A lead fishing weight of mass 0.20 kg is tied to a fishing line that is 0.50 m long. The weight is then whirled in a vertical circle. The finishing line will break if its tension exceeds 100.0 N. (a) If the weight is whirled at higher and higher speeds, at what point in the vertical circle will the string break (top, bottom, or random position)

Answers

Answer 1

Answer:

Following are the solution to this question

Explanation:

please find the complete question in the attached file.

In point a:

The answer is "bottom".

In point b:

Using formula:

[tex]T= mg + \frac{m V^2}{2}[/tex]

[tex]\to 100= 0.2 \times 9.81 + \frac{0.2 \times V^2}{0.5}[/tex]

[tex]\to 100= 1.962+ \frac{0.2 + V^2}{0.5}\\\\\to 100- 1.962= \frac{0.2 + V^2}{0.5}\\\\\to 98.038= \frac{0.2 + V^2}{0.5}\\\\\to 49.019=0.2+V^2\\\\\to 48.819=V^2\\\\ \to 6.987 \ \frac{m}{s}[/tex]

A Lead Fishing Weight Of Mass 0.20 Kg Is Tied To A Fishing Line That Is 0.50 M Long. The Weight Is Then

Related Questions

If you push a heavy box at rest, you must exert some force before it begins to move. Once its moving, you don’t have to as much force. Which of Newton’s three laws explains this?

Answers

Answer:

momentum does

Explanation:

Calculate the velocity of an object moved around a circle with a radius of 1.65 m and an
acceleration of 3.5 m/s2.

Answers

Answer:

2.4m

Explanation:

Given parameters:

Radius of circle  = 1.65m

Acceleration  = 3.5m/s²

Unknown:

Velocity of the object = ?

Solution:

To solve this problem, we have to apply the formula of centripetal acceleration;

   Centripetal acceleration  = [tex]\frac{v^{2} }{r}[/tex]  

v is the velocity

r is the radius

   v² = centripetal acceleration x radius

 Insert parameters and solve;

     v² = 3.5 x 1.65

     v  = √5.775  = 2.4m

The velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.

Given the data in the question;

Radius; [tex]r = 1.65m[/tex]Centripetal acceleration; [tex]a_c = 3.5m/s^2[/tex]

Velocity; [tex]v = \ ?[/tex]

From the centripetal force equation, we use the expression for centripetal acceleration:

[tex]a_c = \frac{v^2}{r}[/tex]

Where [tex]a_c[/tex] is the centripetal acceleration, v is the velocity and r is radius.

We substitute our given values into the equation

[tex]3.5m/s^2 = \frac{v^2}{1.65m} \\\\v^2 = 3.5m/s^2\ *\ 1.65m\\\\v^2 = 5.775m^2/s^2\\\\v = \sqrt{5.775m^2/s^2} \\\\v = 2.4m/s[/tex]

Therefore, the velocity of the object as it moves around a circle with the given radius and acceleration is 2.4m/s.

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yes or no
1.the ink of a pen that is used for writing is not a colloid
2.the blood consists of solid particles and plasma are considered a kind of colloid.​

Answers

Answer:

1. No, it is a colloid

2. Yes

Explanation:

How do covalentes bonds form

Answers

A covalent bond forms when two or more valence electrons are attracted by the positively charged nuclei of two atoms and thus are shared between both atoms.

The first group of planets that are made of rock and closest to the sun

Answers

Answer:

A terrestrial planet, telluric planet, or rocky planet is a planet that is composed primarily of silicate rocks or metals. Within the Solar System, the terrestrial planets are the inner planets closest to the Sun

Explain how you would determine how much air there is between a vector addition in the displacement of the actual trip taken. Why aren’t vectors true straight-line paths in the real world? Would you expect a vector addition to be larger or smaller than the actual trip taken? Why?

Answers

Answer:

This is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. This enables more atoms in the metal to become aligned hence becoming more magnetized.

or...

A method of procedure that has characterized natural science since the 17th century, consisting in systematic observation, measurement, and experiment, and the formulation, testing, and modification of hypotheses.

Hope this helps☺️

How long will it take a 2190 W motor to lift a 1.47 x 104 g box, 6.34 x 104 mm vertically.​

Answers

Answer:

4.2s

Explanation:

Given parameters:

Power = 2190W

Mass of box = 1.47 x 10⁴g

distance  = 6.34 x 10⁴mm

Unknown:

Time  = ?

Solution:

Power is the rate at which work is done;

 Mathematically;

        Power  = [tex]\frac{work done}{time}[/tex]  

   Time  = [tex]\frac{work done}{power}[/tex]  

 Work done  = weight x height

 convert mass to kg;

     100g = 1kg;

           1.47 x 10⁴g  = 14.7kg

convert the height to m;

          1000mm = 1m

          6.34 x 10⁴mm gives 63.4m

  Work done  = 14.7 x 9.8 x 63.4 = 9133.4J

  Time taken = [tex]\frac{9133.4}{2190}[/tex]   = 4.2s

carter found the rock shown in the picture below near a river ​

Answers

Answer:

there's no picture

Explanation:

and what would the question be anyways?

Answer:

what is the question

Explanation:

Which sequence shows electromagnetic waves arranged in a decreasing order of their wavelengths?

Answers

Answer: Gamma rays, x-rays, ultraviolet rays, visible light, and infrared rays.

Answer:

C) radio → infrared → ultraviolet → gamma

Explanation:

It Increases left to right therefore it decreases right to left

Explain the procedures used and data recorded to identify a crystalline mineral based on its properties.

Answers

Answer:

By examining its external shape, color, hardness, etc.

Explanation:

The force of gravity acting on you will increase if you
A. burrow deep inside the planet.
B. stand on a planet with a radius that is shrinking
C. both of these
D.none of these

Answers

Answer:

C.

Explanation:

the closer you get to the centre of an object the greater its gravitational pull- A is correct

If the radius increases the gravity decreases and rise versa - B is correct

the answer is C

The force of gravity acting on you will increase if you  stand on a planet with a radius that is shrinking. So, option (B) is orrect.

What is force?

Force is an external agent that has the power to alter a body's resting or moving condition. It has a size and a movement. The direction of the force is referred to as the force's direction, and the application of force is the place at which the force is applied.

The force of gravity acting on an object due to a planet is given by: F = GMm/R².

Where, G is universal gravitational constant . M and m is masses of the planet and the object respectively and R is distance between them.

Hence, when you stand on a planet with a radius that is shrinking; distance between you and planet decreases. So, the force of gravity acting on you will increase. So, option (B) is correct.

But in the case of burrow deep inside the planet: gravitational force due to outer shell  becomes zero. So, effective gravitational force decreases.

Learn more about force here:

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a bowling ball hits two standing bowling pins at the same time. which of the following is true. assume that all collisions are elastic

Answers

Answer:

b?

Explanation:

At which temperature are the particles in a pencil moving faster: 20°C or 50°C?

Answers

Answer:

movement generates energy=heat so 50c should be it

The Amazon rainforest has millions of trees down in South America. Pantanal, the largest wetland, or swamp, on Earth sits directly below the Amazon on a map. Explain this phenomenon using processes from the water cycle.

The subject is science just to let you know.

Answers

Answer:The Pantanal is, when the season changes of the river flow, the pantanal shrinks after a few river channels The amazon rainforest has a lot of trees.The vapor rises and condenses it into clouds.Water leaves the forest and comes back, the amazon leaves itself.If the amazon water was not to go by itself everything would be different.

Answer:

Nine, Brazil, Venezuela

Explanation:

When the wooden block is placed in the water and allowed to float to the top, what percentage of it is submerged

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, what is described in the question is known as upthrust. Upthrust is an upward force on an object (in this case the wooden block) provided by the liquid (water) as a result of it displacing some of the liquid. Thus floating objects will normally displace some part of the liquid; making some part of it to be submerged in water.

The percentage of the submerged wooden block can be calculated as

length (in height) of the wood block submerged in water/total length (in height) of the wood × 100

If a car traveled 50 meters in 2 seconds, what will the velocity be? (Write the answer with a number, on decimal if needed, then a space and the units, for example 5.7 m/s)

Answers

Answer:

The answer is 25 m/s

Explanation:

The velocity of the car can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question we have

[tex]v = \frac{50}{2} \\ [/tex]

We have the final answer as

25 m/s

Hope this helps you

A 60-kg woman runs up a staircase 15 m high (vertically) in 20 s.

Required:
a. How much power does she expend?
b. What is her horsepowerrating.

Answers

Answer:

(a) 441 W (b) 0.59 hP

Explanation:

Given that,

Mass of a woman, m = 60 kg

Height of a staircase, h = 15 m

Time, t = 20 s

(a) We need to find the power she expend. Work done per unit time is called power. It is given by :

[tex]P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{60\times 9.8\times 15}{20}\\\\P=441\ W[/tex]

( b) Since, 1 hP = 745.7 W

P = 0.59 hP

Two masses are to collide directly with each other. One has a mass of 5 kg and a velocity of 2 m/s. The other has a mass of 3 kg and a velocity of 1 m/2. The collision is perfectly inelastic. Find the velocity of the masses after the collision.

Answers

Answer:

v₃ = 1.625 [m/s]

Explanation:

To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conserved before and after a collision.

Since the collision is inelastic, the two bodies are joined after the collision.

