Answer:
Explanation:
From the information given:
We can properly determine the distance where the fish appear in the air viewing it from in front of the bowl by using the formula:
[tex]\dfrac{n_i}{d_o}+\dfrac{n_2}{d_1}= \dfrac{n_2-n_1}{r}[/tex]
where;
[tex]n_1[/tex] = refractive index in the air; = 1.33 &
[tex]n_2[/tex] = refractive index in water. = 1
[tex]\dfrac{n_2}{d_i}= \dfrac{n_2-n_1}{r}-\dfrac{n_1}{d_o}[/tex]
[tex]\dfrac{1}{d_i}= \dfrac{1-1.33}{-21 \ cm}-\dfrac{1.33}{4.7\ cm}[/tex]
[tex]\dfrac{1}{d_i}= - 0.26726 \ cm[/tex]
[tex]d_i =\dfrac{1}{ - 0.26726 \ cm}[/tex]
[tex]\mathbf{d_i }[/tex] = - 3.74 cm
2)
To determine where the fish appear to be when it is 38.9 cm from the front surface of the bowl by using the formula:
[tex]\dfrac{n_2}{d_i}= \dfrac{n_2-n_1}{r}-\dfrac{n_1}{d_o}[/tex]
[tex]\dfrac{1}{d_i}= \dfrac{1-1.33}{-21 \ cm}-\dfrac{1.33}{38.9\ cm}[/tex]
[tex]\dfrac{1}{d_i}=- 0.0184759 \ cm[/tex]
[tex]d_i = \dfrac{1}{- 0.0184759 \ cm}[/tex]
[tex]\mathbf{d_i = }[/tex] -54.12 cm
A 615.00 kg race car is uniformly traveling around a circular race track. It takes the race car 20.00 seconds to do one lap around the 80.00 m radius circular track. What is the frequency of the race car's circular motion?
Answer:
The value is [tex]f = 0.05 \ Hz[/tex]
Explanation:
From the question we are told that
The mass of the car is [tex]m = 615 \ kg[/tex]
The period of the circular motion is [tex]T = 20 \ s[/tex]
The radius is [tex]r = 80 \ m/s[/tex]
Generally the frequency of the circular motion is
[tex]f = \frac{1}{T }[/tex]
=> [tex]f = \frac{1}{ 20 }[/tex]
=> [tex]f = 0.05 \ Hz[/tex]
Suppose you are in a moving car and the motor stops running. You step on the brakes and slow the car to half speed. If you release your foot from the brakes, will the car speed up a bit, or will it continue at half speed and slow due to friction?
Answer:
See the answer below
Explanation:
If you step on the brake of a car while driving, the frictional force between the tires of the car and the surface of the road increases in opposition to the motion of the car. Consequently, the car slows down.
If you release your foot from the brake pedal when the car is still at half speed, the frictional force reduces and the car speeds up a bit even without pressing the throttle. Eventually, the frictional force will slow down and stop the car if the throttle is not pressed.
HOW CAN AN APPLE DEMONSTRATE POTENTIAL AND ENERGY
Answer and Explanation in one:
In physics, potential energy is the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors. So basically, you could possibly demonstrate with a variety of examples. One example may be just sitting on a table, waiting to get rolled off. I know it sounds silly, so here's another example. You are holding a bow and arrow, you pull back the arrow, aiming at the target. You are holding the arrow, filling it with potential energy. When it is let go, it is kinetic energy, the act of an object in motion, slowly riding of it's potential energy.
Coretta feels confident in her abilities, and she frequently makes contributions to her local community. Based on this information, what can you assume is true about Coretta?
A She has good emotional health.
B She makes self-esteem a priority.
C She recently improved her mental health.
D She exercises at least twice a day.
Answer:
A She has good emotional health.
Explanation:
Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by dEdt=q2a26πϵ0c3 where c is the speed of light.Part AIf a proton with a kinetic energy of 5.0 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.530 m , what fraction of its energy does it radiate per second?(dE/dt)⋅1sE =
Answer:
P /K = 1,997 10⁻³⁶ s⁻¹
Explanation:
For this exercise let's start by finding the radiation emitted from the accelerator
[tex]\frac{dE}{dt}[/tex] = [tex]\frac{q^{2} a^{2} }{6\pi \epsilon_{o} c^{2} }[/tex]
the radius of the orbit is the radius of the accelerator a = r = 0.530 m
let's calculate
\frac{dE}{dt} = [(1.6 10⁻¹⁹)² 0.530²] / [6π 8.85 10⁻¹² (3 108)³]
P= \frac{dE}{dt}= 1.597 10⁻⁵⁴ W
Now let's reduce the kinetic energy to SI units
K = 5.0 10⁶ eV (1.6 10⁻¹⁹ J / 1 eV) = 8.0 10⁻¹⁹ J
the fraction of energy emitted is
P / K = 1.597 10⁻⁵⁴ / 8.0 10⁻¹⁹
P /K = 1,997 10⁻³⁶ s⁻¹
In which of the following situations would there be initial energy in the system?
An apple sits motionless on the ground near a tree
A spring is compressed and held at compression by a person before releasing it
A bowstring is neither pulled nor stretched on a bow
An object rests at a velocity of 0 on a flat surface at ground level
Answer:
A spring is compressed and held at compression by a person before releasing it
Explanation:
All the other answers are showing things that are at rest and have no energy starting nor going through them. This answer show how the energy is starting and being released.
How do you compare the mass of proton, neutron, and
electron?
Answer:Explanation:
Protons and neutrons have very similar mass, while electrons are far lighter, approximately 11800 times the mass. Protons are positively charged, neutrons have no electric charge, electrons are negatively charged. The size of the charges is the same, the sign is opposite.
The temp of the metal in a running car engine is 388 K. Find this temp in Celsius.
Answer:
115°c
Explanation:
°c=k-273
388-273=115
Whet net force is required to accelerate a car at a rate of 10 m/s2 if the car
has a mass of 5,000 kg?
Answer:
[tex]\boxed {\boxed {\sf 50,000 \ Newtons }}[/tex]
Explanation:
Force can be found by multiplying the mass by the acceleration.
[tex]F=m*a[/tex]
The mass of the car is 5,000 kilograms and it's acceleration is 10 meters per square second.
[tex]m= 5,000 \ kg \\a= 10 \ m/s^2[/tex]
Substitute the values into the formula.
[tex]F= 5,000 \ kg * 10 \ m/s^2[/tex]
Multiply.
[tex]F= 50,000 \ kg*m/s^2[/tex]
1 kilogram meter per square second is equal to 1 Newton. So, our answer of 50,000 kg*m/s² is equal to 50,000 Newtons[tex]F= 50,000 \ N[/tex]
A net force of 50,000 Newtons is required to accelerate a 5,000 kilogram car at 10 meters per square second.
Which point has the most Potential energy? [Select]
Which point has the most Kinetic energy? [ Select ]
Answer:
Most potential energy: A
Most kinetic energy: D
Explanation:
Kinetic Energy is the type of energy an object has due to its state of motion. It's proportional to the square of the speed.
The equation for the kinetic energy is:
[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]
Where:
m = mass of the object
v = speed at which the object moves
The gravitational potential energy is the energy stored in an object because of its height h in a gravitational field.
It can be calculated with the equation:
U=m.g.h
The point where the object has the most potential energy is that where it has more height. It corresponds to point A.
When the object is at zero height, all of its potential energy was transformed to kinetic, thus the point where the kinetic energy is D.
Most potential energy: A
Most kinetic energy: D
Answer:
potentail enegry at point a and kinetic enegy at point c
Explanation:
i did this i fourth grade please mark brainlist
How much power will it take to move a 10 kg mass at an acceleration of 2 m/s² a distance of 10 meters in 5 seconds?
Answer:
100 Watts
Explanation:
These equations are needed to work out the answer:
power= work done/ time takenwork done= force* distanceforce= mass* accelerationforce: 10 kg* 2m/s= 20
work done: 20* 10m=200
power: 200/2=100
What type of energy is stored in a pendulum at the top of its arc?
Answer:
potential
Explanation:At this point the energy is stored in a form called potential energy. This means that the system has the potential to do work or to become active thanks here to the weight's position high above the lowest point of its swing.
Arrange Kepler's laws in order: a. The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun. b. The path of each planet around the sun is an ellipse with the sun at one focus. c. As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times. a. 3, 2, 1 b. 2, 3, 1 c. 3, 1, 2 d. 1, 2, 3
Answer:
2,3,1
Explanation:
There are 3 laws of Kepler.
First law = The path of each planet around the sun is an ellipse with the sun at one focus.
Second law = As a planet moves in its orbit, a line from the sun to the planet sweeps out equal areas in equal times.
Third law = The ratio of the squares of the periods of any two planets revolving around the sun is equal to the ratio of the cubes of their average distance from the sun.
Hence, the correct order for Kepler's law is: 2,3,1
what is si unit?mention any give phisical quantities with their si unit.
The SI base units are the standard units of measurement defined by the International System held in France is called Si unit.
A 0.25-kilogram ball is observed to accelerate at 4,000 m/sec2 as it is hit with a bat.
How much force is exerted on the bat by the ball?
Answer:
1000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 0.25 × 4000
We have the final answer as
1000 NHope this helps you
A 0.85-kg arrow flies through the air at a speed of 19 m/s. What is the momentum of the arrow?
16 kg m/s
22 kg m/s
160 kg m/s
360 kg m/s
Answer:
16 kg m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 0.85 × 19 = 16.15
We have the final answer as
16 kg m/sHope this helps you
Making and disposing of synthetic materials affects the amount of natural resources that are available. It also can harm the environment. These problems may not affect us in our lifetime. Who will these problems affect?
Answer:
What I put- This will affect animals, the earth, and could affect future generations. Plastic also gets into the oceans causing sea creaters die by eating it.
Sample Answer- Problems that arise from the unavailability of natural resources and from environmental hazards will affect the generations that follow us.
Explanation:
Answer:
This will affect animals, the earth, and could affect future generations. Plastic also gets into the oceans causing sea creaters die by eating it.
Explanation:
Which physical property is best measured using only a balance? A. Density B. Volume C. Color D. Mass
Answer:
D. Mass
hope it helps
Explanation:
Mass is commonly measured with a balance
A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42° . What is the force of static friction acting on the box if box has a gravitational force of 112.1 N ?
Answer:
Explanation:
The force of static friction acting on the box is the frictional force;
Frictional force Ff = Wsin theta (force acting along the ramp)
W is the gravitational force known as the weight
Ff = 112.1sin42°
Ff = 112.1(0.6691)
Ff = 75.00N
Hence he force of static friction acting on the box if box has a gravitational force of 112.1 N id 75.00N
Answer:
75N i did test
Explanation:
4) Choose Yes or No next to the descriptions to indicate whether or not an object
is accelerating,
A car slows down,
A car stays the same speed,
A car goes faster,
Luke walks at a constant speed of 4 mph,
Luke walks north at a constant speed of 4 mph,
Luke walks north at a constant speed of 4 mph, turns right, and walks
Type here to search
A horizontal pipe contains water at a pressure of 110 kPa flowing with a speed of 1.4 m/s. When the pipe narrows to one half its original diameter, what is (a) the speed and (b) the pressure of the water?
Answer:
a
[tex]v_2 = 5.6 \ m/s[/tex]
b
[tex]P_2 = 80600 \ Pa[/tex]
Explanation:
From the question we are told that
The pressure of the water in the pipe is [tex]P_1= 110 \ kPa = 110 *10^{3 } \ Pa[/tex]
The speed of the water is [tex]v_1 = 1.4 \ m/s[/tex]
The original area of the pipe is [tex]A_1 = \pi \frac{d^2 }{4}[/tex]
The new area of the pipe is [tex]A_2 = \pi * \frac{[\frac{d}{2} ]^2}{4} = \pi * \frac{\frac{d^2}{4} }{4} = \pi \frac{d^2}{16}[/tex]
Generally the continuity equation is mathematically represented as
[tex]A_1 * v_1 = A_2 * v_2[/tex]
Here [tex]v_2[/tex] is the new velocity
So
[tex]\pi * \frac{d^2}{4} * 1.4 = \pi * \frac{d^2}{16} * v_2[/tex]
=> [tex]\frac{d^2}{4} * 1.4 = \frac{d^2}{16} * v_2[/tex]
=> [tex]d^2 * 1.4 = \frac{d^2}{4} * v_2[/tex]
=> [tex]1.4 = 0.25 * v_2[/tex]
=> [tex]v_2 = 5.6 \ m/s[/tex]
Generally given that the height of the original pipe and the narrower pipe are the same , then we will b making use of the Bernoulli's equation for constant height to calculate the pressure
This is mathematically represented as
[tex]P_1 + \frac{1}{2} * \rho * v_1 ^2 = P_2 + \frac{1}{2} * \rho * v_2 ^2[/tex]
Here [tex]\rho[/tex] is the density of water with value [tex]\rho = 1000 \ kg /m^3[/tex]
[tex]P_2 = P_1 + \frac{1}{2} * \rho [ v_1^2 - v_2^2 ][/tex]
=> [tex]P_2 = 110 *10^{3} + \frac{1}{2} * 1000 * [ 1.4 ^2 - 5.6 ^2 ][/tex]
=> [tex]P_2 = 80600 \ Pa[/tex]
Convert 45km to miles show your work
Answer:
distance = 27.95 [mi]
Explanation:
in order to solve this problem, we must use the appropriate conversion factor, i.e. a conversion factor that relates the kilometers to Miles.
[tex]1 [km] = 0.6214 [mill]\\45[km]*0.6212[\frac{mill}{1km} ]=27.95 [mill][/tex]
Which of the following charts correctly compares plant and animal cells?
Answer:
Wheres the charts??
Explanation:
How much power is used if a force of 35 newtons is used to push a box a distance of 10 meters in 5 seconds?w=350j
Answer:
How much power is used if 350J of work is done when pushing a box for 5 seconds.
