach\ the\ maximum\ height\ of\ 50\ m\\ and\ begin\ their\ descent][/tex]
[tex]By\ reconstructing\ the\ Third\ Equation\ Of\ Motion,\ we\ have:\\2gs=v^2\\Hence,\\v^2=2*9.81*50 \\v^2=981\ m^2/s^2 \\v=\sqrt{981\ m^2/s^2} \\v=31.32\ m/s[/tex]
Suppose a uniform solid sphere of mass M and radius R rolls without slipping down an inclined plane starting from rest. The linear velocity of the sphere at the bottom of the incline depends on?
Answer:
None of the mass or the radius of the sphere
Explanation:
When a uniform solid sphere of any given mass, say M and any given radius, say R, rolls without slipping downwards an inclined plane that starts from rest. The linear velocity of the sphere at about the bottom of the inclined happens not to depend on either of its mass or that of the radius of its sphere.
Running up a hill instead of a flat surface will increase which principle of fitness?
A. Intensity
B. Specificity
C. Time
D. Tedium
Answer:
a
Explanation:
Answer:
im pretty sure its intensity
Explanation:
A carousel at the local carnival rotates once every 45 seconds.
(a) What is the linear speed of an outer horse on the carousel, which is 2.75 m from the axis of rotation?
(b) What is the linear speed of an inner horse that is 1.75 m from the axis of rotation?
Answer:
We know that the carousel does a complete rotation in 45 seconds.
Then the frequency of this carousel will be f = 1/45 seconds.
And the angular frequency will be 2*pi times the frequency, then we have:
angular frequency = w = 2*3.14*(1/45s) = 0.1396 s^-1
Now, the linear speed of an object that rotates with a radius R, and an angular frequency W is:
S = R*W
then:
a) in this case the radius is 2.75m, then the linear speed is:
S = 2.75m*0.1396 s^-1 = 0.3839 m/s
b) in this case the radius is 1.75m, then the linear speed here is:
S = 1.75m*0.1396 s^-1 = 0.2443 m/s
(a) The linear speed of an outer horse on the carousel is 0.384 m/s.
(b) The linear speed of an inner horse on the carousel is 0.244 m/s.
Given data:
The time interval for the rotation of carousel is, t = 45 s.
The distance of the outer horse from the axis of rotation is, r = 2.75 m.
The distance of an inner horse from the axis of rotation is, r' = 1.75 m.
(a)
The linear speed in this problem can be obtained from the concept of rotational mechanic, in which the ratio of the circumference and the time gives required linear speed. So,
v = 2 π r/t
Solving as,
v = 2 π (2.75) / 45
v = 0.384 m/s
Thus, we can conclude that the linear speed of an outer horse on the carousel is 0.384 m/s.
(b)
Now similarly the linear speed of an inner horse is calculated as,
v' = 2 π r' / t
Solving as,
v' = 2 π (1.75) / 45
v' = 0.244 m/s
Thus, we can conclude that the linear speed of an outer horse on the carousel is 0.244 m/s.
Learn more about the rotational mechanics here:
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A woman pulls a 7.87 kg suitcase,
initially at rest, with a 29.2 N force
along the handle at 62.7° Friction
pulls back at 11.7 N, and the
suitcase moves 8.44 m. What is
the total work done?
(Unit = J)
Answer:
Effective Pulling Force = 29.2(cos 62.7°) = 13.393 N
Resistance to Pulling Force = 11.7 N
Net Force acting on suitcase = 13.393 - 11.7 = 1.693 N
Distance moved = 8.44 m
Net Work = 1.693(8.44) = 14.289 ≈ 14.3 J ANS
Explanation:
hope that makes sense homie
Answer:
14.3
Explanation:
right answer for acellus
A force of 64 N gives an object an acceleration of 23.53 m/s^2. What is the mass of the object?
A-2.00 kg
B-1505 kg
C-2.72 kg
D-736 kg
*
If a rock falls for 3 seconds off of a bridge, how far will the rock fall?
-30 m
-45m
-60m
-75m
A tennis ball moves 16 meters northward, then 22 meters southward, then 12 meters northward, and finally 32 meters southward.
