A rectangle has a height of 5 and a width of 4x^2-2x-6.Express the area of the entire rectangle. Expression should be expanded.​

Answer:-0.560

Step-by-step explanation:

Answer:

(x/2,(y/2)

Step-by-step explanation:

(16/2,24/2)

(8,12)

Answer:

11/132 = 1/12

Step-by-step explanation:

just put the rise over the run and simplify

Answer:sorry this probably is t the most helpful but the closest i could get was 399 lbs. it’s is st$497.7 for one and $$497.8.

Step-by-step explanation:

Answer:

The goal in solving an equation is to get the variable by itself on one side of the equation and a number on the other side of the equation. To isolate the variable, we must reverse the operations acting on the variable.

Step-by-step explanation:

The objective or equation would be to acquire the variables independently. A further explanation is provided below.

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Answer:

80

Step-by-step explanation:

use the formula of arithmetic progression

Answer:

[tex]\frac{3}{5}[/tex] or 0.6

Step-by-step explanation:

This problem requires the slop formula which is [tex]\frac{y2-y1}{x2-x1}[/tex]

You start with the first point which is (-1,1). This will be x1 and y1.

The next point is (4,4). This will be x2 and y2.

You plug these values into your equation which gives you [tex]\frac{4-1}{4-(-1)}[/tex]

To solve, you evaluate, [tex]\frac{4-1}{4-(-1)}[/tex]  = [tex]\frac{3}{5}[/tex] or 0.6

When y=20 , x is −5.

Answer:

Depends on the formula given

Answer:

-0.21428571428

Answer:

I am going with B.1,3,9,27

Step-by-step explanation:

A,C and D the patterns are from addition ie. A +8, C+3 and D +1 but B it's ×3

Answer:

The correct answer is -3

Step-by-step explanation:

attached is a number line to show diagrammatically how to count five units from the chosen point to point 2 on a number line.

Moving five units from -3 to 2 on a number line is given as follows:

-3 ⇒ -2 ⇒ -1 ⇒ 0 ⇒ 1 ⇒ 2

From the motion expression shown above, moving from -3 to 2 involves moving 5 units.

another way of determining the correct answer is to find the difference in interval between the two points as shown below:

Let the point be x

2 - x = 5 units

2 - 5 = x

∴ x = -3

Answer:

-3

Step-by-step explanation:

it was on quiz baby

Answer:

-2

Step-by-step explanation:

Y = mx+c

M here being the number in front of x

Answer:

a- just took the test

Step-by-step explanation:

Answer:

grew by 6

Step-by-step explanation:

Answer:

the answer is A) X=m/n-p

Step-by-step explanation:

m/x=n-p

n-p=m/X

(n-p)×x=m

X=m/n-p

Answer:

A but im not sure

Step-by-step explanation:

Answer:

56

Step-by-step explanation:

Multiply it out 2×2×2×7 = 56

Answer:

Hector purchased 5 black sweatshirts at $40, and 5 yellow short sleeve shirts at $25. He spent $65 in total.

Rachel purchased 5 red long sleeves shirts at $30.

Mercedes purchased 5 green short sleeve shirts at $25 and 5 long sleeve shirts at $30. She spent $55 in total.

Quinn purchased 10 navy sweatshirts and spent $80 in total.

Answer:

-24

Step-by-step explanation:

If you are struggling with this here's a tip!

-18+-6 is what you are trying to solve

The 6 is negative, so get rid of the plus sign -18-6

2 negative numbers are just added like positive numbers

So add 18 and 6, you should get 24

Don't forget about the negative!

-24

Answer:

p(x) = 0.6x³ - 200x² + 500x- 300

Step-by-step explanation:

Given the cost function and revenue function as:

C(x) = 500x² + 100x

R(x) = -0.6x³ + 700x² – 400x + 300

To get the profit function:

p(x) = C(x) - R(x)

p(x) = 500x² + 100x -(-0.6x³ + 700x² – 400x + 300)

open the parenthesis

p(x) = 500x² + 100x + 0.6x³ - 700x² + 400x - 300

p(x) = + 0.6x³+500x² - 700x² + 100x+ 400x- 300

p(x) = 0.6x³ - 200x² + 500x- 300

Hence the profit function is expressed as p(x) = 0.6x³ - 200x² + 500x- 300

Answer:

1) if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.

2) a standard deviation of 6.0843 results in a 1.07% replacement rate

3) using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit

Step-by-step explanation:

based on the given data;

x will represent the random variable such that the lifetime of its auto batteries, is normally distributed with a mean of 45 months and a standard deviation of 5.6 months

so

x → N( U = 45, ∝ = 5.6)

Under the warranty, if a battery fails within 31 months of purchase, the manufacturer replaces the battery at no charges to the consumer.

if the battery fails after 31 months but within 54 months, the manufacturer provides a prostrated credit towards the purchase of anew battery

1) If the manufacturer's assumptions are correct,

p(x < 3) = p( [x-u / ∝ ] < [ 31-45 / 5.6] )

= p( z < -2.5 )

using the standard normal table,

value of z = 0.0062 ≈ 0.62%

so if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.

2)

The company finds that it is replacing 1.07% of its batteries free of charge. It suspects that its assumption standard deviation of the life of its batteries is incorrect, so a standard deviation of ? results in a 1.07%

so lets say;

p ( x < 31 ) = ( 1.07%) = 0.0107

p ( [x-u / ∝ ] < [ 31-45 / ∝] ) = 0.0107

now from the standard table

-2.301 is 1.07%

so

( 31 - 45 / ∝ ) = -2.301

-14 / ∝ = -2.301

∝ = -14 / - 2.301

∝ = 6.0843

therefore a standard deviation of 6.0843 results in a 1.07% replacement rate

3)

Using the revised standard deviation for battery life, what percentage of the manufacturer's batteries don't free replacement but do qualify for the prorated credit?

p( 31 < x < 54 ) = p ( [31 - u / ∝ ] < [ x-u / ∝]  < [ 54 - 45 / ∝] )

= p ( [31 - 45 / 6.0843 ] < [ x-u / ∝]  < [ 54 - 45 / 6.0843] )

= p ( -2.301 < z < 1.4792 )

= p(Z < 1.5) - p(Z < -2.3)

= 0.9393 - 0.0108

= 0.919 ≈ 91.9%

therefore using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit

Step-by-step explanation:

Find the table attached

a) Given

F(x) = 6/x-2

When x = -4

F(-4) = 6/-4-2

F(-4) = 6/-6

F(-4) = -1

F(x) = 6/x-2

When x = -3

F(-3) = 6/-3-2

F(-3) = 6/-5

F(-3) = -1.2

F(x) = 6/x-2

When x = -2

F(-2) = 6/-2-2

F(-2) = 6/-4

F(-2) = -1.5

F(x) = 6/x-2

When x = -1

F(-1) = 6/-1-2

F(-1) = 6/-3

F(-1) = -2.0

F(x) = 6/x-2

When x = 0

F(0) = 6/0-2

F(0) = 6/-2

F(0) = -3

F(x) = 6/x-2

When x = 1

F(1) = 6/1-2

F(1) = 6/-1

F(1) = -6

F(x) = 6/x-2

When x = 2

F(2) = 6/2-2

F(2) = 6/0

F(2) = infty

F(x) = 6/x-2

When x = 3

F(3) = 6/3-2

F(3) = 6/1

F(3) = 6

F(x) = 6/x-2

When x = 4

F(4) = 6/4-2

F(4) = 6/2

F(4) = 3

b) Given

r(x)=6x+12/x^-4

When x = -4

r(-4) = 6(-4)+12/(-4)^-4

r(-4) = -24+12/(1/256)

r(-4) = -12(256)

r(-4) = -3072

When x = -3

r(-3) = 6(-3)+12/(-3)^-4

r(-3) = -18+12/(1/81)

r(-3) = -6(81)

r(-3) = -486

When x = -2

r(-2) = 6(-2)+12/(-2)^-4

r(-2) = -12+12/(1/16)

r(-2) = -0(16)

r(-2) = 0

When x = -1

r(-1) = 6(-1)+12/(-1)^-4

r(-1) = -6+12/(1)

r(-1) = -6+12

r(-1) = 6

When x = 0

r(0) = 6(0)+12/(0)^-4

r(0) = 0+12/0

r(0) = 12/0

r(0) = infty

When x = 1

r(1) = 6(1)+12/(1)^-4

r(1) = 6+12/1

r(1) = 18(1)

r(1) = 18

When x = 2

r(2) = 6(2)+12/(2)^-4

r(2) = 12+12/1/16

r(2) = 24(16)

r(2) = 384

When x = 3

r(3) = 6(3)+12/(3)^-4

r(3) = 18+12/1/81

r(3) = 30(81)

r(3) = 2430

When x = 4

r(4) = 6(4)+12/(4)^-4

r(4) = 24+12/1/256

r(4) = 36(256)

r(4) = 9216

We want to construct tables of values for the two given functions.

The tables are:

a)

[tex]\left[\begin{array}{ccc}x&y\\-4&-7/2\\-3&-4\\-2&-5\\-1&-8\\0&NaN\\1&4\\2&1\\3&0\\4&-1/2\end{array}\right][/tex]

b)

[tex]\left[\begin{array}{ccc}x&y\\-4&3,048\\-3&954\\-2&180\\-1&6\\0&0\\1&18\\2&204\\3&990\\4&3,096\end{array}\right][/tex]

A table will be something like:

[tex]\left[\begin{array}{ccc}x&y\\-4&\\-3&\\-2&\\-1&\\0&\\1&\\2&\\3&\\4&\end{array}\right][/tex]

Where the values of x go from -4 to 4.

To complete the tables, we just need to evaluate the functions in each one of the x-values at the left, and the outcome will be placed at the right.

a) f(x) = 6/x - 2

Now we just need to evaluate the function in all the given points:

f(-4) = 6/(-4) - 2 =  -3/2 - 4/2 = -7/2

f(-3) = 6/-3 - 2 = -4

f(-2) = 6/-2 - 2 = -5

f(-1) = 6/-1 - 2 = -8

f(0) is undefined, as we can't divide by zero, here we can write NaN (Not a number).

f(1) = 6/1 - 2 = 4

f(2) = 6/2 - 2 = 1

f(3) = 6/3 - 2 = 0

f(4) = 6/4 - 2 = -1/2

Now we put all of these in the correspondent place of the table:

[tex]\left[\begin{array}{ccc}x&y\\-4&-7/2\\-3&-4\\-2&-5\\-1&-8\\0&NaN\\1&4\\2&1\\3&0\\4&-1/2\end{array}\right][/tex]

b) We do the same thing, here we have:

r(x) = 6*x + 12/x^-4 = 6*x + 12*x^4

Now we evaluate this in the given values:

r(-4) = 6*(-4) + 12*(-4)^4 = 3,048

r(3) = 6*(-3) + 12*(-3)^4 = 954

r(-2) = 6*(-2) + 12*(-2)^4 = 180

r(-1) = 6*(-1) + 12*(-1)^4 = 6

r(0) = 6*0 + 120^4 = 0

r(1) = 6*1 + 12*1^4 = 18

r(2) = 6*2 + 12*2^4 = 204

r(3) = 6*3 + 12*3^4 = 990

r(4) = 6*4 + 12*4^4 = 3,096

Now we place these values in the correspondent place on the table:

[tex]\left[\begin{array}{ccc}x&y\\-4&3,048\\-3&954\\-2&180\\-1&6\\0&0\\1&18\\2&204\\3&990\\4&3,096\end{array}\right][/tex]

These are our two tables.

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Answer:

The additional wells for maximum amount of oil per day is 3 wells.

Step-by-step explanation:

Given;

initial number of wells, n = 6

total production, T = 1800

average production per well, = 1800/6 = 300 barrels per day

Let the additional well = y

total number of wells after optimization = 6 + y

new production per well = 300 - 25y

new total production = (6+y)(300-25y)

t = 1800 - 150y + 300y - 25y²

t = 1800 + 150y - 25y²

dt / dy = 150 -50y

for maximum value, dt/dy = 0

150 - 50y = 0

50y = 150

y = 150 / 50

y = 3

Therefore, the additional wells for maximum amount of oil per day is 3 wells.

33 additional wells should be drilled, reaching 39 wells, to obtain the maximum amount of oil per day.

Given that an oilfield contains 6 wells that produce a total of 1,800 barrels of oil per day, and for each additional well that is drilled, the average production per well decreases by 25 barrels per day, to determine how many additional wells should be drilled to to obtain the maximum amount of oil per day, the following calculation must be performed:

Therefore, 33 additional wells should be drilled, reaching 39 wells, to obtain the maximum amount of oil per day.

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x = 33°

Then :-

m∠1 = 33° ( angle x and angle 1 are corresponding angles on a transversal )

m∠1 + m∠2 = 90° ( angle 1 and angle 2 are complementary angles )

33 + ∠2 = 90

∠2 = 90 - 33

m∠2 = 57°

m∠1 + m∠3 = 180° ( angle 1 and angle 3 are a linear pair )

33 + ∠3 = 180°

∠3 = 180 - 32

m∠3 = 147°

Answer:

0.45576

Step-by-step explanation:

z = (x-μ)/σ, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

Standard Deviation = √variance

Mean = 50

= √9

= 3

z = 51 - 50/3

= 0.11111

Probability value from Z-Table:

P(x<51) = 0.54424

P(x>51) = 1 - P(x<51)

= 1 - 0.54424

= 0.45576

The probability that the dealer will sell 51 or more cars is 0.45576

Answer:

2c^2

Step-by-step explanation:

c3-c1=c2

d2-d2=0

8/4=2

Answer:

Step-by-step explanation: