A gas occupies 1.56m at an atm. What would be the volume of this gas if the pressure becomes 3 atm.​

Answers

Answer 1

Answer:

The volume of this gas when pressure becomes 3.00 ATM is 0.52 liters 

Explanation:

Answer 2

Answer:

in image

Explanation:

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A Gas Occupies 1.56m At An Atm. What Would Be The Volume Of This Gas If The Pressure Becomes 3 Atm.
A Gas Occupies 1.56m At An Atm. What Would Be The Volume Of This Gas If The Pressure Becomes 3 Atm.

Related Questions

How far will the driver be behind the vehicle in front at 30mph ? Give your answer to 2 significant figures

Answers

The driver should be at least 39 meters behind the vehicle in front at 30mph. Rounded to 2 significant figures, this is 39 meters.

Meters are a unit of length used in the International System of Units (SI) to measure distance or displacement. A meter is defined as the length of the path traveled by light in a vacuum during a time interval of 1/299,792,458 of a second. This definition provides a precise and universal standard for the measurement of length, as the speed of light is constant and independent of the observer.

Meters are commonly used to measure the length or width of objects, as well as the distance between two points. They are also used in scientific fields such as physics, where they are used to measure quantities such as wavelength and amplitude.

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in the diagram, a conducting loop has a current running through it counter-clockwise. in which direction is the magnetic field inside of the loop going to be pointing?

Answers

Answer:

Place the thumb of your right  hand in the direction  of the current and the fingers will be pointing "upwards" - this is handy for long straight wires

The diagram shows the cross-section of a progressive transverse wave travelling at 24 cm s−1 on
water. The amplitude of the wave is 2.0 cm and the frequency is 4.0 Hz.
Which statement is correct?
A The phase difference between particles at P and S is rad.
B The distance between P and R is 6.0 cm.
C The particle velocity at Q is a maximum.
D Particles at P and R are in phase.

Answers

The amplitude of wave is 2.0 cm and the frequency is 4.0 Hz, then the correct statements are : B) The distance between P and R is 6.0 cm ; D)Particles at P and R are in the phase.

What is meant by transverse wave?

Moving wave whose oscillations are perpendicular to the direction of the wave is known as transverse wave.

As we know, v = fλ

v is the velocity of wave, f is frequency, and λ is wavelength.

λ = v/f

λ = 24 cm s−1 / 4.0 Hz = 6.0 cm

So the wavelength of the wave is 6.0 cm.

A.)The phase difference between particles at P and S is π/2 radians.

This statement cannot be determined from given information.

B.)Distance between P and R is 6.0 cm.

This statement is correct as the distance between two consecutive points on a wave with wavelength of 6.0 cm is also 6.0 cm.

C.)The particle velocity at Q is maximum.

This statement cannot be determined from given information.

D.)Particle at P and R are in phase.

This statement is correct as particles at two points on a wave with wavelength of 6.0 cm are in phase.

Therefore, correct statements are B and D.

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PLEASE HELP MEE
Two blocks of silver have a temperature of 175°C. One block has a mass of 33g, the other block has a mass of 300g. Do the blocks have the same amount of thermal energy? Why or why not?

Answers

Answer & Explanation FROM YOUR TEACHER:

The blocks does not have the same amount of thermal energy

The mass and temperature of an item are both inversely correlated with thermal energy. Thermal energy is expressed as follows:

Mass times Specific Heat Capacity times Temperature equals thermal energy.

where the material's specific heat capacity relates the amount of heat required to raise a unit mass of the material's temperature by one degree Celsius.

Even if the two blocks are at the same temperature, they will have different quantities of thermal energy since they have different masses. Assuming they are both composed of the same material and have the same specific heat capacity, the block with a mass of 300g will contain more thermal energy than the block with a mass of 33g.

33g × specific heat capacity x 175°C Equals 33g thermal energy of a 33g block.

Heat capacity of a 300g block is equal to 300g times 175°C in terms of thermal energy.

The thermal energy of the two blocks will vary since the masses are different.