Determine the magnitude of the distance the object traveled and the magnitude and direction of the displacement.
Answer:
The answer is 8m N
Explanation:
When a tennis ball moves 16 meters northward, then 22 meters southward, then 12 meters northward, and finally 32 meters southward. then the distance traveled by it is 82 m and the displacement covered by it is 26 m in a southward direction
What is displacement?
An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard. Displacement describes this shift in location.
Displacement is a vector quantity. This indicates that it has both a direction and a magnitude and that it is visually represented as an arrow that points from the starting position to the ending position.
Thus, when a tennis ball travels 16 meters to the north, 22 meters to the south, 12 meters to the north, and 32 meters to the south. then it has a covered distance of 82 meters and has covered 26 meters of displacement in a southerly direction.
Learn more about displacement here
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#SPJ2
What electromagnetic wave is a is a TV remtoe
Answer:
infared radiation
Explanation:
An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 28.3 m/s. It then flies a further distance of 48900 m, and afterwards, its velocity is 45.5 m/s. Find the airplane's acceleration (m/s^2) and calculate how much time elapses (s) while the airplane covers those 40500 m.
Answer:
a==0.012979m/s^2
t=662.6s
Explanation:
.
Using the Newton equation below
Vf^2 = Vi^2 + 2as
Where Vf= final velocity
Vi= initial velocity
a= acceleration
Vf=45.5 m/s
Vi=28.3 m/s
Xf=48900 m,
Xi=0
a= (Vf^2 - Vi^2)/2s
If we substitute the values,
a=(45.5^2 -28.3^2)/(2×48900)
=(2070.25-800.88)/(2×48900)
=
a= 1269.36/97800
=0.012979m/s^2
Hence, the airplane's acceleration (m/s^2) is =0.012979m/s^2
Using the Newton equation we can calculate the time
a=(vf - vi) /t
Making "t" subject of the formula, we have
t=(vf - vi) /a
a=0.012979m/s^2
If we substitute the values, where
, we have
t= (45.5-28.3)/(2×=0.012979)
=17.2/0.025958
=662.6s
Hence, time elapses (s) while the airplane covers those 40500 m. Is =662.6s
20 pts.
Which of the following statements is true?
O Electromagnets use electrlcity and magnets.
O Magnetic fields are strongest around the poles of a magnet.
O The south pole of a magnet will repel the south pole of another magnet.
O all of the above
Answer:
all are true so d is right
Explanation:
Electromagnets use electrlcity and magnets is true.
Magnetic fields are strongest around the poles of a magnet is true.
The south pole of a magnet will repel the south pole of another magnet is true
and since all of them is true the answer is d all of the above
The average speed of a car that drives 140 kilometers in 2 hours
Answer:
240 kilometer
Explanation:
ur just mutipling the number by 2
Your average speed was 70.0 Kilometers per hour (km/h)
A 1.2-kg object moving with a speed of 8.0 m/s collides perpendicularly with a wall and emerges with a speed of 6.0 m/s in the opposite direction. If the object is in contact with the wall for 2.0 ms, what is the magnitude of the average force on the object by the wall?
a. 9.8 kN.
b. 8.4 kN.
c. 7.7 kN.
d. 9.1 kN.
e. 1.2 kN.
Given that,
Mass of the object, m = 1.2 kg
Initial speed of the object, u = 8 m/s
Final speed of the object, v = -6 m/s (in opposite direction)
Time, t = 2 ms
To find,
The average force on the object by the wall.
Solution,
Let F be the force. Using Newton's second law of motion,
F = ma, a is acceleration
[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{1.2\times ((-6)-8)}{2\times 10^{-3}}\\\\=8400\ N[/tex]
or
F = 8.4 N
So, the magnitude of average force in the object by the wall is 8.4 N.
An airplane wing is designed so that the speed of the air across the top of the wing is 297 m/s when the speed of the air below the wing is 209 m/s. The density of the air is 1.29 kg/m3. What is the lifting force on a wing of area 26.0 m2?
Answer:
The value is [tex]F_L = 759200 \ N[/tex]
Explanation:
From the question we are told that
The speed of air across the top of its wings is [tex]v = 297 \ m/s[/tex]
The speed of air below its wings is [tex]u = 209 \ m/s[/tex]
The density of air is [tex]\rho = 1.29 \ kg/m^3[/tex]
The area of the wing is [tex]A = 26.0 \ m^2[/tex]
Generally the lifting force is mathematically represented as
[tex]F_L = \Delta P * A[/tex]
Here [tex]\Delta P[/tex] is the difference in kinetic energy density between the top and the bottom
[tex]\Delta P = \frac{1}{2} * \rho * [v^2 - u^2 ][/tex]
=> [tex]\Delta P = \frac{1}{2} * 1.29 * [297^2 - 209^2 ][/tex]
=> [tex]\Delta P = 2.92 *10^{4} \ Pa[/tex]
So
[tex]F_L = 2.92 *10^{4} * 26.0[/tex]
=> [tex]F_L = 759200 \ N[/tex]
What is the condition required of the phase difference (in radians) between two waves with the same wavelength if these waves interfere constructively?
a. (2m +1)π where m= 0, +1, +2, etc.
b. mπ where m = 0, +1, +2, etc.
c. 2mπ where m = 0, +1, +2, etc.
d. (m+1)π where m = 0, +1, +2, etc.
Answer:
c.
Explanation:
In order to two waves with the same wavelength can interfere constructively, their crests and valleys must coincide in space, so the phase difference must be equal to an integer number of wavelengths, i.e. m *(2 π rad), where m= 0, +1, +2, etc.This is equal to the stated by the answer c) , so c) it's the right answer.PHYSICS! HELP ME PLEASE ASAP!
1.) If an ambulance passes you while you're walking your dog, a change in pitch is ____?
A.) not perceived by either the pedestrian or you
B.) perceived by the you
C.) perceived by the driver
2.) In the star wars movies, the soundtrack is very important. musicians and sound technicians spend weeks perfecting the noise of the light sabers, lasers, tie fighters and explosions. in real life, there would be no sound at all in space. Why?
A.) mechanical waves require a medium to travel
B.) sound is an electromagnetic wave
C.) mechanical waves do not require a medium to travel
D.) sound is a product of vibration
3.) what is a compression?
A.) region of zero pressure in a medium caused by a wave passing
B.)region of a high altitude in a medium caused by a passing wave
C.) region of a high pressure in a medium cause by a passing wave
D.) region of low pressure in a medium caused by a passing wave
Answer:
1B, 2B and 3C hope this helps
Explanation:
Light of wavelength 650 nm is normally incident on the rear of a grating. The first bright fringe (other than the central one) is at an angle of 5o with respect to the normal.
A. Find the number of slits per centimeter in the grating.
B. Two rays of light of wavelength 650 nm and 420 nm are normally incident on a different grating. If the grating has 5000 slits/cm, what is the angular seperation of of the two light rays' second order maximum?
Answer:
A
[tex]N = 1340.86 \ slits / cm[/tex]
B
[tex]\theta = 15.7^o[/tex]
Explanation:
From the question we are told that
The wavelength is [tex]\lambda = 650 \ nm = 650 *10^{-9} \ m[/tex]
The angle of first bright fringe is [tex]\theta = 5^o[/tex]
The order of the fringe considered is n =1
Generally the condition for constructive interference is
[tex]dsin (\theta ) = n * \lambda[/tex]
=> [tex]d = \frac{1 * 650 *10^{-9 }}{ sin(5)}[/tex]
=> [tex]d = 7.458 *10^{-6} \ m[/tex]
Converting to cm
[tex]d = 7.458 *10^{-6} \ m = 7.458 *10^{-6} * 100 = 0.0007458 \ cm[/tex]
Generally the number of grating pre centimeter is mathematically represented as
[tex]N = \frac{1}{d}[/tex]
=> [tex]N = \frac{1}{0.0007458}[/tex]
=> [tex]N = 1340.86 \ slits / cm[/tex]
Considering question B
From the question we are told that
The first wavelength is [tex]\lambda_1 = 650 \ nm = 650 *10^{-9} \ m[/tex]
The second wavelength is [tex]\lambda_2 = 429 \ m = 420 *10^{-9 } \ m[/tex]
The order of the fringe is [tex]n = 2[/tex]
The grating is [tex]N = 5000 \ slits / cm[/tex]
Generally the slit width is mathematically represented as
[tex]d = \frac{1}{N }[/tex]
=> [tex]d = \frac{1}{ 5000 }[/tex]
=> [tex]d = 0.0002 \ c m = 2.0 *10^{-6} \ m[/tex]
Generally the condition for constructive interference for the first ray is mathematically represented as
[tex]d sin(\theta_1) = n * \lambda_1[/tex]
=> [tex]\theta_1 = sin^{-1} [\frac{ 2 * \lambda }{d}][/tex]
=> [tex]\theta_1 = sin^{-1} [\frac{ 2 * 650 *10^{-9} }{ 2*10^{-6}}][/tex]
=> [tex]\theta_1 = 40.5 ^o[/tex]
Generally the condition for constructive interference for the second ray is mathematically represented as
[tex]d sin(\theta_2) = n * \lambda_2[/tex]
=> [tex]\theta_2 = sin^{-1} [\frac{ 2 * \lambda_1 }{d}][/tex]
=> [tex]\theta_2 = sin^{-1} [\frac{ 2 * 420 *10^{-9} }{ 2*10^{-6}}][/tex]
=> [tex]\theta_2 = 24.8 ^o[/tex]
Generally the angular separation is mathematically represented as
[tex]\theta = \theta_1 - \theta_1[/tex]
=> [tex]\theta = 42.5^o - 24.8^o[/tex]
=> [tex]\theta = 15.7^o[/tex]
Define conductor and insulator, including how the resistance is different in the two, and give at least one example of each.
Answer:
Those substances which can conduct electricity are called conductors, while those substances which don't conduct electricity are called insulators.
Resistance is the obstruction provided by the material through which the current passes,so since conductors conduct electricity and insulators don't,so the obstruction i.e resistance provided by the conductor must be less,while insulators being unable to conduct electricity,has very high resistance.
Example of conductor is copper
Example of insulator is plastic
In simple harmonic motion, the acceleration is proportional to In simple harmonic motion, the acceleration is proportional to:_________.
a. the amplitude.
b. the velocity.
c. the frequency.
d. the displacement.
e. all of the above
Answer:
e. all of the above
Explanation:
In simple harmonic motion, the acceleration is given as;
a = -ω²x = -(2πf)²x
[tex]a_{max} = -\omega ^2A[/tex]
where;
ω is the angular velocity
f is the frequency
x is the displacement
A is the amplitude
Thus, In simple harmonic motion, the acceleration is proportional to the amplitude, velocity, frequency, and displacement.
The correct option is E.
"all of the above"
WILL MARK BRAINLIEST JUST PLEASE HELP
Answer:
40N in either direction is the answer
Pure sodium metal explodes when it makes contact with water, and chlorine, in its natural state, is a deadly, poisonous gas. When these two chemicals combine, they form a harmless, white powder known as sodium chloride or table salt. Which of the following statements does this information support?
A.The properties of substances change during chemical reactions but then later go back to their original condition.
B.Heat must be added in order to change the chemical properties of substances.
C.When substances are chemically combined, the properties of the new substances that are formed are often different from the properties of the original substances.
D.When substances are chemically combined, the properties of the new substances that are formed are the same as the properties of the original substances.
Answer: When substances are chemically combined, the properties of the new substances that are formed are often different from the properties of the original substances.
Explanation:
Find the current if 55 C of charge pass a particular point in a circuit in 5 seconds.
Answer:
The current is 11 Amperes
Explanation:
Electric Current
The electric current is defined as a stream of charged particles that move through a conductive path.
The current intensity can be calculated as:
[tex]\displaystyle I=\frac{Q}{t}[/tex]
Where:
Q = Electric charge
t = Time taken by the charge to move through the conductor
The current intensity is often measured in Amperes.
The charge passing through a point in a circuit is Q= 55 c during t=5 seconds, thus the current intensity is:
[tex]\displaystyle I=\frac{55}{5}[/tex]
I = 11 Amp
The current is 11 Amperes