A local hamburger shop sold a combined total of 591 hamburgers and cheeseburgers on Tuesday. There were 59 fewer cheeseburgers sold than hamburgers

On tuesday how much did they sell

Answers

Answer 1

Answer:

On Tuesday

591 burgers are sold.

Some are hamburgers and some are cheeseburgers.

59 fewer cheeseburgers sold than hamburgers.

Number of cheeseburgers --> x

Number of hamburgers --> y

x+y= 591 --> x = 591-y

x = y-59

so

591-y = y-59

-2y = -650

y = 325

so

x = 325-59

x =266

Answer 2

The hamburger shop sold a combined total of 591 hamburgers and cheeseburgers on Tuesday.

Let's represent the number of hamburgers sold as "H" and the number of cheeseburgers sold as "C." From the information given, we have two equations:

1. H + C = 591 (The combined total of hamburgers and cheeseburgers sold on Tuesday was 591).

2. C = H - 59 (There were 59 fewer cheeseburgers sold than hamburgers).

Now, we can use substitution to solve for the number of hamburgers: Substitute the value of C from the second equation into the first equation:

H + (H - 59) = 591

Now, combine like terms:

2H - 59 = 591

Next, isolate the term with H:

2H = 591 + 59

2H = 650

Now, solve for H:

H = 650 / 2

H = 325

So, they sold 325 hamburgers on Tuesday. To find the number of cheeseburgers sold, use the second equation:

C = H - 59

C = 325 - 59

C = 266

They sold 266 cheeseburgers on Tuesday. To find the total sales, add the number of hamburgers and cheeseburgers: Total sales = 325 (hamburgers) + 266 (cheeseburgers) = 591.

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Answers

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To learn more on Speed click:

https://brainly.com/question/28224010

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