a basketball player made 62 out of 80 free throw shots. what percent of the free throws did she make

Answer: Match each equation with an equivalent equation. Some of the answer choices are

not used.

A. 3x + 6 = 4x+7

B. 3(x + 6) = 4x+7

C. 4x + 3x = 7-6

1.9x = 4x +7

2. 3x + 18 = 4x+7

3.3x = 4x + 7

4. 3x1 = 4x

5.7x = 1

A. 3x + 6 = 4x+7 = 3

B. 3(x + 6) = 4x+7 = 2

C. 4x + 3x = 7-6 = 5

1.9x = 4x +7 = 3

3x + 18 = 4x+7 = 2

3.3x = 4x + 7 = 1

3x1 = 4x = not used

5.7x = 1 = not used

So,

3x + 6 = 4x+7 matches with 3

3(x + 6) = 4x+7 matches with 2

4x + 3x = 7-6 matches with 5

1.9x = 4x +7 matches with 3

3x + 18 = 4x+7 matches with 2

3x = 4x + 7 matches with 1

3x1 = 4x is not used

7x = 1 is not used

Step-by-step explanation:

Kimiyo would make $987 in a work week if she sold $4,800 worth of merchandise.

A ratio or value that may be stated as a fraction of 100 is called a percentage. And it is represented by the symbol '%'.

Given:

Kimiyo earns a weekly salary of $675 plus a 6.5% commission on sales at a gift shop.

She sold $4,800 worth of merchandise.

That means,

the commissioned amount = 4800 x 6.5 /100

The commissioned amount = $312

In a week,

Kimiyo's total earning is,

= $675 + $312

= $987

Therefore, $987 is the total salary.

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Answer:11.15

Step-by-step explanation:

sry if its wrong :)

just add them

the opposite sides of the quadrilateral PQRS are equal and parallel and so PQRS is a PARALLELOGRAM.

Option (C) is CORRECT.

A pair of numbers called coordinates are used to locate a point or a form in a two-dimensional plane. The x-coordinate and the y-coordinate are two numbers that define a point's location on a 2D plane.

Given, that the coordinates of the vertices of a  quadrilateral composed in the first quadrant of the coordinate plane are (0,0) (a, b), (a + c, b), and (c, 0).

We are to select the most accurate classification of the quadrilateral.

Let the coordinates of the vertices of the quadrilateral be P(0,0), Q(a, b), R(a + c, b), and S(c, 0).

The lengths of the sides are calculated using the distance formula as follows :

PQ = √(a² + b²)

QR = √(a +c -a)² + (b-b)² = √c² = c

RS =  √(a² + b²)

SP = c

So, the opposite sides are equal in length.

And, the slopes of the sides are calculated as follows :

The slope of PQ(m₁) = (b-0)/(a-0)

The slope of QR(m₂) = (b-b)/(c-a-c) = 0

The slope of RS(m₃) = 0-b/(c-a-c) = 0

The slope of SP(m₄) = (0-0)/(0-c) = 0

So, the slopes of the opposite sides are equal but:

m₁ *m₂ = 0 ≠ -1

m₃ *m₄ = 0 ≠ -1

Therefore, the opposite sides of the quadrilateral PQRS are equal and parallel and so PQRS is a PARALLELOGRAM.

Option (C) is CORRECT.

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The fraction of a pound of granola Marty buys is 3/4.

A fraction is a part of a whole number, value, and variable.

There are proper and improper fractions, including complex fractions.

Proper fractions are those with the numerator less than the denominator. An improper fraction produces a whole number with a remainder when the denominator divides the numerator.

On the other hand, complex fractions are rational expressions that have some fractions in their numerators, denominators, or both.

1 pound = 16 ounces

The quantity of granola Marty buys = 12 ounces

The fraction of a pound of granola Marty buys = 3/4 (12/16)

Thus, we can conclude that Marty buys 3/4 or 75% of a pound of granola.

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The graph with the slope of 2 is the second graph.

The slope of a line is a measure of its steepness. The slope of a line is the change in dependent variable with respect to the change in the independent variable.

Therefore, let's find the slope of the graph to know the one with the slope of 2.

Hence,

slope = y₂ - y₁ / x₂ - x₁

Using the second graph,

(-1, -1)(0, 1)

slope = 1 + 1 / 0 + 1

slope = 2 / 1

slope = 2

Therefore, the graph with slope of 2 is the second graph.

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The notion of an equation in algebra is a statistical statement that demonstrates the equality of two mathematical expressions.

For the stated question;

365 days are included in a year.

There are 256 days a year on average when it is foggy.

Determine the approximate number of clear days by using the formula:

We round the figures.

