A sailor is walking on an aircraft carrier and is observed by a stationary barge. The sailor's velocity according to the barge is 36 m/s. At the same time, the barge observed the aircraft carrier moving at 43 m/s. What is the velocity of the sailor relative to the aircraft carrier?

The average velocity of the car is 40m/s

The average velocity of an object can be determined by dividing the change in position by the change in time.

For this situation, the vehicle begins from rest (initial velocity of 0 m/s) and arrives at a final velocity of 80 m/s.

We can use the equation:

Average velocity = (final velocity + initial velocity) / 2

Average velocity = (80 m/s + 0 m/s) / 2

Average velocity = 40 m/s

This is the average velocity of the vehicle during the entire time interval. Remember that this isn't equivalent to the instantaneous velocity at one point in time, which can be not quite the same as the average velocity.

It's important to take note of that on the off chance that the vehicle's speed increase isn't constant, the average velocity won't rise to the final velocity in addition to the initial velocity isolated by two.

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The possible ways that heat can be transferred in this system are:

The most typical method of heat transfer is conduction, which involves the direct exchange of heat between two things.

Heat waves are created during the radiation heat transfer process and may be absorbed, reflected, or transmitted through a cooler substance. Earth is warmed by the sun using electromagnetic radiation. Heat waves come from warm bodies.

When Joiya sets the bottle of water down on a table or chair, then by conduction, heat ( or the loss of it ) would move around the table. Radiation would allow for the cold temperature to move into the air around the cold bottle.

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Options for this question include:

The distance which a force of 3N will pull a wooden block before transferring 12J of energy is 4m.

This is referred to as an influence that can change the motion of an object and the unit is Newton.

It has a relationship with distance and work which can be seen below:

Work = Force × distance

12J = 3N × d

d = 12/3 = 4m.

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(i) The power wasted in heating the wire if the current in part (a) flows in the wire is 53.8 MW.

(ii) The power wasted in heating the wire if the current in part (b) flows in the wire is 17,800 MW.

The value of the power wasted in heating the wire is calculated by applying the following formula.

P = I²R

where;

For the first case when the resistance, R = 9 Ω and current, I = I,

The power wasted is calculated as;

P = I² x 9

P = 9I²

For 22 kV, the current, I = (22,000 V) / 9 Ω

I = 2,444.44 A

P = 9 x (2,444.44)²

P = 5.38 x 10⁷ W

P = 53.8 x 10⁶ W

P = 53.8 MW

For the second case when the resistance, R = 9 Ω and current, I = I,

The power wasted is calculated as;

P = I² x 9

P = 9I²

For 400 kV, the current, I = (400,000 V) / 9 Ω

I = 44,444.44 A

P = 9 x (44,444.44)²

P = 1.78 x 10¹⁰ W

P = 17,800 x 10⁶ W

P = 17,800 MW

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At the height 2650 km, the value of acceleration due to gravity is 50% of its value at the surface.

The new value of gravity at a height h is given as g' = g R²/(R+h)²

As visible from the formula, increasing h results in decreasing gravity.

So, just put g′ = g/2 i.e. 50% less than g where g is gravity at surface. So, we get,

g/2 = g R²/(R+h)²

1/2 = R²/(R+h)²

2/1 = (R+h)²/R²

√2 = (R+h)/R = 1 + h/R

h/R = √2 - 1 = 0.414

h = 0.414 R

As we know radius of the earth = 6400 km, putting it in the above equation,

h = 0.414 R = 0.414(6400) = 2649.6 km

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The resultant force is approximately 11.75 N

If five equal forces of 10 N are applied at a point, and the angle between them is equal, then the forces can be considered as forming a regular pentagon.

The angle between any two adjacent forces in a regular pentagon:

180 - 360 degrees

            n

where,

n = the number of sides.

In this case, the angle is

180 - 360

           5

θ = 108 degrees.

To calculate the resultant force, we can use vector addition. Since the forces are equal and the angle between them is 108 degrees, we can use the law of cosines to find the magnitude of the resultant force. The law of cosines states that the square of the magnitude of the resultant force (R) is equal to the sum of the squares of the individual forces (F) plus twice the product of the individual forces and the cosine of the angle between them (θ).

R² = F² + F² + 2 * (F) *(F)* cos(108)

R² = 10² + 10² + 2(10)(10)cos(108)

R² = 100 + 100 + 200 * (cos(108))

R² = 100 + 100 + 200 * (-0.309016994)

R = ([tex]\sqrt({100 +100 - 62)}[/tex]

R = √138

R = 11.75 N

The magnitude of the resultant force is approximately 11.75 N, which is the force that would be required to replace all five forces.

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The net force that acts on the object is 36.5 N.

We have to note that the first thing that we would have to obtain is the acceleration of the object and we can be able to obtain this by the use of the formula;

v ^2 = u^2 + 2as

v = final velocity

u = initial velocity

a = acceleration

s = distance

(0.75)^2 = (0)^2 + 2 * a * 5.5

a = (0.75)^2 / 2 * 5.5

a = 0.5625/11

a = 0.05 m/s^2

The net force is ma

F = 730 kg * 0.05 m/s^2

F = 36.5 N

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The building block of all elements and the smallest component into which an element can be divided d. atom

Quarks, the universe's tiniest particles, are significantly smaller and have far greater energy levels than the protons and neutrons in which they are found.

An atom is the smallest unit of an element that retains all of its characteristics.

However, atoms include several subatomic particles, the most significant of which are protons, neutrons, and electrons.

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Correct Question:

what is the gauge pressure profile of the water against a section of the container?

Gauge pressure is the pressure in relation to atmospheric pressure. For pressures greater than atmospheric pressure, gauge pressure is positive. For pressures lower than atmospheric pressure, gauge pressure is negative.

Pg stands for gauge pressure, which has the following relationships with absolute pressure: pg is equal to p - pa, where Pa is the local atmospheric pressure. Example: The tyre pressure, as determined by a vehicle tyre gauge, is 32.0 psi. The local atmosphere has a pressure of 14.2 psi.

There is pressure between two items that are in touch. The pressure profile is the distribution of pressure throughout the whole contact area.

Since the majority of gauges measure pressure in relation to atmospheric pressure, which acts as the zero point, this form of reading is simply referred to as "gauge pressure." But anything that is not a total vacuum is seen as being under pressure of some kind.

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The density of silicon is [tex]2.33 * 10^{-9} kg.m^{3}[/tex]

Given density of silicon  is 2.33 gram centimeter cube.

We know that:

                            100 cm = 1 m

                            1cm = 1/100m = [tex]10^{-2} m[/tex]

                            [tex]1 cm^{3} = 10^{-6} m^{3}[/tex]

Also,

        1000 gram = 1 kg

        1 gram = 1/1000 kg = [tex]10^{-3} kg[/tex]

Now, to convert gram centimeter cube into kilogram meter cube we should multiply by these values.

So, By putting these values we get:

Density = 2.33 * [tex]10^{-3} kg * 10^{-6} m^{3} = 2.33 * 10^{-9}kg. m^{3}[/tex]

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The cost of making toast 16 times per month at a rate of 9.0 cents/kWh is approximately $0.1 per month.

How does the energy consumption of a device change with the length of usage?

The strength consumption of a tool commonly will increase with the duration of utilization. This is due to the fact maximum devices devour electricity continuously at the same time as in use, no matter how long they're used for. Some gadgets, along with appliances with standby or sleep modes, may devour less strength while now not in use, but will eat extra strength the longer they're used. For example, a fridge will consume extra power over a month than it will over an afternoon, and a pc will devour more energy over a 12 months than it's going to over a month.

A few gadgets, consisting of incandescent light bulbs, will eat extra energy and put on out faster the greater they may be used.

We convert from Watt to kilowatt

650/1000 = 0.65KW

We convert from minutes to hour:

6/60= 0.1 hr

Convert cents to dollars

9/100 = $0.09

Energy cost in KWh= 0.65 × 0.1 × 0.09 ×16= $ 0.1 per month

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The distance between the two parallel plates can be found using the equation E = V/d where E is the electric field, V is the potential difference and d is the distance between the plates. Thus, d = V/E = 125V / 4.25 x 103N/C = 29.41cm

The relationship between electric field, potential difference and distance in parallel plates is inversely proportional. As the potential difference increases, the electric field between the plates increases and the distance between the plates decreases. And as the distance between the plates increases, the electric field between the plates decreases and the potential difference applied to the plates decreases.

It can be mathematically represented by the formula E = V / d, where E is the electric field, V is the potential difference, and d is the distance between the plates.

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The distance between the two parallel plates can be found using the equation E = V/d  , 29.41cm far apart are the plates .

                             E = V/d

where E is the electric field,

V is the potential difference and

d is the distance between the plates.

