a school is arranging a field trip. the school spends 814.98 dollars on passes for 32 students and 2 teachers. they also spend 309.76 dollars on lunch for just the students. how much money was spent on a pass and lunch for each student?

Answer:

5.36

Step-by-step explanation:

If the car travels for 4 hours on the highway at a rate of 65 miles per hour,12.4 gallons of gas should the car used, to the nearest tenth of a gallon.

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has basic four operators that are +, -, ×, and ÷.

It is given that a car can go 21 miles per gallon of gas on a highway and that the car can travel for 4 hours at a speed of 65 miles per hour.

As a result, the distance traveled by car,

Distance = speed × time

Distance = 65 miles / hr × 4 hr

Distance = 260 miles

The number of gallons of gas the car should consume is determined by dividing the entire distance driven by the per gallon of gas as follows:

= 260 miles / 21 miles per gallon

= 12.38 gallon

The value nearest tenth of a gallon is,

=12.4 gallons

Thus, if the car travels for 4 hours on the highway at a rate of 65 miles per hour,12.4 gallons of gas should the car used, to the nearest tenth of a gallon.

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Answer:

  0.4 kg

Step-by-step explanation:

A proportion can be used to find the amount of sugar.

  x/(1.1 L) = (0.1 kg)/(0.275 L)

  x = (1.1)(0.1)/0.275 kg = 0.4 kg

Angela needs 0.4 kg of sugar for her biscuits.

Answer:

4

3

+

5

9

2

−

8

0

Step-by-step explanation:

the average weight of 4boys 39.6 is Wight

Answer:

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Pumpkins are used as decorations during the fall months.

Answer:

Zero-product property.

Step-by-step explanation:

[tex]\text{If}~ ab =0\\\\\text{then}~ a=0~ \text{or}~ b=0[/tex]

Answer:

x= 5 ........................ .......

Answer:

1.5

Step-by-step explanation:

Four goes into six once, then four goes into 20 5 times

Answer:

Red: y=4

Green: x=-1

Yellow: x=6

Blue: x=-2

Step-by-step explanation:

The lines are all passing through the Axis, so there is no slope for each line.

[tex]\dfrac{0.25}a = -0.25\\\\\implies 0.25 = -0.25 a\\\\\implies a = \dfrac{0.25}{-0.25} =-1\\\\\\\text{Hence the answer is}~ -1.[/tex]

Answer:

well, when you divide 1/.25 you get 4 so 1^.25 is the correct answer to all questions where you need to find the answer

Step-by-step explanation:

Answer:

Step-by-step explanation:

The slope is the cost of a renewal: $10.

The y-intercept is the initial cost: $65.

There are 20 red marbles

Since the probability of randomly choosing a blue marble is 5/9, then the probability of choosing a red marble will be:

= 1 - 5/9

= 4/9

If there are 45 marbles in total, the number of red marbles will be:

= 4/9 × 45

= 20

Therefore, there are 20 red marbles.

[tex]\text{Given that,}\\\\\cos \theta = - \dfrac 23\\\\\implies \cos^2 \theta = \dfrac 49\\\\\implies 1- \sin^2 \theta = \dfrac 49\\\\\implies \sin^2 \theta =1-\dfrac 49\\\\\implies \sin^2 \theta =\dfrac 59\\\\\\\text{Now,}\\\\\cot^2 \theta = \dfrac{\cos^2 \theta}{\sin^2 \theta} \\\\\\\implies \cot^2 \theta = \dfrac{\tfrac 49}{\tfrac 59}\\\\\\\implies \cot^2 \theta = \dfrac 49 \times \dfrac 95\\\\\\\implies \cot^2 \theta = \dfrac 45\\\\\\[/tex]

[tex]\implies \cot \theta = \pm\sqrt{\dfrac 45} = \pm \dfrac 2{\sqrt 5}\\\\\\\text{Since}~ \theta ~ \text{lies in the second quadrant,} \cot \theta ~\text{will be negative.}\\\\\text{Hence,}~ \cot \theta = - \dfrac{2}{\sqrt 5}[/tex]

Answer:

yysywywyyw7e7eueuuwuwuuwueu3u3

Divide total by number of days:

367/5 = 73.40 per day

Answer:

x = 29

Step-by-step explanation:

64°+y°+y° = 180°

64+2y = 180

2y = 116

y = 58

(180°-58°)+2x° = 180

122+2x = 180

2x = 58

x = 29

This is an example of substitution because you have substituted the 'y' variable to find the 'x' variable.

Hoped this helped.

[tex]BrainiacUser1357[/tex]

The function represents the graph is (d) [tex]y = \sqrt[3]{x+3} + 3[/tex]

The points on the graph are given as:

[tex](x,y) = (-3,3)[/tex] --- the inflection point

[tex](x,y) = (0,4.5)[/tex] --- the y-intercept

The function that satisfy the above points is:

[tex]y = \sqrt[3]{x+3} + 3[/tex]

The proof is as follows:

At the inflection point, we have the x value to be -3.

So, the function becomes

[tex]y = \sqrt[3]{x+3} + 3[/tex]

[tex]y = \sqrt[3]{-3+3} + 3[/tex]

[tex]y = \sqrt[3]{0} + 3[/tex]

[tex]y = 0+ 3[/tex]

[tex]y = 3[/tex] ---- the y-value at the inflection point is true for x = -3

Also, at the y-intercept, we have the x-value to be 0

So, the function becomes

[tex]y = \sqrt[3]{x+3} + 3[/tex]

[tex]y = \sqrt[3]{0+3} + 3[/tex]

[tex]y = \sqrt[3]{3} + 3[/tex]

[tex]y = 1.45+ 3[/tex]

[tex]y = 4.45[/tex] ---- the y-value at the y-intercept is true for x = 0

Hence, the function represents the graph is (d) [tex]y = \sqrt[3]{x+3} + 3[/tex]

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Answer:

D

Step-by-step explanation:

Answer:

10\frac{7}{12}

Step-by-step explanation:

First thing you want to do is find the common denominator for \frac{1}{3} and \frac{3}{4}. You do this by multiplying to denominators together, so 3*4=12.

Next, multiple the numerators with the opposite denominator. 1*4=4 and 3*3=9.

Now you are left with \frac{4][12] and \frac{9}{12}.

Add those back to your numbers

16\frac{4}{12} - 5\frac{9}{12} = 10\frac{7}{12}

Answer:

4000 sqft

Step-by-step explanation:

you multiply 5*10 which equals 50 then 8*10 which equals 80 then to find area you multiply 50*80 which equals 4000 sqft

The factorization of the given expression is 2ab(b²+4a).

The given expression is 2ab³+8a²b.

A number's factors are those that divide into another number equally. A number is factorized when it is written as the sum of smaller numbers.

The given expression can be factorize as follows:

2ab³+8a²b

Here, 2ab is the common factor from both the terms, Take it out side the bracket.

That is, 2ab(b²+4a)

Therefore, the factorization of the given expression is 2ab(b²+4a).

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Answer:

[tex]\huge\color{green}\boxed{\colorbox{black}{Answer ☘}}[/tex]

To find - sum of the given two terms.

[tex](4 + 3x) + (5 - 4x + 2x {}^{2} ) \\ 4 + 3x + 5 - 4x + 2x {}^{2} \\ = > 2x {}^{2} - x + 9[/tex]

[tex]\color{purple}\boxed{\colorbox{black}{Additional Information♡}}[/tex]

we basically added the like terms together..

like, the terms ( 3x and -4x ) will be added together.. and the terms ( 4 and 5 ) will be added together...

since there's none other term having "x²" as the coefficient.. so 2x² will be left as it is!

hope helpful~

The sum of the expression 4+3x and 5-4x+2x² is 2x² + 7x + 9

Given:

4+3x

5-4x+2x²

(4+3x) + (5-4x+2x²)

= 4 + 3x + 5 - 4x + 2x²

= 2x² + 3x - 4x + 5 + 4

= 2x² + 7x + 9

Therefore, the sum of the expression is 2x² + 7x + 9

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Answer:

x = 2.3

Step-by-step explanation:

x = 5*(13-12.54) = 2.3

Answer:

127.7

Step-by-step explanation:

you do 12.54 + 13 = 25.54

then 25.54 x 5 = 127.7

Answer:

0.75 And 75%

Step-by-step explanation:

If 3/4 came then 25, 50, 75, 100 what is the 3rd number of of those 4

Answer:

270

Step-by-step explanation:

so u would take 6 and 45 and multiplay

[tex]\huge \bf༆ Answer ༄[/tex]

The additional information needed to prove that the triangles are congruent is ~ A

Answer: Choice A

Explanation:

The shorthand AAS stands for "angle angle side". The diagram shows we have a pair of congruent angles, which takes care of one "A" of "AAS". So we need info about another pair of angles to take care of that other "A".

One possible pair is angle M and angle V, or we could go for angle N and angle U. Whichever option you go for, the tickmarked sides are not between the angles mentioned. If the side was between the angles, then we'd have to use ASA which is slightly different from AAS. The order matters.

[tex]\text{Consider the slope - intercept form} ~y = mx +c,\\\\ \text{where m is the slope and and c is the y-intercept.}\\\\(a) \\\\y = -\dfrac 12 x +8 \\\\\text{This is in a form of y = mx +c, so}\\\\\text{Slope, m =}-\dfrac 12 ~ \text{and}~ \text{y - intercept , c =8}\\\\(b)\\\\y = 9x -2 \\\\\text{This is in a form of y = mx +c, so}\\\\\text{Slope, m =9}~ \text{and}~ \text{y - intercept ,}~ c =-2\\\\[/tex]

Answer:

y=3.7x + 120.3, 180

Step-by-step explanation:

Add them into a graphing calculator and you get y=3.7x + 120.3

Put 16 in for x:

3.7 (16) + 120.3

59.2 + 120.3 = 179.5, rounds to 180

Answer:

None of these

Step-by-step explanation:

None of these are correct because you would need to multiply 5 x 10 to a certain power. 5.55621 x 10 to the 8th power would do it.

Answer: I believe D is correct

Step-by-step explanation: