A small boat leaves a port town and travels due north for 7.4 miles and then turns due east for 3.6 miles
and stops. If the boat's captain then turns back to town. a) how far does the boat travel and b) along
what bearing would the boat have to travel from its stopped position?

Answers

Answer 1

11 miles far does the boat travel

Step-by-step explanation:

hope it helps

Answer 2

The total distance travelled will be 22 miles and the bearing will be 60.89° .

It is given that a boat travels from port town to north for 7.4 miles and then east for 3.6 miles and stops at destination.

We have to find out the total distance travelled and bearing from stopped position.

What are bearings ?

A bearing is the angle in degrees measured clockwise from north i.e., 30° from north.

As per the question ;

Boat travels from port town to north for 7.4 miles and then east for 3.6 miles and it then stops at destination.

So ;

a)

Total distance travelled from port town to destination is ;

= 7.4 miles + 3.6 miles

= 11 miles

And

If boat's captain turns back to town , then total distance will be ;

= 11 + 11

= 22 miles

b)

We know that ;

cos θ = B/H

The bearing would be ;

cos θ = [tex]\frac{3.6}{7.4}[/tex]

cos θ = 0.486

θ = [tex]cos^{-1}[/tex] (0.486)

θ = 60.89°

Thus , the total distance travelled will be 22 miles and the bearing will be 60.89° .

To learn more about bearings click here ;

https://brainly.com/question/22979538

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Answers

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Answer:

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Answers

Answer:

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