                          Thus, d = V/E

                          = 125V / 4.25 x 103N/C

                                    = 29.41cm

The relationship between electric field, potential difference and distance in parallel plates is inversely proportional. As the potential difference increases, the electric field between the plates increases and the distance between the plates decreases. And as the distance between the plates increases, the electric field between the plates decreases and the potential difference applied to the plates decreases.

It can be mathematically represented by the formula E = V / d, where E is the electric field, V is the potential difference, and d is the distance between the plates.

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The greatest distance away from the initial position that an object can be if it struck by the airplane is 12.5 ft, if the initial speed of the airplane is 10 ft/s.

Initial speed of the paper airplane, u = 10 ft/s

Final speed of the paper airplane, v = 0

deceleration of the airplane, a = -4 ft/s²

By the first equation of motion, v = u -at

Time of flight, t = (v-u)/a

t = (0 - 10)/-4 = 2.5 sec

Maximum distance travelled by the airplane, = S

S = ut + 0.5at²

S = 10 × 2.5 - 0.5 × 4 × 2.5²

S = 12.5 ft

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After a brief period of falling, the upward air friction on the cargo would equal the downward gravity pull if a parachute opened.

Air resistance reaches its maximum magnitude at the falling object's terminal velocity. Due to the fact that the two forces are acting in opposing directions, there is no net force acting on the item, and its speed has stabilised.

In addition, gravity is pulling the thing downward as it falls. Gravity is an imbalanced force at the beginning of a descent. The result is an increase in speed or acceleration for the object. Aerodynamic drag or air resistance is encountered as it accelerates.

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The driver gear is the gear that provides the input motion to the gear train, while the driven gear is the gear that receives motion from the other gears in the train and provides the output motion.

This refers to the main or primary gear that majorly drives the other gears found in the gear train.The driver gear is typically connected to a power source, such as an electric motor or a combustion engine, while the driven gear is connected to the load that the gear train is intended to drive. The driver gear is also the one that has the greater torque and the one that rotates faster.

Driven gears refer to the gear that receives motion from the other gears in the train and provides the output motion.

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Celestial navigation is the best method of naming or locating stars, if we have to give someone the location of a star.

With the help of "sights" or time angular measurements taken typically between a celestial body (e.g. the Sun, a planet, the moon or a star) and the visible horizon, Celestial navigation locate a star or any celestial body. However it can also take advantage of measurements between celestial bodies without taking the Earth horizon as reference, such as when the Moon is used in the practice, then it is called "lunars" or lunar distance method, which is used for determining precise time when time is unknown.

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The least speed is required to cover the rest of the trip to arrive in time for the interview is [tex]114.05km/hr[/tex]

Distance and displacement are two quantities that seem to mean the same but are distinctly different with different meanings and definitions. Distance is the measure of “how much ground an object has covered during its motion” while displacement refers to the measure of “how far out of place is an object.”

Here distance formula is,

Δ[tex]d=d_{1} +d_{2}[/tex]

Here we need to find the time left and the distance covered:

T[tex]1[/tex] [tex]=\frac{100}{100}=1hr=60 min[/tex]

T[tex]2[/tex] [tex]=\frac{43}{41} =1.04hr=62.92 min[/tex]

Total time was [tex]3.25hr[/tex][tex]=195min[/tex]

So, Time left is: [tex]1.21hr =72.08min[/tex]

Total distance left to cover is:

D[tex]=280-100-43=137[/tex][tex]km[/tex]

Now minimum speed required is:

[tex]s=\frac{distance}{time} =\frac{137}{1.21} =114.05km/hr[/tex]

Therefore, the least speed is required to cover the rest of the trip to arrive in time for the interview is [tex]114.05 km/hr[/tex].

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Complete question: you are to drive to an interview in another town, at a distance of 280km on a expressway. The interview is at 11:15 a.m. you plan to drive at 100km/h, but then construction work forces you to slow to 41.0km/h for 43.0km what would be the least speed needed for the rest of the trip to arrive in time for the interview?

The amount of the potential energy that was converted into thermal energy  is determined as 440,000 J.

The amount of the potential energy that was converted into thermal energy  is calculated by applying the principle of conservation of energy as follows;

P.E - K.E = Eth

where;

( 2,000 kg x 9.8 m/s² x 150 m ) - ¹/₂ (2,000 kg )( 50 m/s )² = Eth

2,940,000 J - 2,500,000 J = Eth

440,000 J = Eth

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In this case, the acceleration amplitude would be (0.23 ips x 1170 cpm)2 = 546.7 g.