To the nearest tens, 365 days

= 370 days

The nearest tenth of 256 days

= 260 days

370 - 260 days, then

= 110 days

The precise number of days without fog is =

= 365 − 256

= 109

Thus, the precise number of days without fog is found as 109 days.

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The complete question is -

Solve the problem by using​ addition, subtraction,​ multiplication, or division. First use front end rounding to estimate the answer. Then find the exact answer. The foggiest place in a certain country is City A. It is foggy there an average of 256days each year. How many days is it not foggy each​ year? Find the estimated and the exact number of days.

There are 2187 combinations to select 7 cookies from a bakery that sells cookies of 3 different flavors (oatmeal, chocolate chip, almond).

When selecting 7 cookies from a bakery that sells 3 different flavors, each cookie selected can be one of the 3 different flavors. This means that for the first cookie, there are 3 choices, for the second cookie, there are also 3 choices, and so on for the 7th cookie. This is known as the combinations formula and it can be represented as 3 x 3 x 3 x ... x 3 (3 being repeated 7 times).

Using the 3⁷ formula, we can calculate that there are 2187 ways to select 7 cookies from a bakery that sells cookies of 3 different flavors. This means that there are 2187 unique combinations of cookies that can be selected, assuming that more than 7 cookies are available for each flavor.

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Your question seems incomplete, but I assume the question was:

"How many ways can you select 7 cookies to buy from a bakery that sells cookies of 3 different flavors (oatmeal, chocolate chip, almond)? We assume that more than 7 cookies are displayed for each flavor. For example, one way is to choose 7 chocolate chip cookies."

The equation of the regression line is Y=2.83+0.52x .

Linear regression is the statistical technique that is most frequently used to simulate a relationship between two sets of variables. As a result, a data-applicable linear regression equation is produced.

Plotted your points and drew a linear regression line.

y = a + bₐₓx

bₐₓ = n∑xy-∑x-∑y

        n∑x²- ∑x²

x = 8.81

y = 7.45

∑x² = 947

∑xy=770.95

bₐₓ = 0.52

a = 2.83

y=1.3082X + 3.3436.

Its equation is

y = 2.83+0.52x .

Therefore, the regression line in a scatter plot ignores non-linear properties, so the equation of the reggresion line will be y = 2.83+0.52x .

Your question is incomplete but most probably your full question was

Use the given data to find the equation of the regression line. Examine the scatterplot and identify a characteristic of the data that is ignored by the regression line.

x y

9 7.38

9 6.75

12 13.08

9 7.42

11 7.56

13 8.53

7 5.93

4 5.33

12 8.1

6 6.46

5 5.44

Required:

Create a scatterplot of the data.

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Using the Central Limit Theorem, it is found that the correct option is: C  

For all samples of size 400 from this population, the mean of all resulting sample proportions of cell phone screens with a screen defect is 0.05.

By the Central Limit Theorem, for a proportion p in a sample of size n, the mean of the sampling distribution of sample proportions is u=5, while the standard error is [tex]SE=\sqrt{\frac{p*(1-p)}{n} }[/tex]

In this problem, the mean of the sampling distribution of sample proportions is 0.05, that is, the mean proportion of all samples, hence, the correct option is C.

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Answer:4x

Step-by-step explanation:

We can conclude that -

        Q = 5(280 - P)

Given is a story of Dr. Leona Williams who is a well-known plastic surgeon.

{ 1 } -

Dr. Williams estimated demand for her work is -

Q = 280 - 0.2P

Inverse of a function can be calculated by following the steps mentioned below -

So, we can write -

P = 280 - 0.2Q

P - 280 = - 0.2Q

- (280 - P) = - 0.2Q

(280 - P) = 0.2Q

Q = (280 - P)/0.2

Q = 5(280 - P)

{ 2 } -

The average variable cost function for reconstructive nose surgery is -

AVC = 2Q² – 15Q + 400

Let AVC = A{Q}

For maximum profit -

d/dQ (A{Q}) = 0

d/dQ (2Q² – 15Q + 400) = 0

d/dQ (2Q²) - d/dQ (15Q) + d/dQ (400) = 0

4Q - 15 = 0

4Q = 15

4Q = 15

Q = 3.7

Q = 4 {approx.}

Therefore, we can conclude that -

        Q = 5(280 - P)

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The value of h in the algebraic equation in fraction 11/12 = 3/4h is equal to 9/11

We shall first find the lowest common multiple LCM of the denominators to help us clear the fractions, before then simplifying further for the value of h as follows:

LCM of the denominators 12 and 4h is 12h

multiply both sides by the LCM

11/12 × 12h = 3/4h × 12h

11 × h = 3 × 3

11h = 9

divide both sides by the coefficient of h

11h/11 = 9/11

h = 9/11

Therefore, the value of h in the algebraic equation in fraction 11/12 = 3/4h is equal to 9/11.

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Answer:

A(3) = 13

A(4) = 18

A(10) = 48

Step-by-step explanation:

This seems like a plug and play.

Starting with A(3). Everywhere you see an n, you'll replace it with a 3, as follows;

3 + (3-1)(5) = ?

We'll solve it step by step. First is 3-1. That's 2, bringing it to

3 + (2)(5).

2 times 5 is 10, bringing it to

3 + 10.

3 + 10 = 13, which concludes

A(3) = 13.

Now doing it for the remaining 2.

3 + (4-1)(5)

3 + (3)(5)

3 + 15

A(4) = 18

Last one...

3 + (10-1)(5)

3 + (9)(5)

3 + 45

A(10) = 48

Answer:

slope = 4

Step-by-step explanation:

Answer:

=

Step-by-step explanation: Please mark brainliest

Substitute 3 in for m and solve

4m - 1 = 4(3) - 1 = 11

5m - 4 = 5(3) - 4 = 11

Answer:

Step-by-step explanation:

P&R3 model and solve

problems using linear

equations of the form:

ax = b *

x

a

= b, a ≠ 0*

ax + b = c *

x

a

+ b = c ,a ≠ 0*

a x( ) + b = c *

ax + b = cx + d *

* a bx ( ) + c = d ex ( ) + f

*where a, b, c, d, e, and f [C,

CN, PS, V]

1. Introduction to Solving Linear Equations (pg. 4-7)

• Model the solution of a given linear equation using concrete or

pictorial representations, and record the process.

Algebra stones and Algebra Tiles.

Solve x + 5 = 10 , x − 7 = 10 , 2x = 10 , x

3 = 10

2. Solving equations of the form ax+b=c and a/c +b=c (pg. 8-10)

• Solve a given linear equation symbolically.

• Solve a given problem using a linear equation and record the

process.

Solve. 4m+3=31 & 2

5

m − 5 = 3

3. Solving equations of the form a(x+b)=c and ax+b=cx+d(pg. 11-14)

• Determine, by substitution, whether a given rational number is a

solution to a given linear equation.

Solve. 4(m+3)=40 & 6m+3=2m+15

Is m=5 a solution to the equation 2(m + 2) = 14 ?

4. More practice with ax+b=cx+d (Pg. 15-18)

• Identify and correct an error in a given incorrect solution of a

linear equation

Solve. 2(m+1)+4m=4(m-2)+6.

5. Solve equation with fractions. (Pg. 19-23)

• Solve a given linear equation symbolically. Solve m

3 + 2m

5 − 1

2

= 2

6. Solve Linear equations without numbers. (Pg. 24-28)

• Solve a given linear equation symbolically.

Solve for m. )( =+ BnmA

P&R4 explain and illustrate

strategies to solve single

variable linear inequalities with

rational coefficients

within a problem-solving

context.

7. Introduction to linear inequalities (Pg. 29-33)

• Translate a given problem into a single variable linear inequality

using the symbols ≥, >, < , or ≤ .

• Determine if a given rational number is a possible solution of a

given linear inequality.

Write an expression to represent the following

statement: Melanie needs at least $280 for snow

boarding.

8. Inequalities that Include Addition and Subtraction (Pg. 34-37)

• Generalize and apply a rule for subtracting a positive or

negative number to determine the solution of a given inequality.

• Generalize and apply a rule for multiplying or dividing by a

positive or negative number to determine the solution of a given

inequality.

• Solve a given linear inequality algebraically and explain the

process orally or in written form.

• Verify the solution of a given linear inequality using

substitution for multiple elements in the solution.

Solve 2x + 5 < 25 and verify your solution.

True or False.

If −2x > −10 then x > 5 .

9. Solving Problems with Linear Inequalities (Pg. 38-41)

• Compare and explain the process for solving a given linear

equation to the process for solving a given linear inequality.

• Graph the solution of a given linear inequality on a number line.

• Compare and explain the solution of a given linear equation to

the solution of a given linear inequality.

• Solve a given problem involving a single variable linear

inequality and graph the solution.

Vertical Wireless charges $50/ month plus $0.25 for

all minutes above 400 minutes per month. Frue Gal has

decided that she does not want to pay more than $70

per month. Write an inequality to represent how many

minutes she can use per month without going over her

$70 limit. Approximate your solution on the number

line

10. Chapter Review and Practice Test

• Help students develop sound study habits.

• Many students will graduate high school saying they do not

know how to study for math tests.

11. Go over Practice Test

12. Unit Evaluation

Since it has no impact on the result or solution of the problem, assuming that a > d does not reduce the generality of the statement. If a > d, the issue can be solved by simply swapping the values of a and d.

It makes no difference to the problem whether an is more or less than d because we are presuming that each integer is distinct. Furthermore, by supposing that a > d, the problem's variables can be arranged consistently, making it simpler to comprehend and resolve. As a result, making the assumption that a > d does not reduce the generality of the solution because the problem remains the same and the assumption may be readily changed if necessary.

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Answer:

A. 881

C. 353

Step-by-step explanation:

In order to form 8 lines with each line having equal length, the total number of members has to be divisible by 8:

440/8 = 55, so 440 isn't the answer

224/8 = 28, so 224 isn't the answer

881/8 = 110.125. In addition, even numbers can't be divided evenly by odd numbers like 881, so A. 881 is the answer.

Same goes to 353 since 353 is also an odd number that can't evenly divide the even number 8. Hence, C. 353 is the answer as well.

The required number is 42 which gives a result of −4 when 11 is subtracted from the quotient of the number and 5.

A quotient is defined as the outcome of dividing an integer by any divisor that can be said to be a quotient. The dividend contains the divisor a specific number of times.

Let n be the number in question; then, we can write the word problem as an equation like this:

⇒ (n/6) - 11 = -4

Add 11 on both sides of the equation,

⇒ (n/6) - 11 + 11 = 11 - 4

⇒ (n/6) = 7

Multiply by 6 on both sides of the above equation, and we get

⇒ n = 42

Hence, the number is 42.

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Answer:

0.55 times 20.1 is equal to 11.055

Step-by-step explanation:

To show work, we can simply multiply 0.55 by 20.1 using long multiplication.

0.55

20.1

0.55

+11.05

11.055

So 0.55 times 20.1 is equal to 11.055

So, the possible fourth corners are (4,4) and (-2,2).

Given the three vertices of a parallelogram (1,1), (4,2), and (1,3), we can use vector algebra to find the fourth corner. We know that opposite sides of a parallelogram are parallel, and therefore have the same vector direction. We can use this property to find the vector pointing from one corner to another and then use this vector to find the fourth corner.

One possible method is:

Another possible method is:

So, the possible fourth corners are (4,4) and (-2,2).

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The value of z in the given linear equation in one variable is -1.

By equating it to zero, a linear polynomial over a field, from which the coefficients are extracted, can be converted into a linear equation.

The values that, when employed as stand-ins for the unknowns in such an equation, lead to the equality being true are the solutions.

When there is just one variable, there is just one solution. The term "linear equation" is generally understood to relate to this particular circumstance, when the variable is accurately referred to as the "unknown."

It is possible to interpret each solution as the Cartesian coordinates of a specific point on the Euclidean plane when there are only two variables.

-6z -18z + 2z +6z = 16

-16z = 16

z = -1

Hence, the value of z is -1

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a) The z-score for a structure costing $2,300 is given as follows: -0.67.

b) The z-score for a structure costing $4,900 is given as follows: 1.5.

c) The interpretation of each z-score is given as follows:

d) The structure would have an unusual price, as the z-score has an absolute value greater than 2.

The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation for this problem are given as follows:

[tex]\mu = 3100, \sigma = 1200[/tex]

For item a, the z-score is then given as follows:

Z = (2300 - 3100)/1200

Z = -0.67.

For item b, the z-score is then given as follows:

Z = (4900 - 3100)/1200

Z = 1.5.

For the price of $13,000, the z-score is given as follows:

Z = (13000 - 3100)/1200

Z = 8.25.

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The area under the normal curve with a mean of 20 and a standard deviation of 5 is 0.8413 when x = 25.

The area under the normal distribution curve is calculated using the z-score, which is the number of standard deviations a value is from the mean. To calculate the area under the normal curve for a given mean and standard deviation, one must use the formula:

Area = ½[1 + erf(z)]

Where erf is the Gaussian error function, and z is the z-score.

To calculate the area under the curve given a boundary x, the z-score must be calculated first. This is done using the formula:

z = (x - mean) / standard deviation

Substituting this into the formula above gives:

Area = ½[1 + erf((x - mean) / standard deviation)]

For example, if the mean is 20 and the standard deviation is 5, and the boundary value is x = 25, the area under the normal curve is calculated as follows:

z = (25 - 20) / 5 = 1

Area = ½[1 + erf(1)] = 0.8413

Therefore, the area under the normal curve with a mean of 20 and a standard deviation of 5 is 0.8413 when x = 25.

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c=170/30 is the equation that represents the number of calories,c, burned per min.

A division is a process of splitting a specific amount into equal parts.

Given that Tarmu run 30 min and burned 170 calories

We need to find the equation that represents the number of calories, c, burned per min.

To find the calories burned in each minute we have to divide one hundred seventy by thirty.

c=170/30

c=5.66 cal/min

Hence, c=170/30 is the equation that represents the number of calories,c, burned per min.

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