Which have the longer wavelength, radio waves or microwaves?

Answers

The correct answer in that the Radio waves have a longer wavelength than microwaves.

Radio waves have a wavelength range of about 1 millimeter to 100 kilometers, while microwaves have a wavelength range of about 1 millimeter to 1 meter. This means that radio waves have a longer wavelength than microwaves in general. Wavelength is related to the frequency of the electromagnetic wave by the equation: λ = c / f, where λ is the wavelength, c is the speed of light, and f is the frequency. Since the speed of light is constant, a longer wavelength corresponds to a lower frequency and vice versa. Radio waves are commonly used for communication and broadcasting, while microwaves are used for a variety of applications including cooking food, radar, and wireless communication. Understanding the properties of different electromagnetic waves, including their wavelength and frequency, is important for many areas of science and technology.

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A) A force of 4. 40 N is applied to a dart over a distance of 54 cm. The dart has a mass of 28 g. Assuming no energy is lost due to friction, what will be the kinetic energy of the dart after it is thrown?

b) Use your result in part a) calculate the speed of the dart

c) If the dart were thrown straight upwards, what maximum height would it reach?

Answers

a) The kinetic energy of the dart after it is thrown is 2.376 J.

b) The speed of the dart is 18.45 m/s.

c) If the dart were thrown straight upwards, the maximum height it would reach is 17.0 m.

a) The work done on the dart by the applied force is given by:

work = force x distance = 4.40 N x 0.54 m = 2.376 J

Since no energy is lost due to friction, all of this work is converted to the kinetic energy of the dart:

kinetic energy = work = 2.376 J

b) The kinetic energy of the dart can also be expressed as:

kinetic energy = (1/2) x mass x velocity^2

Rearranging this equation gives:

velocity^2 = (2 x kinetic energy) / mass

Substituting the values from part a) gives:

velocity^2 = (2 x 2.376 J) / 0.028 kg = 340.29 m^2/s^2

Taking the square root of both sides gives:

velocity = 18.45 m/s

c) When the dart is thrown straight upwards, its initial vertical velocity is zero. The maximum height it will reach can be calculated using the formula:

maximum height = (initial velocity^2) / (2 x acceleration)

where acceleration is the acceleration due to gravity, which is approximately 9.81 m/s^2.

Substituting the speed calculated in part b) gives:

maximum height = (18.45 m/s)^2 / (2 x 9.81 m/s^2) = 17.0 m

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A bowl is shaped like a hemisphere with diameter 76 cm. A heavy ball with diameter 8 cm is placed in the bowl and water is poured into the bowl to a depth of h centimeters. Find the volume v of water in the bowl. (consider two cases: one in which the ball is not completely submerged and the other in which it is. )

Answers

The volume of water in the bowl is then:

v = (2/3)π(38)^3 - (1/3)π(h - 4)^2(3h + 8) - 256π/3 Case 1: The ball is not completely submerged

The volume of water displaced by the ball is equal to the volume of the ball. The radius of the ball is 4 cm, so its volume is (4/3)π(4)^3 = 256π/3 cm^3. The height of the water in the bowl is h - 4 cm, where h is the total height of the water and the ball. The volume of water in the bowl is given by the formula for the volume of a hemisphere with radius 38 cm minus the volume of the spherical segment cut off by the water level: v = (2/3)π(38)^3 - (1/3)π(h - 4)^2(3h + 8). The volume of water in the bowl is then:

v = (2/3)π(38)^3 - (1/3)π(h - 4)^2(3h + 8) - 256π/3

Case 2: The ball is completely submerged

In this case, the volume of water displaced by the ball is equal to the volume of the ball. The height of the water in the bowl is h, so the radius of the water level is (38^2 - 4^2)^(1/2) = 37.83 cm (by the Pythagorean theorem). The volume of water in the bowl is then the volume of a spherical cap with radius 37.83 cm and height h, minus the volume of the ball:

v = (1/3)πh^2(3(37.83) - h) - (4/3)π(4)^3

Note that the volume of the ball is the same in both cases, but the volume of water in the bowl is different.

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What is the electric field strength between two parallel charged plates that are 3.50 cm apart and have a potential difference of 18.0 V?

Answers

The electric field strength between the two parallel charged plates is 514.29 V/m.

How do you determine the electric field strength between two parallel charged plates?

The electric field strength (E) between two parallel charged plates can be determined using the formula:

E = V / d

where V is the potential difference (in volts) between the plates, and d is the distance (in meters) separating them.

In this case, the potential difference V is 18.0 V and the distance d is 3.50 cm. First, we need to convert the distance from centimeters to meters:

d = 3.50 cm x (1 m / 100 cm) = 0.035 m

Now we can calculate the electric field strength:

E = 18.0 V / 0.035 m = 514.29 V/m

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can some one help me answer this qustion

Answers

The X component of the tiger's velocity is 53.59 km/h.

The vertical (Y) component of the tiger's velocity is 12.37 km/h.

What are the component of the tiger's velocity?

The components of the tiger's velocity include X and Y components; the magnitudes of the X and Y components is calculated using the following formula.

The X component of the tiger's velocity is calculated as;

Vx = V cosθ

where;

θ is the angle of the velocityV is the magnitude of the velocity

Vx = 55 km/h  x  cos (13)

Vx = 53.59 km/h

The vertical (Y) component of the tiger's velocity is calculated as;

Vy = V sinθ

Vy = 55 km/h  x sin (13)

Vy = 12.37 km/h

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A block weighing 12.0 newtons is on a ramp inclined at 30.0° to the horizontal. A 3.0-newton force of friction, Fƒ, acts on the block as it is pulled up the ramp at constant velocity with force F, which is parallel to the ramp, as shown in the diagram. What is the magnitude of force F?
A) 9.0N
B) 10.0N
C) 12.0 N
D) 15.0N

Answers

the block when it is being hauled up the slope at a constant speed using force F perpendicular to a ramp, with a force of 10.0N.

What is force, and what is its unit?

Force is indeed a physical phenomenon that alters or has the potential to alter an object's shape, its state of motion, or both.

What is force, and what is its equation?

According to Newton's second law of motion, the force corresponds to the momentum change divided by the time change. Force equals mass times acceleration, or F = m x a, for a constant mass.

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how tall must a water-filled manometer be to measure blood pressure as high as 300 mm hg? density of blood is 1.05 x 103 kg/m3

Answers

The height of a water-filled manometer required to measure blood pressure as high as 300 mm Hg is 229.69 cm.

A manometer is a pressure measurement device that is utilized to measure the pressure of gases and liquids in a container.

The weight of the liquid in the manometer rises or falls depending on the pressure of the gases and liquids in the container.

In order to measure blood pressure, a water-filled manometer is used. The density of blood is 1.05 x 103 kg/m3. The height of the manometer is required to be found.

The pressure of blood is 300 mm Hg.

The following formula will be used to calculate the height of the manometer:

h = (P*d)/(g*H2O)

where, P = 300 mm Hg,

d = 1.05 × 103 kg/m^3,

g = 9.8 m/s2, and

H2O = 1000 kg/m^3

Substituting the values in the equation:

h = (300*1.05*103)/(9.8*1000)

h = 229.69 cm

The height of the manometer must be 229.69 cm to measure blood pressure as high as 300 mm Hg.

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onsider the two statements below. Which of the following best explains (I) and (II)? (I) the Ka of HXO2 is greater than the Ka of HYO2, but (II) the Ka of HX is less than the Ka of HY (A) (I) X is more electronegative than Y, and (II) the H-X bond is shorter than the H-Y bond (B) (I) X is less electronegative than Y, and (II) the H-X bond is longer than the H-Y bond (C) (I) the HX bond is weaker than the H-Y bond, and (II) X is more electronegative than Y (D) (I) the HX bond is stronger than the H-Y bond, and (II) X is less electronegative than Y

Answers

(I) The Ka of HXO2 is greater than the Ka of HYO2 because the HX bond is weaker than the H-Y bond. This is because X is more electronegative than Y, which means the electron density in the H-X bond is more attracted to X, making the bond weaker than the H-Y bond. The best explaination is option (C).

(II) The Ka of HX is less than the Ka of HY because the H-X bond is longer than the H-Y bond. This is because X is more electronegative than Y, which means that the electron density in the H-X bond is more attracted to X, causing it to be longer than the H-Y bond.

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A 0. 60 kg spike is hammered into a railroad

tie. The initial speed of the spike is equal to

1. 8 m/s.

If the tie and spike together absorb 57. 8

percent of the spike's initial kinetic energy

as internal energy, calculate the increase in

internal energy of the tie and spike.

Answer in units of J.

Answers

The increase in internal energy of the tie and spike is approximately 1.12 Joules.

The initial kinetic energy of the spike is:

K_i = (1/2) * m * v^2

K_i = (1/2) * 0.60 kg * (1.8 m/s)^2

K_i = 1.94 J

The amount of kinetic energy that is absorbed as internal energy is:

K_absorbed = 0.578 * K_i

K_absorbed = 0.578 * 1.94 J

K_absorbed = 1.12 J

Thus,the value is 1.12 Joules.

Kinetic energy is the energy an object has because of its motion. If we want to accelerate an object, then we must apply a force. Applying a force requires us to do work. After work has been done, energy has been transferred to the object, and the object will be moving with a new constant speed.

Kinetic energy is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy. A person walking, a soaring baseball, a crumb falling from a table and a charged particle in an electric field are all examples of kinetic energy at work.

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A crate is placed on the flatbed of truck and is free to move. Truck accelerates in the positive +x direction (to the right) too fast and crate slides and falls back of the truck. There is some friction between the truck bed and the crate.(a) When the crate falls off, in what direction is it moving relative to the ground?Choose the correct option:A. It is not moving with respect to the groundB. To the left (negative x direction)C. To the right (positive x direction)

Answers

Answer:

(C) it is moving to the right wrt to the ground

The crate is accelerated to the right (wrt the ground) because the frictional force between the truck bed and the crate is to the right and it is this force that provides movement to the crate

Answer : a) The crate will be moving in the negative x direction (to the left) when it falls off the truck. The force of the acceleration of the truck in the positive x direction will push the crate in the negative x direction. This will cause the crate to move away from the truck in the negative x direction. Correct answer is option B

This is because the truck is accelerating in the positive x direction (to the right), and the crate, being free to move, will have the same acceleration as the truck. This will cause the crate to slide backwards off the truck in the negative x direction.

Therefore, the crate will be moving in the negative x direction (to the left) when it falls off the truck.

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What are two reasons digital storage of data is more secure than analog
storage?
A. Digital data can be encoded by a computer program.
B. Digital data can be protected by a fingerprint or facial ID.
C. Access to digital data requires a stronger password.
D. Digital data are easy to change with a computer program.
SUBMIT

Answers

Digital data can be encoded by a computer program and are easy to change by a computer program. Therefore, options A and D are correct.

Why are the given two options correct?

A and D are two reasons why digital storage of data is more secure than analogue storage.

A - Digital data can be encoded using various encryption techniques that make it more difficult for unauthorized individuals to access or interpret the data.

D - Digital data are easy to change or modify using a computer program, but this can also be a security advantage as it allows for quick updates and corrections to be made, and changes can be tracked and logged for security purposes.

B and C are not necessarily unique to digital storage, and may also be applicable to analogue storage. Fingerprint or facial ID can be used to protect physical storage devices, and a strong password can also be used to secure both digital and analogue storage.

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Answer:

A. Digital data can be encoded by a computer program.

B. Digital data can be protected by a fingerprint or facial ID.

Explanation:

did quiz

If a bus is running with a speed of 72km HR calculate the distance traveled in 5 sec​

Answers

Answer:

0.1 KM/S

Explanation:

First, looking at the question we can say a few things: distance = speed/time. First we will change the 72 KM/HR to ? KM/S (seconds). To change the units fo the speed to seconds, we need to find how many seconds are in an hour which is 3600) then we have 72 KM/3600S and we will divide 3600 by 5 to get 720 which is what we will divide 3600 by to get to 5 seconds and what we will divide 72 by to get your speed in kilometers for your answer. 3600/720 = 5 seconds, and 72/720 is equal to 0.1. To format your answer, you would get 0.1 KM/S (kilometers/seconds)

If your teacher won't accept that answer or you want to change the unit of measurement for speed, you can also find out how many feet/miles a kilometer is and then multiply 0.1 times that value and then you'd have ? ft/s or mi/s.

1. The speed of a bobsled is increasing because it has an acceleration of 2.4 m/3. At a given instant in time, the forces resisting the motion, including kinetic friction and air resistance, total 450 N. The combined mass of the bobsled and its riders is 270 kg. (a) What is the magnitude of the force propelling the bobsled forward? (b) What is the magnitude of the net force that acts on the bobsled?

Answers

Answer:

Explanation:

Fnet = ma = (270 kg)(2.3 m/s²) = 621 N

Fnet = F-forward - F-resistance

a)  F-forward = Fnet + F-resistance = 621 N + 450 N = 1,071 N

b)  Fnet = F-forward - F-resistance = 1071 N - 450 N = 621 N

Problem 7.4 Two capacitors, each of capacitance 2 μF are connected in parallell. If the p.d. across them is 120V, calculate the charge on each capacitor.​

Answers

Answer:

240 μC

Explanation:

When two capacitors are connected in parallel, the effective capacitance is the sum of the individual capacitances. In this case, the effective capacitance is:

C = C1 + C2 = 2 μF + 2 μF = 4 μF

The charge on a capacitor is related to the capacitance and the potential difference across it by the equation:

Q = C × V

where Q is the charge, C is the capacitance, and V is the potential difference.

Using this equation, the charge on each capacitor can be calculated as follows:

Q1 = C1 × V = 2 μF × 120 V = 240 μC

Q2 = C2 × V = 2 μF × 120 V = 240 μC

Therefore, the charge on each capacitor is 240 μC.

sarah attempts to do the popular physics trick of swinging a shallow pail of water around in a vertical circle with uniform circular motion so that the water doesn't spill out when the pail is upside down. if the distance from the bottom of the pail to her shoulder (the center of rotation) is 0.449 meters long, what is the minimum constant tangential speed that the pail bottom must have so that the water does not spill out at the top of the circular path

Answers

A pail of water is swung in a vertical circle using a uniform circular motion. In order to make sure that the water doesn't spill out when the pail is upside down, a minimum constant tangential speed of 2.1 m/s is required.

The minimum constant tangential speed required by the pail of water in order to ensure that the water doesn't spill out when the pail is upside down can be calculated using the formula:

[tex]v = \sqrt{gr}[/tex]

where v = minimum constant tangential speed g = acceleration due to gravity r = radius of the circle.

The distance from the bottom of the pail to Sarah's shoulder is 0.449 m long.

Since this distance is the radius of the circular path, we can substitute it in the formula.

Therefore,

[tex]v = \sqrt{9.8 m/s^2 \times 0.449 \ m} = \sqrt{4.4102 m^2/s^2} = 2.1 \ m/s[/tex]

Therefore, the minimum constant tangential speed required by the pail of water is approximately 2.1 m/s.

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If old mountains are worn down over the course of millions of years, what is one of the primary reasons that mountains still exist?

Answers

Volcanic activity and the movement of lithospheric plates both result in the formation of new mountains.

Describe volcanic activity.

Volcanic activity can include the release of gases, pro lava emissions, or extremely ferocious explosive bursts that can last for several hours. Volcano shapes and sizes are influenced by eruption type, which also affects the relative volumes & types of lava flows and volcaniclastic debris.

What would occur in the event that Yellowstone erupted?

Worldwide repercussions would result from another big caldera-forming eruption at Yellowstone. The repercussions of such a large eruption would be felt locally and include ash fall and short-term (decades to years) changes to the global climate.

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if you were in a rocket ship travelling away from earth at a speed close to the speed of light, what changes would you notice in the clock and volume of your friend who stayed on earth?

Answers

If you were in a rocket ship traveling away from earth at a speed close to the speed of light, then the changes that you would notice in the clock and the volume of your friend who stayed on earth are time dilation and volume dilation.

Time dilation: According to special relativity theory, time dilation occurs as an object's velocity approaches the speed of light. The faster an object travels, the slower its internal clock ticks. Time would seem to pass more slowly for you than it would for your friend on earth. The time on the rocket would appear to be slower than the time on the earth, and the rocket's clock would tick more slowly as seen from the earth.

Volume dilation: Volume dilation is a term used to describe a length contraction or expansion of an object along the direction of motion. According to the Lorentz transformation, as the velocity of an object approaches the speed of light, its length appears to shrink in the direction of motion.

This would result in the volume of the object appearing to decrease in size as well. Your friend on earth would notice that your rocket ship appears to be shorter than it really is, and its volume would appear to be less.

Therefore, time dilation and volume dilation are the two factors that would be noticed.

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Two people leave points A and B at the same time. They intend to meet at point C at the same time. The person who leaves point A walks at a speed of 3 miles per hour. You and a friend are trying to determine how fast the person who leaves point B must walk. Your friend claims you need to know the length of . Is your friend correct? Explain your reasoning.

Answers

Your friend is correct. In order to determine the speed at which the person who leaves point B must walk, you need to know the length of AC and BC.

This is because the time it takes for each person to reach point C is dependent on the distance they must travel and the speed at which they are traveling.

Using the formula time = distance / speed, you can calculate the time it takes for each person to reach point C.

For the person leaving point A, the time it takes to reach point C is tA = AC / 3, since they are traveling at a speed of 3 miles per hour.

For the person leaving point B, the time it takes to reach point C is tB = BC / x, where x is the speed at which they are traveling.

Since both people are intended to reach point C at the same time, you can set the two equations equal to each other:

AC / 3 = BC / x

Cross-multiplying and solving for x gives you the speed at which the person leaving point B must walk:

x = 3BC / AC

Without knowing the length of AC and BC, you cannot determine the speed at which the person leaving point B must walk. Therefore, your friend is correct.

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electricity flows into hair dryer when it is plugged into a socket. if electricity has been added to the hair dryer ,why doesn't it keep operating for a while after being unplugged?​

Answers

A hair dryer uses the electricity from the power source to run its motor and heating element when it is hooked into an electrical outlet. Heat and kinetic energy are created from this electrical energy.

I was using my hair dryer when the power went off, why?

One of the most frequent causes of circuit breakers being tripped by a hairdryer is an overloaded circuit. A circuit overload occurs when there are several high-powered gadgets drawing 15 to 20 amps of electricity simultaneously on the same circuit.

Does a hair dryer draw power?

A conventional in-room, wall-mounted hair dryer uses roughly 1.6 kW of power on average. This indicates that a guest will use 0.4 kilowatt-hours (kWh) of power if they use their hair dryer for 15 minutes.

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i really need help someone help for the scent e fills

Answers

This implies that when the force applied on an item increases, so does the object's acceleration. Similar to how an object's acceleration decreases as its mass increases, so does its mass.

What principle of Newton's law asserts that a rise in force leads to a rise in acceleration?

Force with acceleration are directly correlated, as shown by Newton's second law. The more force that is exerted to an object, the faster it will accelerate. For instance, the acceleration doubles when the force exerted on an object doubles.

Why does acceleration cause a rise in force?

The relationship among acceleration and force is explained in Newton's second laws of motion. They are comparable in size. An object moves forward at a speed equal to the force pushing against it. The simplest approach to determine force is to multiply mass by acceleration.