Acceleration is the rate of change of velocity over time. It is a vector quantity, meaning that it has both magnitude and direction. The magnitude of acceleration is the rate at which the velocity changes, and the direction of acceleration is the same as the direction of the velocity.

Displacement amplitude:
The formula for displacement amplitude is displacement amplitude = velocity amplitude / (2πf).
In this case, the displacement amplitude would be 0.23 ips / (2π x 1170 cpm) = 0.00196 inches pk-pk. Converting to mils pk-pk, this would be 1.96 mils pk-pk.
Acceleration amplitude:

The formula for acceleration amplitude is acceleration amplitude = (velocity amplitude x f)2.
In this case, the acceleration amplitude would be (0.23 ips x 1170 cpm)2 = 546.7 g.

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Option E -  it remains the same , if a simple pendulum oscillates with small amplitude and its length is doubled .

The greatest displacement or distance that a point on a wave or vibrating body may travel in relation to its equilibrium position

A wave's amplitude is the difference between its starting position and its maximum displacement. Frequency is the amount of waves which pass past the certain place each second. Period is the length of time it takes for a wave cycle to finish.

    Given,length of a simple pendulum  is doubled .

To find, frequency of motion.

we have Time period T before doubling the length,

T = 2π[tex]\sqrt{\frac{L}{g} }[/tex]   L- length,g-acceleration due to gravity

T/2π = [tex]\sqrt{\frac{L}{g} }[/tex]  

g = L(2π/T[tex])^{2}[/tex]   → 1

when length is doubled,Time period [tex]T^{'}[/tex]

[tex]T^{'}[/tex] = 2π [tex]\sqrt{\frac{2L}{g} }[/tex]

( [tex]T^{'}[/tex] /2π[tex])^{2}[/tex] = [tex]\frac{2L}{g}[/tex]

g=2L( 2π/T[tex])^{2}[/tex] → 2

from equation 1 and 2

L( 2π/T[tex])^{2}[/tex] = 2L( 2π/T[tex])^{2}[/tex]

2π/T=[tex]\sqrt{2}[/tex](2π/T)

1/T  =[tex]\sqrt{2}[/tex](1/T)

we know,frequency γ = 1/T

γ  =[tex]\sqrt{2}[/tex]  γ '

γ ' =[tex]\frac{1}{\sqrt{2} }[/tex]  γ

Therefore option E is correct.

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The volume of object will be equal to the volume of water displaced so the object's volume is also 17.04 dm⁻³.

In water, the object appears lighter than in air.

That is,

936 - 769 = 167N.

Water provided the167N buoyant force.

The buoyant force on an object in water is equal to the weight of water displaced by the object. The buoyant force acting on the metal object in this case is 167N. The object must have displaced the same weight of water.

Given g = 9.8m/s²

Water displacement mass:

Mass = weight /g

         = 167/9.8

.         = 17.04 kg

Water displacement volume:

At room temperature, the density of water is 1.000 kg.dm⁻³. Each kilogram of water has a volume of 1 dm³ (one cubic decimeter), which is equal to 1 L. (one liter).

V = Mass / Density

= m/ρ

= 17.04/1.000 kg.dm⁻³

= 17.04dm⁻³

The object is completely submerged. As a result, the object's volume will remain constant. The object is completely submerged. As a result, the object's volume will be equal to the volume of water displaced. The object's volume is also 17.04 dm⁻³.

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When this problem is solved, we will arrive at the value 72741 to 4 meters per second.

An object's total, directionless motion is measured in terms of distance. Distance may also be referred to as the amount of ground covered by an element, depending on the starting or finishing point.

By calculating its distance, we can determine an object's actual size. One can measure the space that an object takes up above us. Its true size can be determined after we know how far away it is. As you get further away, something gets smaller.

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The distance that the support must be from point A . 1.2010 3 N.

At x = 0, where the x axis is parallel to the diving board, we assume the force acting on the left pedestal to be F1. We define the right pedestal's force as F2 and its location as x=d. W is the diver's weight, which is found at x=L. Setting the total of forces (with upward positive) and the sum of torques (around x2) to zero yields the following two equations:

F 1 +F 2 −W=0

F 1 d+W(L−d)=0

(a) The result of the second equation is F 1 = d L d W = (2.5m 3.0m)

(600N) = 800N, which should be rounded to F 1 = 1.210 3 N. Consequently, F 1 = 1.2010 3 N

(b) F 1 is negative, suggesting a downward force.

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The upper fixed point, also known as steam point, is the temperature at which pure water boils at normal atmospheric pressure.

In case of the Celsius scale, the upper fixed point is 100°C.

This is the boiling point of pure water at 1atm which is the normal atmospheric pressure.

The pressure that the atmosphere exerts on the earth's surface is called atmospheric pressure.

The temperature at which liquid water starts changing into vapour is called boiling point.

Celcius is an unit of measuring temperature.

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If the work required to speed a car up from 10km/h to 20km/h is 5.0 x 10^3 J, the work required to increase the cars speed from 20km/h to 30km/h is: 8.33 × 10³J.

Using this formula to determine the   work required to increase the cars speed from 20km/h to 30km/h

[tex]Wii = Wi (V^2_2- V^2_1) /v^2_2 - v^2_1[/tex]

Let plug in the formula

Work required = (5 × 10³) (30² -20²) / (20² -10²)

Work required = (5 × 10³)  ( 900 - 400) /(400  - 100)

Work required = (5 × 10³) ( 500) / 300

Work required = 8.33 × 10³J

Therefore the Work required is 8.33 × 10³J.

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Part a: Velocity with no friction: v = 6.41 m/s.

Part b:  velocity of the moving object when it reached at the bottom is found as  5.29 m/s.

Potential energy P.E

P.E =  mgh

P.E = 38 x 9.8 x 2.1   J

This all transforms to kinetic energy just at bottom = 0.5 mv² if there is no energy loss.

So,

0.5 x 38 x v² = 38 x 9.8 x 2.1,

v = 6.41 m/s

Part b: If friction results in a loss of energy of 250 J

0.5 x 38 x v² = 38 x 9.8 x 2.1 - 250

v² = 532.04/ (0.5 x 38)

v = 5.29 m/s

Thus, the velocity of the moving object when it reached at the bottom is found as  5.29 m/s.

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The correct question is-

2. A 38kg child is at the top of a slide that is 2. 1m tall.

(a) If there is no friction, how fast will they be moving when they reach the bottom of the slide?

(b) If they lose 250. 0J of energy to sound, heat, and friction, how fast will they be moving when they reach the bottom?

The required acceleration has a magnitude of 19.7 m/s2  directed upwards, correct to three significant figures.

The the purpose of analysis, the motion of rocket is divided into two phases.

Phase 1: the free fall motion of the rocket from the height 2.98*102m to a height 96.5m.

Phase 2: the motion of the rocket due to the acceleration of the rocket also from the height 96.5 m to the point of touchdown y = 0m.

The initial velocity of the rocket is 0m/s when it started to experience a fall from rest under free fall. g = 9.8m/s² t1 is the time taken for phase 1 and t2 is the time taken for phase2.

The final velocity under free fall becomes the initial velocity for the accelerated motion of the rocket in phase 2 and the final velocity or speed in phase 2 is equal to zero.

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In order to calculate time, we need to know one more variable, the gravitational acceleration of earth which is 9.8 m/s^2 and the force exerted on the player's legs, which can be calculated by F=ma.

In order to determine how long the player will remain in the air, we would need to know the player's upward acceleration (which can be affected by factors such as the player's mass and the force exerted on the player's legs as they jump) as well as the player's initial upward velocity. Without this information, it is not possible to calculate how long the player will remain in the air.

In physics, an object's vertical motion can be described by the equation:

y = vi*t + (1/2)at^2

where y is the vertical displacement (or height) of the object, vi is the initial upward velocity, t is the time in the air, and a is the upward acceleration.

If we know the initial upward velocity (vi) and the acceleration (a), we can use this equation to solve for the time in the air (t). The acceleration of the object is determined by various factors such as the force applied on the object and the mass of the object.

In this case, we know the initial upward velocity of the basketball player is 3.53 m/s, but we don't have the acceleration value, which means we cannot solve for time. In order to calculate time, we need to know one more variable, the gravitational acceleration of earth which is 9.8 m/s^2 and the force exerted on the player's legs, which can be calculated by F=ma.

Therefore, without additional information, it is not possible to calculate the time the player will remain in the air.

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0.034 second is the main time period of the motion for a machine which is operating at a speed of 1780 cpm.

Time period of an object is the time required for it to complete its one cycle or oscillation. Angular frequency is angular displacement of any object of the waves per unit time. The formula for time is, T = 1/f

where T is time-period and f is frequency.

Operating speed of the machine = 1780 cpm (cycle per minute)

Cycle in one minute = 1780

Cycle in 1 second = 1780/60 = 29.67 cycles

Time required in one cylcle, T = 1/29.67 = 0.034 second

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