P = m*v [kg*m/s]

m = mass [kg]

v = velocity [m/s]

where:

P = lineal momentum [kg*m/s]

Now, it is important to clarify that in the following equation we will take the left side of the equation as the momentum before the collision and the right side of the equal sign as the momentum after the collision.

Pbefore = Pafter

(m₁*v₁) + (m₂*v₂) = (m₁+m₂)*v₃

where:

m₁ = mass one = 5 [kg]

v₁ = velocity of the mass one = 2 [m/s]

m₂ = mass two = 3 [kg]

v₂ = velocity of the mass two = 1 [m/s]

v₃ = velocity of the combined masses after the collision [m/s]

Now replacing we have:

(5*2) + (3*1) = (5 + 3)*v₃

10 + 3 = 8*v₃

v₃ = 13/8

v₃ = 1.625 [m/s]

The peripheral speed of the tooth of a 10-in.-diameter circular saw blade is 230 ft/s when the power to the saw is turned off. The speed of the tooth decreases at a constant rate, and the blade comes to rest in 17 s. Determine the time at which the total acceleration of the tooth is 130 ft/s2.

Answers

Answer:

The time is  [tex]t_r =21.58 \ s[/tex]  

Explanation:

From the question we are told that

   The  diameter of the circular saw  is [tex]d = 10 \ in = \frac{10}{12} = 0.833 \ feet[/tex]

   The peripheral speed is [tex]u = 230 \ ft/s[/tex]

    The time taken for the blade to come to rest is t = 17 s

    The total  acceleration of the tooth considered is  [tex]a = 130 \ ft/s^2[/tex]  

Generally the radius of the blade is mathematically represented as

            [tex]r = \frac{0.833}{2}= 0. 4165 \ feet[/tex]

Generally the tangential acceleration of the blade is mathematically represented as

           [tex]a__{t}} = \frac{v - u}{t}[/tex]

Here v is the final  velocity of the tooth of the blade which is  zero  since the blade came to  rest

so  

         [tex]a__{t}} = \frac{0 - 230}{ 17}[/tex]

=>      [tex]a__{t}} = - 13.53 \ ft/s^2[/tex]

Generally the total acceleration of the tooth of the blade is mathematically represented as

         [tex]a = \sqrt{a_t^2 + a_r^2}[/tex]

Here [tex]a_r[/tex] is the radial acceleration , now making [tex]a_r[/tex] the subject of the formula we have that

        [tex]130= \sqrt{13.56 ^2 + a_r^2}[/tex]

=>     [tex]a_r = \sqrt{130^2 -(- 13.56)^2}[/tex]

=>     [tex]a_r = 129.3 \ m/s^2[/tex]

Generally radial  acceleration is mathematically represented as

      [tex]a_r = \frac{v_r^2}{r}[/tex]    

Here  [tex]v_r[/tex] is the velocity at which the total acceleration is 130 ft/s2.

=>   [tex]v_r = \sqrt{a_r * r }[/tex]  

=>  [tex]v_r = \sqrt{129.3 * 0.4165 }[/tex]

=>  [tex]v_r = 7.34 \ m/s[/tex]

Generally the time at which the total acceleration is  130 ft/s2. is mathematically represented as

        [tex]t_r = \frac{7.34 - 300}{a_t}[/tex]

=>      [tex]t_r = \frac{7.34 - 300}{-13.56}[/tex]

=>      [tex]t_r =21.58 \ s[/tex]    

QUESTION 13
Marci would describe almost a perfect person whenever her friends would ask her who she thought was
her ideal life partner. This "perfect" person would be ain)
O a prototype
b.reinforcer
oc. anagram
d. heuristic

Answers

The answer is d.heuristic

A current of 15 Amps flows through a circuit with a resistance of 0.10 Ohms. What is the voltage?
A. 0.006 Volts
OB. 1.5 Volts
O C. 15 Volts
D. 150 Volts

Answers

Voltage = (current) x (resistance) (Ohm's law)

Voltage = (15 A) x (0.10 ohm)

Voltage =  1.5 volts (B)

If the jet is moving at a speed of 1140 km/h at the lowest point of the loop, determine the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.0 g's.

Answers

Answer:

The radius is  [tex]r =1705.44 \ m[/tex]

Explanation:

From the question we are told that

   The speed is [tex]v = 1140 \ km /h = \frac{1140 * 1000}{3600} = 316.67 \ m/s[/tex]

   The centripetal acceleration is  [tex]a = 6 g's = 6 * 9.8 = 58.8 \ m/s^2[/tex]

Generally the centripetal force acting on the jet is mathematically represented as  

        [tex]F_c = \frac{m * v^2 }{r}[/tex]

Generally this centripetal force is equal to the net force acting which according to Newton's third law is mathematically  represented as

      [tex]F = m * a[/tex]

So

      [tex]\frac{m * v^2 }{r} = ma[/tex]

=>   [tex]\frac{ v^2 }{r} = a[/tex]

=>  [tex]r = \frac{v^2}{a}[/tex]

=>  [tex]r = \frac{316.67^2}{58.8}[/tex]

=>  [tex]r =1705.44 \ m[/tex]

what is a factor that scientists use to classify orders of soil?

Answers

climate, plant type, soil composition.

Which of the following is made up of vibrating electric and magnetic fields
traveling together?
A. An electromagnetic wave
B. A generator
C. An induced current
D. An electromagnet

Answers

Answer:

A. An electromagnetic wave

Explanation:

A P E X

What is the magnitude of the tangential acceleration of a bug on the rim of a 13.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 79.0 rev/min in 3.80 s

Answers

Answer:

The correct solution will be "12.48 in/s²".

Explanation:

The given values are:

Angular speed

= 79.0 rev/min

Time

= 3.80 seconds

Now,

⇒  [tex]Angular \ acc.=\frac{(\frac{79\times 2\times \pi}{60})}{3.8}[/tex]

                          [tex]=\frac{8.2}{3.8}[/tex]

                          [tex]=2.1 \ rad/s^2[/tex]

Tangential acceleration will be:

= [tex]Angular acc.\times radius[/tex]

= [tex]2.1\times 6.5\times 0.0254[/tex]

= [tex]0.3467 \ m/s^2[/tex]

= [tex]12.48 \ in/s^2[/tex]

for a solar eclipse to occur which of the following alignments must be necessary

Answers

very specific alignment of the Sun, Earth, and Moon. If the Moon is lined up precisely with the Sun from the Earth's point of view, the Moon will block Sunlight from reaching the Earth, causing a solar eclipse.

Which chemicals are major contributors to ozone layer destruction? Select two answer choices.

Answers

Answer:

what are the answers to select? or do you just say them

Explanation:

???

Answer:

c and d

Explanation:

A batter hits a foul ball. The 0.140-kg baseball that was approaching him at 40.0 m/s leaves the bat at 30.0 m/s in a direction perpendicular to the line between the batter and the pitcher. What is the magnitude of the impulse delivered to the baseball?
A) 9.80 Ns
B) 3.50 Ns
C) 7.00 Ns
D) 5.60 Ns
E) 1.40 Ns

Answers

Answer:

The magnitude of the impulse delivered to the baseball is 7.0 Ns

Explanation:

Given;

mass of the foul ball, m = 0.14 kg

initial velocity, u = 40 m/s

final velocity, v = 30 m/s in perpendicular direction

Impulse is given as change in momentum;

initial momentum in horizontal direction, Pi = mu

Pi = 0.14 x 40 = 5.6 Ns

final momentum in perpendicular direction, Pf = mv

Pf = 0.14 x 30

Pf = 4.2 Ns

The resultant impulse is given by;

J² = 5.6² + 4.2²

J² = 49

J = √49

J = 7.0 Ns

Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns

A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23 m/s. If the ball was caught 42 m from the thrower:

What is the initial vertical velocity?

What is the initial horizontal velocity?

How long was it in the air?

How high did the ball travel before being caught?

Answers

Answer:

a) [tex] v_{0y} = 9.72 m/s [/tex]

b) [tex] v_{0x} = 20.85 m/s [/tex]

c) [tex] t = 2.01 s [/tex]

d) [tex] h_{max} = 4.82 m [/tex]

Explanation:

a) The initial vertical velocity is given by:

[tex] v_{0y} = v*sin(\theta) [/tex]

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

[tex] v_{0y} = 23 m/s*sin(25) = 9.72 m/s [/tex]

b) The initial horizontal velocity can be calculated as follows:

[tex] v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s [/tex]

c) The flight time can be calculated using the following equation:

[tex] v_{0x} = \frac{x}{t} [/tex]

Where:

x: is the total distance = 42 m

[tex] t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s [/tex]

d) The maximum height is given by:

[tex] v_{fy}^{2} = v_{0y}^{2} - 2gh_{max} [/tex]

Where:

[tex] v_{fy}[/tex]: is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

[tex]h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m[/tex]

I hope it helps you!                                  

A 1,200 kg roller coaster car starts rolling up a slope at a speed of 15 m/s. What is the highest point it could reach?

Answers

Answer:

11.48 m

Explanation:

The following data were obtained from the question:

Mass (m) of the roller coaster = 1200 Kg

Initial velocity (u) = 15 m/s.

Final velocity (v) = 0 m/s (at highest point)

Acceleration due to gravity (g) = 9.8 m/s²

Highest point (h) =?

The highest point reached by the roller coaster can be obtained as illustrated below:

h = u²/2g

h = 15² / 2 × 9.8

h = 225/19.6

h = 11.48 m

Therefore, the highest point reached by the roller-coaster is 11.48 m

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