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A laborer wants to move crates containing bottles of olive oil from a truck to the ground by sliding them along a ramp. The ramp is 6 m long and is at an angle of 25°. There is friction on the ramp for the first crate. The laborer doesn’t know that there is a small leak in one of the bottles. The leak leaves a layer of oil on the ramp. The oil creates a frictionless surface for the second crate Wayne sends down the ramp. At the bottom of the ramp, the speed of the second crate (without friction) is 2. 5 the speed of the first crate (with friction). Find the coefficient of kinetic friction. Hint: this is a multistep problem that is be solved using only energy equations. Do not use kinematics or you will not receive full credit, even if your answer is correct. Use conservation of energy and start with the frictionless case. (30 pts)

Answers

Therefore, the coefficient of kinetic friction is approximately 0.136

the acceleration of the first crate with friction down the ramp.

We'll use the following formula:

a = gsin(theta) - mucos(theta)*g

whereg = acceleration due to gravity = 9.8 m/[tex]s^2[/tex]

theta = angle of the ramp = 25 degrees

mu = coefficient of kinetic friction

Plugging in the values, we get:

a = 9.8sin(25) - mucos(25)9.8

a = 3.9763 - 3.5299mu

Plugging in the values, we get:

[tex]v^2=[/tex] 0 + 2*(3.9763 - 3.5299*mu)6

[tex]v^2[/tex] = 47.715 - 42.1794mu

the velocity of the second crate without friction at the bottom of the ramp. We know it's 2.5 times the velocity of the first crate with friction, so:v' = 2.5sqrt(47.715 - 42.1794mu)

no friction for the second crate, we can use the conservation of energy to relate the initial potential energy to the final kinetic energy:

mg6sin(25) = 0.5m*[tex]v^2[/tex]

where

g = acceleration due to gravity = 9.8 m/

Simplifying and plugging in the value for v', we get:

mg6sin(25) = 0.5m*)(47.715 - 42.1794mu)

3.5299 = 11.885 - 10.545*mu

mu = 0.136

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A body slides down a smooth inclined plane at 30° to the horizontal. The distance covered after 15s from rest is

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The distance covered by the body after 15 seconds down the inclined plane is approximately 1102.5 meters.

We can use the equations of motion to solve this problem. The acceleration of the body down the inclined plane can be found using trigonometry:

a = gsin(30°) = (9.8 m/s²)(1/2) = 4.9 m/s²

where g is the acceleration due to gravity.

Using the equation of motion:

s = ut + (1/2)at²

where s is the distance covered, u is the initial velocity (which is zero in this case), and t is the time taken, we can find the distance covered after 15 seconds:

s = (1/2)4.9(15)² = 1102.5 meters

Therefore, the distance covered by the body after 15 seconds down the inclined plane is approximately 1102.5 meters.

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9. A 1385-kg pickup truck hitched to a 453-kg

trailer accelerates along a level road from a

stoplight at 0. 75 m/s2 [forward]. Ignore friction

on the trailer and air resistance. Calculate

(a) the tension in the hitch a

(b) the force of static friction exerted by the road

on the pickup truck to propel it forward a

(c) the force the trailer exerts on the pickup

truck a

Answers

(a) The tension in the hitch is 339.75 N.

equal to the mass of the trailer times the acceleration (453 kg x 0.75 m/s2 = 339.75 N).
(b) The force of static friction exerted by the road on the pickup truck is  1038.75 N.
(c) The force the trailer exerts on the pickup truck is equal to 339.75 N.

(a) The tension in the hitch is equal to the mass of the trailer times the acceleration.

It is calculated by,

453 kg x 0.75 m/s2

= 339.75 N.

(b) The force of static friction exerted by the road on the pickup truck to propel it forward is equal to the mass of the pickup truck times the acceleration

It is calculated by

1385 kg x 0.75 m/s2

= 1038.75 N

(c) The force the trailer exerts on the pickup truck is equal to the mass of the trailer times the acceleration.

It is calculated by,

453 kg x 0.75 m/s2

= 339.75 N

Static friction is a force that keeps an object at rest. Static friction definition can be written as: The friction experienced when individuals try to move a stationary object on a surface, without actually triggering any relative motion between the body and the surface on which it is on.

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Peter is heating water on the stove to boil eggs for a picnic. How much heat is required to raise the temperature of his 10 kg vat of water from 20°C to 100°C?

Answers

Answer:

The specific heat capacity of water is 4.184 J/g°C, and we need to find the amount of heat required to raise the temperature of 10 kg (or 10,000 g) of water from 20°C to 100°C.

The formula for calculating the amount of heat required is:

Q = m * c * ΔT

where:

Q = heat energy (in Joules)

m = mass (in grams)

c = specific heat capacity (in J/g°C)

ΔT = change in temperature (in °C)

We can start by calculating the change in temperature:

ΔT = 100°C - 20°C = 80°C

Then, we can plug in the values and solve for Q:

Q = 10,000 g * 4.184 J/g°C * 80°C

Q = 3,347,200 J

Therefore, Peter needs 3,347,200 Joules of heat to raise the temperature of his 10 kg vat of water from 20°C to 100°C.

Two cars are traveling towards one another. The VW Bug has a mass of 187 kg and its initial velocity is -38 m/s. The compact car has a mass of 702 kg and an initial velocity of 23 m/s. They collide and stick together. How fast does the wreckage move immediately after the collision

Answers

Answer:

10.17 m/s in the direction the compact car was going (+)

Explanation:

Law of conservation of momentum states that total P before the collision must equal total momentum after the collision.

P = mv

solve for v, velocity of the two cars stuck together after the collision:

(187kg)(-38 m/s) + (702kg)(23 m/s) = (187 + 702 kg)v

         momentum before               =   momentum after

-7106 kg·m/s + 16146 kg·m/s = 889 kg(v)

9040 kg·m/s = 889 kg(v)

v = 9040 kg·m/s / 889 kg = 10.17 m/s

Polarizing windows, filters, etc. , are often used to reduce the amount of light that enters the lens of a camera or into a room or a car. A library atrium has an overhead skylight that lets in too much light during the day, which heats up the interior of the library far too much. The building engineer installs new double-paned polarizing sky lights to reduce the intensity. If sunlight, which is unpolarized, has an average intensity of 1340 W/m2, what angle should the polarizing axis of the second pane of the window make with the polarizing axis of the first pane of the window in order to reduce the intensity of the sunlight to 34% of the original value

Answers

The polarizing axis of the second pane of the window make with the polarizing axis of the first pane of the window in order to reduce the intensity of the sunlight to 34% of the original value is [tex]23^o[/tex].

The intensity of the sunlight falling from the first pane

[tex]I_1 = \frac{I_o}{2}[/tex]

Once this intensity light passes through the second pane then

[tex]I_2 = I_1 \cos^2 \thetaI_2 = \frac{I_o}{2} \cos^2 \theta[/tex]

Given I2 /Io = 0.42  (42%) so

[tex]0.42 = \frac{1}{2} \cos^2 \theta\\[/tex]

[tex]\cos^2 \theta = 0.84[/tex]

[tex]\cos \theta = \sqrt{0.84} = 0.9165\\[/tex]

[tex]\theta = \cos^{-1} ( 0.9165) = 23.6^o[/tex]

The polarizing axis, also known as the polarization direction, is the direction of the electric field oscillation of an electromagnetic wave. When light passes through a polarizing filter, only the component of the electric field parallel to the polarizing axis is allowed to pass through, while the perpendicular component is blocked.

For example, a linear polarizing filter has a polarizing axis that allows only light waves oscillating in a specific direction to pass through. If the electric field oscillation of the light is perpendicular to the polarizing axis, it will be blocked, resulting in a darker image. In contrast, circular polarizers have a rotating polarizing axis that can selectively block light waves based on their direction of rotation. This is useful in photography and other applications where glare or reflections need to be minimized.

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