Answer:
I think it would be 0.1496 but I'm not really sure sorry
__________ refers to the distinctive character of a sound, or the quality that allows one to distinguish it from other sounds of similar pitch and loudness.
What does the Area under a Speed-time graph represent?
A. acceleration
B. average speed
C. deceleration
D. distance travelled
Answer:
d. distance travelled
Explanation:
answer
train travels 1/4of its total distance over half of its time with a constant velocity of 5m/s. calculate the average velocity
Let D be the total distance (say in meters) traveled by the train and T the time (say in seconds) it takes to do so. (Assume the train moves in a straight line in only one direction.) Then the average velocity of the train as it covers this distance is
v (ave) = D/T
We're told the train can traverse a distance of D/4 in a matter of T/2 seconds if it moves at a speed of 5 m/s. This means
D/4 = (5 m/s) (T/2)
⇒ 5 m/s = 1/2 D/T
⇒ v (ave) = D/T = 10 m/s
The smallest possible particle of complete matter is the atom. True or false?
true
false
Answer:
TRUE !!
Explanation:
An atom is the smallest particle of an element
the only two forces acting on a body have magnitudes of 20 n and 35 n and directions that differ by 80. the resulting acceleration has a magnitude of 20 m/s2. what is the mass of the body?
Answer:
the mass of the body is 2.75 kg
place any object (textbook, pen, or eraser) on a floor what happens then
Answer:
The force of gravity on earth, no matter the object is approximately 9.8 m/ s2 . The reason the crumpled paper hits the ground first is because of air resistance. A crumpled piece of paper has less surface area than an piece of paper that is not crumpled. More surface area means more air resistance.
Object 1 has a mass of 7.0kg and a initial velocity of 17.0 m/s. Object 2 has a mass of 8.0kg and a initial velocity of -14.0 m/s. What are the final velocitys of each object. Please show work
[tex]\\ \sf\longmapsto m1v1+m2v2=(m1+m2)v3[/tex]
[tex]\\ \sf\longmapsto 7(17)+8(-14)=(7+8)v3[/tex]
[tex]\\ \sf\longmapsto 119-112=15v3[/tex]
[tex]\\ \sf\longmapsto 15v3=7[/tex]
[tex]\\ \sf\longmapsto v3=7/15[/tex]
[tex]\\ \sf\longmapsto v3=2.1m/s[/tex]
In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg m/s. After the two balls collide, the final momentum of the cue ball is 0.01 kg m/s
Answer: 0.22
Explanation: Subtract 0.01kg from 0.23kg
What effect do shiny metals have on radiant energy?
Answer:
Metals conduct heat and reduce the kinetic energy within the components that need to remain cool
A 5kg ball is on top of the school building at a height of 40m above the ground.
A. calculate the potential energy of the ball at that height.
B. How much power would it take to get the ball from the ground to that height in 1 minute.
C. If it is dropped what type of energy will the ball have as it approaches the ground.
D. What speed will the ball hit the ground
Answer:
A-Caclcuate the potential energy of the ball at that height
Explanation:
(a). Mass of the Body = 10 kg.
Height = 10 m.
Acceleration due to gravity = 9.8 m/s².
Using the Formula,Potential Energy = mgh
= 10 × 9.8 × 10 = 980 J.
(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.
∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.
∴ Kinetic Energy = 980 J.
(c). Kinetic Energy = 980 J.
Mass of the ball = 10 kg.
∵ K.E. = 1/2 × mv²
∴ 980 = 1/2 × 10 × v²
∴ v² = 980/5
⇒ v² = 196
∴ v = 14 m/s.
a q deben los cambios de la materia??
Answer:
wat
Explanation:
can somebody explain it to me please?
Range be R and height be h
[tex]\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}[/tex]
[tex]\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}[/tex]
u=initial velocity
theta is angle of projection.
g=acceleration due to gravity
ATQ
[tex]\\ \sf\longmapsto R=2h[/tex]
[tex]\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}[/tex]
Cancelling required ones
[tex]\\ \sf\longmapsto sin^2\theta=sin2\theta[/tex]
sin2O=2sinOcosO
[tex]\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta [/tex]
[tex]\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2[/tex]
[tex]\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2[/tex]
[tex]\\ \sf\longmapsto tan\theta=2[/tex]
[tex]\\ \sf\longmapsto \theta=tan^{-1}(2)[/tex]
[tex]\\ \sf\longmapsto \theta=63.4°[/tex]
Done
Option B is correct
A horizontal force F~ is applied to a block of mass m = 1 kg placed on an inclined
at θ = 30◦ plane. The coefficients of static and dynamic friction are µs = 0.3 and µ = 0.2, respectively. Find F such that the block is moving up the slope with a constant speed.
Hi there!
To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.
Recall:
[tex]\large\boxed{F_D = \mu N}}[/tex]
The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.
[tex]\large\boxed{N = Mgcos\theta + Fsin\theta}}[/tex]
We can plug in the known values to solve for one part of the normal force:
N = (1)(9.8)(cos30) + F(.5) = 8.49 + .5F
Now, we can plug this into the equation for the dynamic friction force:
Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F
For a block to move with constant speed, the summation of forces must be equivalent to 0 N.
If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:
Fcosθ = 1.697 + .1F
Solve for F:
Fcos(30) - .1F = 1.697
F(cos(30) - .1) = 1.697
F = 2.216 N
A 7.5 kg beaver dives horizontally off a 50 kg log at a speed of 4 m/s. What is the speed of the log?
Answer:
[tex]0.6\; \rm m\cdot s^{-1}[/tex], assuming that drag of the water on the log is negligible.
Explanation:
The momentum [tex]p[/tex] of an object is equal to the product of mass [tex]m[/tex] and velocity [tex]v[/tex]. That is, [tex]p = m\, v[/tex].
If the drag of water on the log is negligible, momentum of the beaver and the log, combined, would be preserved.
The momentum of the beaver and the log, combined, was initially [tex]0\; \rm kg\cdot m \cdot s^{-1}[/tex].
The momentum of the beaver right after the dive would be [tex]7.5 \; {\rm kg} \times 4\; {\rm m \cdot s^{-1}} = 30\; {\rm kg \cdot m \cdot s^{-1}}[/tex].
The sum of the momentum of the beaver and the log is conserved and should continue to be [tex]0\; {\rm kg\cdot m \cdot s^{-1}}[/tex] even after the dive. Since the momentum of the beaver is [tex]30\; {\rm kg \cdot m \cdot s^{-1}[/tex] after the dive, the momentum of the log should become [tex](-30)\; {\rm kg \cdot m \cdot s^{-1}}[/tex].
Since the mass of the log is [tex]50\; {\rm kg}[/tex], the new velocity of this log would be:
[tex]\begin{aligned}v &= \frac{p}{m} \\ &= \frac{(-30)\; {\rm kg \cdot m \cdot s^{-1}}}{50\; {\rm kg}} \\ &= (-0.6)\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].
(The new velocity of the log is negative because the log would be moving away from the beaver.)
The speed of an object is the magnitude of velocity. For this log, a velocity of [tex](-0.6)\; {\rm m \cdot s^{-1}}[/tex] would correspond to a speed of [tex]|(-0.6)\; {\rm m \cdot s^{-1}| = 0.6\; {\rm m \cdot s^{-1}[/tex].
A car accelerates at a constant rate of 3 m/s2 for 5 seconds. If it reaches a velocity of 27 m/s, what was its initial velocity?
A
15 m/s
B
42 m/s
C
12 m/s
D
2.1 m/s
The initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.
CALCULATE INITIAL VELOCITY:
The initial velocity of the car can be calculated by using one of the equation of motion as follows:
V = u + at
Where;
V = final velocity (m/s)u = initial velocity (m/s)a = acceleration due to gravity (m/s²)t = time (s)According to this question, a car accelerates at a constant rate of 3 m/s² for 5 seconds. If it reaches a velocity of 27 m/s, its initial velocity is calculated as follows:
u = v - at
u = 27 - 3(5)
u = 27 - 15
u = 12m/s.
Therefore, the initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.
Learn more about motion at: https://brainly.com/question/974124
A tennis ball is dropped from a height of 3 m and bounces back to a height of
1 m after hitting the ground (s = 0).
Use the equation V^2=U^2 + 2as to calculate the velocity of the tennis
ball when it hits the ground.
The velocity of the tennis ball when it hits the ground is calculated as 4.43m/s. Details about velocity can be found below.
How to calculate velocity?The velocity of a moving object can be calculated using the equation of motion as follows:
v² = u² + 2as
Where;
v = final velocityu = initial velocitya = accelerations = distancev² = 0² + 2(9.8) (1)
v² = 19.6
v = ✓19.6
v = 4.43m/s
Therefore, the velocity of the tennis ball when it hits the ground is calculated as 4.43m/s.
Learn more about velocity at: https://brainly.com/question/18084516
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how is the rate of evporation of a liquid affected by temperature, the surface area of a liquid exposed to air
Which substances are inorganic? Check all that apply.
C6H12O6
K2CO3
C4H10
C27H46O
Fe3O4
The major characteristic an organic compound has which an inorganic
compound doesn't have is the presence of carbon atoms in the molecule.
This helps us to differentiate the compounds into their respective divisions.
Inorganic compounds
K2CO3Fe3O4Organic compounds
C6H12O6C4H10C27H46OWe can observe that inorganic compounds lack carbon atoms which makes
the answer valid.
Read more about inorganic compounds on https://brainly.com/question/2169750
Answer:
B and E because yk thats the asnwer
please help me !! i’ll give you brainliest if you get the answer right!
Answer: 25N to the right
Explanation: 35N - 10N = 25N
A concrete block (B-36 x10 °C-') of volume 100 mat 40°C is cooled to
-10°C. What is the change in volume? *
A. It will increase by 0.18 m
B. It will decrease by 0.18 m'
C.It will increase by 0.05 m
D. It will decrease by 0.05 mº
Applying Charles law
[tex]\\ \sf\Rrightarrow \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
[tex]\\ \sf\Rrightarrow \dfrac{100}{313}=\dfrac{V_2}{263}[/tex]
[tex]\\ \sf\Rrightarrow V_2=\dfrac{26300}{313}[/tex]
[tex]\\ \sf\Rrightarrow V_2=84.02ml[/tex]
Part Two: Criteria, Constraints, and Prioritizations
1. Choose one sub-problem that you will investigate further and explain which one you chose here.
o
2. List two realistic criteria for the sub-problem.
o
o
3. Explain why it is important for these criteria to be met in order to solve the problem.
o
4. List two constraints for the sub-problem.
o
o
5. Explain why these constraints exist. (How do they limit solutions to the problem?)
o
6. Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.
PLEASE HELP ME I DONT UNDERSTAND<333
Answer:
Usually, a solution can have several criteria and constraints. Even though all are important, some criteria are more important than others. The same holds true for constraints. But what do you do if it's impossible for a solution to cover every criterion while avoiding every constraint? In cases like this, you can use prioritization. Listing criteria and constraints based on priority shows the relative importance of each. You will need to prioritize the criteria and constraints for each sub-problem so that you can design a solution for each one individually. Prioritization can help you compare two different possible solutions. For example, the criterion that cars travel at 15 mph through the neighborhood might be a higher priority than the constraint that homeowners are only willing to spend $10,000 on this issue. If this is the case, you would want to generate solutions that also follow the priority in mind. All criteria are important, but engineers must sometimes make a trade-off, which is a compromise or change in one or more criteria or constraints so that they can be met at the same time. This is where prioritization comes in handy as it helps determine the trade-offs. A solution that is doing a better job of meeting one criterion may result in not completely meeting another criterion. Prioritization will help you choose which solution to go with.
Explanation:
I got this from quizlet :)
A 50 kg pitcher throws a baseball with a mass of 0. 15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is no net force on the system, what is the velocity of the pitcher? â’0. 1 m/s â’0. 2 m/s â’0. 7 m/s â’1. 4 m/s.
The velocity of the pitcher at the given mass is 0.1 m/s.
The given parameters:
Mass of the pitcher, m₁ = 50 kgMass of the baseball, m₂ = 0.15 kgVelocity of the ball, u₂ = 35 m/sLet the velocity of the pitcher = u₁
Apply the principle of conservation of linear momentum to determine the velocity of the pitcher as shown below;
m₁u₁ = m₂u₂
[tex]u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{0.15 \times 35}{50} \\\\u_1 = 0.105 \ m/s\\\\u_1 \approx 0.1 \ m/s[/tex]
Thus, the velocity of the pitcher at the given mass is 0.1 m/s.
Learn more about conservation of linear momentum here: https://brainly.com/question/13589460
What force is responsible for how magma flows and rocks stack up on top of one another?
Question 6 options:
Electroweak and Strong
Nuclear
Electromagnetic
Gravitational
Gravitational force is responsible for how magma flows and rocks stack up on top of one another.
Gravitational force is the force hat attracts all objects to the center of the earth. The force of gravity accounts for the fact that when an object is thrown up, it falls back to the earth.The force that is responsible for how magma flows and rocks stack up on top of one another is the gravitational force.Hence, it is the gravitational force that is responsible for how magma flows and rocks stack up on top of one another.
Learn more about gravitational force: https://brainly.com/question/24783651
Select the correct answer
1. Instruments that produce sound are called sources of light.
2. Music has no ability to heal the mental stress.
3. A medium is necessary for sound travel.
4. We hear sounds of frequencies below 20 Hz. O First answer O Second answer O Third answer O Forth answer
Answer:
C or 3
Explanation:
A: no they are called sources of sound. A is incorrect.
B: It does. Many people attest to this. But this is not a property of physics.
C: A media is required is the correct answer.
D: Dogs might. In general we don't.
I would pick C
what is the prmary source of energy inside of the earth
What force is responsible for how magma flows and rocks stack up on top of one another?
Question 6 options:
Electroweak and Strong
Nuclear
Electromagnetic
Gravitational
Gravitational Force
Explanation:-
The magma flows through the gap between the rocks which are stacked up on top of one another.
The gravity attracts the magma to do that.
Also the rocks are stacked because of the gravitational force between them
Hence Option D is correct
Hope it helps
Answer:
pls mark me as brainliest
Explanation:
last one
what is value of 2.37 in sl units
How many kilojoules are in 1,967,256J? Round your answer to the nearest whole number.
Answer:
1,967 kilojoules.
Explanation:
1 kilo = a thousand.
There are 1.967 kilojoules in 1,967,256 joules.
What is law of energy conservation?Energy can neither be created nor destroyed.It is only get transfered from one form to another form.What is the SI unit of energy?Joule is a SI unit of energy.There are 1000 joules in 1 kilojoules .learn more about unit of energy here - https://brainly.com/question/3012083
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how to find initial velocity without acceleration
Answer:
actually you can't find it without acceleration.
you need to use one of these three equations
1- Vf = Vi + at
2- 2ad = Vf^2 - Vi^2
3- d = Vit + 1/2 at^2
what is the necessary condition for the conservation of angular momentum
Answer:
The conservation of momentum of a system is a fundamental principle in classical mechanics. The only condition for this principle being valid is that the system should be an isolated one, i.e. It should not be acted upon by any external force.