Explanation:
the answer is 70watts
How much heat in kcal is required to change 0.5 kg of ice, originally at - 10 0 * C into steam at 110 C?Constants needed in the problemLatent heat of fusion=79.7 kcal/kg Specific heat of ice=0.5 kcal/kg/K ; Latent heat of vaporization ation = 539 kcal/kg ; Specific heat of water 1.0 kcal/kg/K Specific heat of ieam=0.480 kcal/kg
Answer:
Q = 364.25 kcal
Explanation:
In this question, we will have to calculate the heat absorptions for different steps of temperature rise and phase change. And then we will ad them to calculate total heat absorbed.
1. RISE IN TEMPERATURE OF ICE:
First, the temperature of ice will be increased from - 10°C to 0 °C. Heat absorbed during this process will be given as:
Q₁ = mC₁ΔT₁
where,
Q₁ = Heat absorbed while increasing temperature of ice = ?
m = mass of ice = 0.5 kg
C₁ = specific heat of ice = 0.5 kcal/kg k
ΔT₁ = change in temperature of ice = 0 - (-10) = 10 k
Therefore,
Q₁ = (0.5 kg)(0.5 kcal/kg.k)(10)
Q₁ = 2.5 kcal
2. MELTING OF ICE:
Now, the melting of ice will occur at 0°C and the heat absorbed during this process will be:
Q₂ = m(Latent Heat of Fusion of Ice)
where,
Q₂ = heat Absorbed during melting of ice = ?
Therefore,
Q₂ = (0.5 kg)(79.7 kcal/kg)
Q₂ = 39.85 kcal
3. RISE IN TEMPERATURE OF WATER:
Now, the temperature of water will be increased from 0°C to 100 °C. Heat absorbed during this process will be given as:
Q₃ = mC₃ΔT₃
where,
Q₃ = Heat absorbed while increasing temperature of water = ?
m = mass of water = 0.5 kg
C₃ = specific heat of water = 1 kcal/kg k
ΔT₃ = change in temperature of ice = 100 - 0 = 100 k
Therefore,
Q₃ = (0.5 kg)(1 kcal/kg.k)(100 k)
Q₃ = 50 kcal
4. VAPORIZATION OF WATER:
Now, the vaporization of water will occur at 100°C and the heat absorbed during this process will be:
Q₄ = m(Latent Heat of Vaporization of Water)
where,
Q₄ = heat Absorbed during vaporization of water = ?
Therefore,
Q₄ = (0.5 kg)(539 kcal/kg)
Q₄ = 269.5 kcal
5. RISE IN TEMPERATURE OF STEAM:
Now, the temperature of steam will be increased from 100°C to 110 °C. Heat absorbed during this process will be given as:
Q₅ = mC₅ΔT₅
where,
Q₅ = Heat absorbed while increasing temperature of steam = ?
m = mass of steam = 0.5 kg
C₅ = specific heat of steam = 0.48 kcal/kg k
ΔT₅ = change in temperature of ice = 110 - 100 = 10 k
Therefore,
Q₅ = (0.5 kg)(0.48 kcal/kg.k)(10 k)
Q₅ = 2.4 kcal
Hence, the total heat absorbed to change 0.5 kg of ice at - 10°C into steam at 110°C will be:
Q = Q₁ + Q₂ + Q₃ + Q₄ + Q₅
Q = 2.5 kcal + 39.85 kcal + 50 kcal + 269.5 kcal + 2.4 kcal
Q = 364.25 kcal
a toy car is wound up and released on the floor. it accelerates at a rate of 0.4 m/s/s . the mass of the care is 3kg. what is the force that the cars wheels exert on the floor.
Answer:
1.2N
Explanation:
f=m×a
m=3kg
a=.4m/s/s
3×.4=1.2
kg×m/s/s = N
A train travels at a speed of 30mph and travelled a distance of 240 miles. How long did it take the train to complete its journey? Must show your work
Answer:
8
Explanation:
240 divided by 30 = 8
Earthquakes
Shaking of the ground
Seismographs
Scientific method
Answer:
C. seismographs
Explanation:
Theirs another name for seismographs but c is correct
The weight of an object is measured in air to be 7.0 N. The
object is then immersed in water and its apparent weight is
measured to be 4.0 N. Determine the buoyant force and state
whether or not the object floats.
Answer:
Buoyant force = 3.0 N
The object will not float.
Explanation:
Apparent weight of a body immersed in water is the actual weight of object minus buoyant force
Given in the question that;
Weight of object in air = 7.0 N
Apparent weight of object = 4.0 N
4.0 N = 7.0 N - Buoyant force
Buoyant force = 7.0 - 4.0 = 3.0 N
In this case, the buoyant force is less than weight of the object thus the object will sink.
I WILL GIVE BRAINLYIST
Which of the following types of stars had the smallest initial mass? (10 points)
Group of answer choices
Blue main sequence
Neutron star
Red supergiant
White dwarf
Answer:
White dwarf
Explanation: