A converging-diverging nozzle has a throat area of 10 cm2 and an exit area of 28.96 cm2 . A normal shock stands in the exit when the back pressure is sea-level standard. If the upstream tank temperature is 400 K, estimate (a) the tank pressure and (b) the mass fl ow

Answers

Answer 1

The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

The given parameters:

Throat area of the nozzle, [tex]A^*[/tex] = 10 cm² = 0.001 m²The exit area of the nozzle, A = 28.96 cm² = 0.002896 m²Air pressure at sea level = 101.325 kPa

The ratio of the areas of the converging-diverging nozzle is calculated as follows;

[tex]= \frac{A}{A^*} \\\\= \frac{0.002896}{0.001} \\\\= 2.896[/tex]

From supersonic isentropic table, at [tex]\frac{A}{A^*} = 2.896[/tex], we can determine the following;

[tex]M_e = 2.6 \ kg/s\\\\\frac{P_o}{P_e} = 19.954[/tex]

The tank pressure is calculated as follows;

[tex]\frac{P_o}{P_e} = 19.954 \\\\P_e = \frac{P_o}{19.954} \\\\P_e = \frac{101.325 \ kPa}{19.954} \\\\P_e = 5.08 \ kPa[/tex]

Thus, the tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

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Related Questions

i need some help getting started on an essay for physics. i decided on the topic of roller costers and dont know how to start it. see the image on my requirements.​

Answers

Explanation:

force , motion , electric current

Zoe is setting up a track for a toy car. The track has a ramp that is 32° above horizontal. If Zoe wants the car to travel as a projectile for 1.0 seconds, how fast does the toy car need to be moving as it leaves the ramp?
4.9 m/s
1.0 m/s
9.2 m/s
7.4 m/s m

Answers

Answer:

Explanation:

Not enough information.

IF we ASSUME she wants the car to be at LAUNCH LEVEL after 1 second of flight.

THEN

The highest point will have zero vertical velocity and will have taken ½ second to get there. This means that the initial vertical velocity was

v = gt

vy₀ = 9.8(0.5)

vy₀ = 4.9 m/s

vsinθ = vy₀

v = vy₀/sinθ

v = 4.9/sin32

v = 9.2466...

v = 9.2 m/s

What is the significance of Isaac's name?

Answers

[tex] \large \bf{Answer:-}[/tex]

The name Isaac means “one who laughs” or “one who rejoices.” In the Old Testament of the Bible, Isaac is the firstborn son of Abraham. He is one of the three biblical patriarchs revered by Jews, Christians, and Muslims.

During a car accident on the NJ Turnpike, the airbags deploy. A 79 kg passenger traveling at 32 m/s makes impact with the airbag over a time of 0.25 seconds. What
was the impact force experienced by the passenger?

Answers

Hi there!

Recall that:

Impulse = Δ in momentum = mΔv

Impulse = Force · time

Begin by calculating the change in momentum, or impulse.

I = mΔv = m(vf - vi)

I = (79)(0 - 32) = -2528 Ns

Now, we can use the equation relating force and time to impulse.

I = Ft

Rearrange for time:

I/F = t

-2528/0.25 = -10112 N

**OR, if magnitude ⇒ |-10112| = 10112 N

Sophie applies a 50 n force to push a box 2 meter across the floor calculate the smount of work done in the box

Answers

Work done = force x distance

Work done = 50 x 2

Work done = 100J

explain how water erosion changes land forms

Answers

Answer:

Water erosion can slowly wash away dirt and rocks, wearing away landforms and sometimes forming rivers that can even carve out stone over time.

A rollercoaster accelerates from 10 m/s to 100 m/s2 for 25 seconds. What is the acceleration?

Answers

Answer:

A roller coasters accelerates from an initial velocity of of 6.0 m/s to a final velocity of 70 m/s over 4 seconds. What's the acceleration? Q. Acceleration only takes place when things speed up. Q. A drag racer accelerated from 0 m/s to 200 m/s in 5 s.

Explanation:

Which variable mentioned in Table 2-1 is kept constant? a. amount of time spent swimming b. type of swimming stroke c. number of calories used d. the person swimming

Answers

Answer:

a. amount of time spent swimming

The graph below shows the variation with distance r from the nucleus of the square of the wave function, Ψ^2, of a hydrogen atom according to Schrödinger theory.
A. is most likely to be near a.
B. is always a.
C. is always less than a.
D. is always greater than a.

Answers

The region a represents the distance of the electron from the nucleus.

According to the wave mechanical model of the atom, the probability of finding an electron within a given volume element (representing the atom) is the square of the wave function psi.

Since a is the region in space where there is the greatest probability of finding the electron in the atom, it follows that distance of the electron form the atom is always a.

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3. Particles carrying no charge ____________

Answers

Answer:

Neutrons

Explanation:

How much work is done on a 30 kg object when 20 Newton’s of force is exerted for a distance of 5 meters

Answers

Answer:

Work = force * displacement

= 50 N * 20 Meter

=1000 Newton meter = 1000 joule .

Explanation:

Predict changes in state according to change in particle motion. Know the vocabulary used to describe changes of state.

Answers

The change in the state of matter causes change in the motion of the particles of the matter. The gaseous state of matter has the greatest speed while the solid state has the least speed.

The change in state of every matter is accompanied by lost or gained of energy.

Example is water.

The solid state of water is ice. The motion of particles of the water is relatively zero because the molecules are held at a fixed position.

The liquid state of water occurs when the temperature of the ice is increased above zero degree Celsius. The speed of the particles of water in liquid state is greater than solid state.

The gaseous state of water occurs when the temperature of the liquid water is increased beyond 100 degree Celsius. The speed of water in gaseous state is greater than liquid state.

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Hydrochloric acid and sodium hydroxide react to produce water and sodium chloride in endothermic reaction. Which statement must be true of the reaction?

A. more bond energy is absorbed on the reactants side than is released on the products side.

B. The energy of each bond in water and sodium chloride is greater than the energy of each bond in hydrochloric acid and sodium hydroxide

C. The bond energy used to break the bonds in hydrochloric acid in the sodium hydroxide is less than the energy released to from the bonds in water and sodium chloride.

D. The total energy of wster and sodium chloride is greater than the total bond energy of hydrochloric acid and sodium hydroxide. ​

Answers

In the endothermic reaction, the total energy of water and sodium chloride is greater than the total bond energy of hydrochloric acid and sodium hydroxide.

Endothermic reactions are reactions in which heat energy is absorbed during the reaction. The formation of products by the reactants requires addition of heat because the energy required to form the bond in the products is greater than the energy released when reactant bond are broken.

Thus, in an endothermic reaction, the total bond energy of the products are greater than the bond energy of the reactants.

The properties of endothermic reactions include:

Heat is absorbed by the system from the surroundings The entropy of the surrounding decreases (ΔS <0) Enthalpy change (ΔH) is positive

Examples of endothermic reactions include;

Cooking of foodDissolution of ammonium chloride in water

The reaction between acids and bases to form salt and water known as neutralization reactions are usually exothermic in nature.

However, if a given reaction between hydrochloric acid and sodium hydroxide to produce water and sodium chloride is endothermic as in the question, the total energy of water and sodium chloride is greater than the total bond energy of hydrochloric acid and sodium hydroxide. ​

Learn more at: https://brainly.com/question/11906094

Learn more at: https://brainly.com/question/6506846

Answer: C.) The total bond energy of water and sodium chloride is greater than the total bond energy of hydrochloric acid and sodium hydroxide.

Hope this helps :)

A 1250 kg car is stopped at a traffic light. A 3550 kg truck moving at 8.33 m/s strikes the car from behind, causing the bumpers to lock together.

A) What is the momentum of the car-truck system before the collision?

B) What is the momentum of the car-truck system after the collision?

C) How fast do the car and truck move after the collision?

(Do NOT put any links or reproductions, I just need help with this.)​

Answers

A) Before the collision, the total momentum is

(1250 kg) (0 m/s) + (3550 kg) (8.33 m/s) ≈ 29,600 kg•m/s

B) Momentum is conserved, so after the collision it is still approximately 29,600 kg•m/s.

C) If v is the speed of the locked car-truck system, then

(1250 kg) (0 m/s) + (3550 kg) (8.33 m/s) = (1250 kg + 3550 kg) v

Solve for v :

29,571.5 kg•m/s = (4800 kg) v

v ≈ 6.16 m/s

Which is better, forward bias or reverse bias, and why ?!

Answers

Answer:

reverse bias

Explanation:

bcz the potential barrier and impedes the flow of charge carriers. In contrast, a forward bias weakens the potential barrier, thus allowing current to flow more easily across the junction.

A dwarf planet has a mass of 0.0045 times that of the Earth and a diameter on average 0.19 times that of the Earth. What is the escape velocity of the dwarf planet? (Type in the numerical answer and unit, e.g. 10m/s)

Answers

The escape velocity of the dwarf planet is 1,721.8 m/s.

The given parameters:

Mass of the dwarf planet, m = 0.0045 MMass of the Earth = 5.98 x 10²⁴ kgDiameter of the planet, d = 0.19 DDiameter of the Earth, D = 12,742 km

The mass of the of the dwarf planet is calculated as follows;

[tex]m = 0.0045 \times 5.98 \times 10^{24} \ kg\\\\m = 2.69\times 10^{22} \ kg[/tex]

The radius of the dwarf planet is calculated as follows;

[tex]r = \frac{0.19 D}{2} \\\\r = \frac{0.19 \times 12, 742, 000}{2} \\\\r = 1,210,490 \ m[/tex]

The escape velocity of the dwarf planet is calculated as follows;

[tex]v _e = \sqrt{\frac{2GM}{r} } \\\\v_e = \sqrt{\frac{2\times 6.67 \times 10^{-11} \times 2.69 \times 10^{22}}{1,210,490}}\\\\v_e = 1,721.8 \ m/s[/tex]

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objects want to ______ ___________ doing what they're __________ ____________ because they are "lazy." This is called __________.

Answers

Answer:

Explanation:

Objects want to continue doing what they're already doing because they are "lazy." This is called inertia.

a ball of mass 0.15 kg is attached to one end of a string 1.10 m long. the ball moves in a horizontal circle with a speed of 12 m/s. determine the magnitude of the tension in the string​

Answers

Answer:

[tex]19.64N[/tex]

Explanation:

Let's remember that if a mass describes a circle of radius [tex]l[/tex] with a constant speed of [tex]v[/tex], it has an angular velocity [tex]\omega=\frac vl[/tex]. in our case, our angular velocity will be of [tex]12/1.1= 10.91 rad/s[/tex].

Now that same mass will be subject of a centripetal acceleration [tex]a_c[/tex], caused of the tension of the string, equal to [tex]a_c=\omega^2l[/tex], which, in our situation, will be [tex](10.91)^2\times1.1=130.91 m/s^2[/tex]

We're almost done. We got mass, we got acceleration, the tension has to be their product: [tex]T= ma=130.91\times0.15=19.64N[/tex]

What is the unit of pressure
is it P=F/A?

Answers

The SI unit for pressure is the pascal (Pa), equal to one newton per square metre (N/m2, or kg·m−1·s−2). This name for the unit was added in 1971; before that, pressure in SI was expressed simply in newtons per square metre.

Answer:

Units of pressure include: Pa, bar, at, atm, torr, lbf/in^2

Explanation:

P = F/A is a formula for pressure not a unit.

Pa = Pascal

Bar = Bar

at = Technical Atmosphere

Torr = Torr

lbf/in^2 = pounds per square inch

At the end of meiosis II, the new haploid cells in humans are known as which of the following?
Diploid cells
Embryo
Zygotes
Gametes

Answers

Diploid cells. Is the answer

What do these weapon stats mean?

Idle sway control is measured in Fc???

Flinch resistance is measured in N.

Answers

Answer:

its sort of like how Pounds are measured in lbs

Explanation:

Pounds are measured in lbs when they dont sound anything similar, same thing applies to gun technology.

Which ball moved at the same speed as Ball 3?

Answers

Answer:

you forgot to attach the image

The earth has a mass of 5.972 x 1024 Kg. You decide to
put the satellite in an orbit 400 Km above the surface of the earth which has a radius of 6,371 Km, so the total
distance from the center of the earth to the satellite is 6,771,000 m. What will you need the velocity of the
satellite to be to stay in orbit? Show your work

Answers

Answer:

Explanation:

You want the required centripetal force to equal gravity force

if m is the mass of the satellite

ma = mv²/R

a = v²/R

F = ma = GMm/R²

a = GM/R²

v²/R = GM/R²

v² = GM/R

v = √(GM/R)

v = √(6.674 x 10⁻¹¹(5.972 x 10²⁴)/6.771 x 10⁶)

v = 7.672 x 10³ m/s

The following is an example of what type of reaction?

Answers

Answer:

Single Displacement Reaction

Explanation:

Here, only one element is getting replaced during the reaction, that is, silver gets replaced by copper, hence, single displacement reaction.

Hope it helps :)

True or False. Isaac at first resisted his father's command to be the sacrifice.

Answers

False, he never resisted. He lay still, allowing himself to be tied.

PLEASE HELP ASAP
I need help understanding this question, form my guess I’m thinking it’s C but I’m not to sure

Answers

Answer:

Explanation:

Without the diagram, we have to bracket our answers.

Total energy is constant, so we eliminate options A and B.

C is correct if position 1 is closer to the star than position 2

D is correct if position 2 is closer to the star than position 1

How far has a 15 kg object moved, when a force of 22 N is applied for 5 seconds if it started at 3 m/s?

Answers

First start by finding the acceleration experienced by the force. Then use the acceleration and a suvat equation to solve for distance.

Hey guys can you help me solve this problem "how long will it take a car travelling 30m/s to come to stop ifs its acceleration is -3 m/s2".

Answers

Answer:

10 seconds.

Explanation:

We can use a kinematic equation where we know the final velocity, initial velocity, acceleration, and need to determine the time t:

[tex]\displaystyle v_f = v_i + at[/tex]

The initial velocit is 30 m/s, the final velocity is 0 m/s (as we stopped), and the acceleration is -3 m/s².

Substitute and solve for t:

[tex]\displaystyle \begin{aligned} (0\text{ m/s}) & = (30 \text{ m/s}) + (-3 \text{ m/s$^2$}) t \\ \\ t & = \frac{-30\text{ m/s}}{-3 \text{ m/s$^2$}} \\ \\ & = 10 \text{ s} \end{aligned}[/tex]

Hence, it will take the car 10 seconds to come to a stop.

A 2.00 kg rock is dropped from the top of a 30.0 m high building. Calculate the ball’s momentum at the time that it strikes the ground.

Answers

Explanation:

We use the Theorem of conservation of mechanical energy for finding the velocity when it strikes the ground:

Ei = Ef

Ki + Ui = Kf + Uf

Ui = Kf

m g h = 1/2 m v^2

v = sqrt(2gh)

So the momentum will be:

p = mv = m * sqrt(2gh)

You have a pendulum clock made from a uniform rod of mass M and length L pivoting around one end of the rod. Its frequency is 1 radian/sec. The pivot breaks. Though the mass change is negligible, you need to rehang the rod halfway between the old pivot point and the middle of the rod. The new oscillation frequency is:
A. 0.88 rad/sec
B. 1.13 rad/sec
C. 1.07 rad/sec
D. 0.92 rad/sec

Answers

The new oscillation frequency of the pendulum clock is 1.14 rad/s.

     

The given parameters;

Mass of the pendulum, = M Length of the pendulum, = LInitial angular speed, [tex]\omega _i[/tex] = 1 rad/s

The moment of inertia of the rod about the end is given as;

[tex]I_i = \frac{1}{3} ML^2[/tex]

The moment of inertia of the rod between the middle and the end is calculated as;

[tex]I_f = \int\limits^L_{L/2} {r^2\frac{M}{L} } \, dr = \frac{M}{3L} [r^3]^L_{L/2} = \frac{M}{3L} [L^3 - \frac{L^3}{8} ] = \frac{M}{3L} [\frac{7L^3}{8} ]= \frac{7ML^2}{24}[/tex]

Apply the principle of conservation of angular momentum as shown below;

[tex]I _i \omega _i = I _f \omega _f\\\\\frac{ML^2}{3} (1 \ rad/s)= \frac{7ML^2}{24} \times \omega _f\\\\\frac{24 \times ML^2}{3 \times 7 ML^2} (1 \ rad/s)= \omega _f\\\\1.14 \ rad/s = \omega _f[/tex]

Thus, the new oscillation frequency of the pendulum clock is 1.14 rad/s.

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