The pressure at the bottom of the water layer is 1.22 x 10⁵ Pa
The fluid's weight divided by the surface area gives an estimate of the pressure that the fluid exerts on its surroundings. The density of the fluid can be calculated by multiplying its mass by the acceleration caused by gravity. In this case, we are given that:
Depth of oil (h oil) = 80 cm = 0.8 m
Depth of water (h water) = 140 cm = 1.4 m
Density of water (ρ water) = 1000 kg/m³
Density of oil (ρ oil) = 881 kg/m³
The Standard Atmospheric Pressure (P) = 101325 Pa = 1.01 x 10⁵ Pa
To calculate the pressure due to the weight of liquid, we can use this following formula:
P= ρ g h
Where:
P = pressure
ρ = density of liquid
g = acceleration due to gravity
H = depth of the liquid
To calculate the absolute pressure at the bottom of the water layer, we use:
P(absolute)= P x [ρ(water) × h(water)× g] + [ ρ(oil) × h(oil)× g]
P(absolute) = 1.01 x10⁵ + (1000 x 1.4 x 9.8) + (881 x 0.8 x 9.8)
P(absolute) = 1.01 x10⁵ + 0.21 x 10⁵
P(absolute) = 1.22 x 10⁵ Pa
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if the kinetic energy of the electron is 1.6 x 10-17 j and if the electron is to stop just as it reaches the plate, how far from the plate must the launch point be
The distance from the launch point to the plate is x = 0/v = 0/√3.5 x 10-15 = 0, meaning that the launch point must be at the same point as the plate.
What is kinetic energy?Kinetic energy is the energy of motion. It is the energy associated with the movement of an object or particle, and is defined as the work needed to accelerate the object to its current velocity. Kinetic energy is a form of energy that is always associated with the movement of an object, regardless of its speed or direction. It is calculated by multiplying the mass of the object by the square of its velocity. Kinetic energy exists in both living and non-living objects, and is a key factor in the behavior of these objects.
The distance between the launch point and the plate can be determined using the formula for kinetic energy, which is E = ½mv². To solve for the distance, we rearrange the equation to v² = 2E/m and then plug in the given values: v² = 2(1.6 x 10-17)/(9.11 x 10-31) = 3.5 x 10-15. Then, using the equation x = vt, we solve for the distance x, where t is the time it takes for the electron to reach the plate. Since the electron needs to come to a complete stop, we set the velocity equal to zero. Thus, the distance from the launch point to the plate is x = 0/v = 0/√3.5 x 10-15 = 0, meaning that the launch point must be at the same point as the plate.
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if a second object b with the same charge as a is placed at 0.250 m south of a (so that objects a and b and point p follow a straight line), what is the magnitude of the total electric field produced by the two objects at p?
The magnitude of the total electric field produced by the two objects at point p is 4*k*qa/0.25 m^2.
What is electric field?Electric field is a physical quantity used to describe the strength and direction of an electric force on a charged particle. It is a vector field, meaning that it has both a magnitude and a direction associated with it.
The total electric field at point p is the vector sum of the electric fields produced by object a and object b.
The electric field produced by each object at point p is given by:
E = k*q/r^2
where k is the Coulomb constant, q is the charge of the object, and r is the distance from the object to point p.
Therefore, the electric field produced by object a is:
Ea = k*qa/ra^2
And the electric field produced by object b is:
Eb = k*qb/rb^2
Since the charges of a and b are the same, we can use the same value for qa and qb. We can also use the same value for k.
Therefore, the total electric field at point p is:
E = Ea + Eb = k*qa/ra^2 + k*qb/rb^2
Substituting in the values given in the question:
E = k*qa/(0.250 m)^2 + k*qa/(0.500 m)^2
Simplifying gives:
E = 4*k*qa/0.25 m^2
Therefore, the magnitude of the total electric field produced by the two objects at point p is: E = 4*k*qa/0.25 m^2.
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A moving electron has kinetic energy K1 After a net amount of work W has been done on it, the electron is moving one-quarter as fast in the opposite direction. Find W in terms of K1
The final kinetic energy of the electron is K2 = K1/4 since it is moving one-quarter as fast. The work done on the electron can be found using the equation W = K2 - K1 = K1/4 - K1 = -3/4K1. So, W=-3/4K1
How does the velocity of an object affect its kinetic energy?
The velocity of an object is directly proportional to its kinetic energy. As the velocity of an object increases, so does its kinetic energy. This relationship is described by the equation K = 1/2 * m * v^2, where K is the kinetic energy, m is the mass of the object and v is its velocity. This equation shows that the kinetic energy of an object is proportional to the square of its velocity. This means that if the velocity of an object is doubled, its kinetic energy will increase by a factor of four. Conversely, if the velocity of an object is halved, its kinetic energy will decrease by a factor of four.
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After a net amount of work W has been done on it, the electron is moving one-quarter as fast in the opposite direction W in terms of K1 = W= -3/4K1
Evaluating :The final kinetic energy of the electron is K2 = K1/4 since it is moving one-quarter as fast.
The work done on the electron can be found using the equation
W = K2 - K1
= K1/4 - K1
= -3/4K1.
So, W= -3/4K1
How does the velocity of an object affect its kinetic energy?The velocity of an object is directly proportional to its kinetic energy. As the velocity of an object increases, so does its kinetic energy. This relationship is described by the equation K = 1/2 × m × v², where K is the kinetic energy, m is the mass of the object and v is its velocity.
This equation shows that the kinetic energy of an object is proportional to the square of its velocity. This means that if the velocity of an object is doubled, its kinetic energy will increase by a factor of four. Conversely, if the velocity of an object is halved, its kinetic energy will decrease by a factor of four.
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a boat can move at 30 km/h in still water. how long will it take to move 12 km upstream in a river flowing 6.0 km/h?
A boat can move at 30 km/h in still water, so to move 12 km upstream in a river flowing 6.0 km/h, it will take 20 minutes.
Water is referred to as still water when its motion is zero, or when it is still. Motionless water is defined as water that remains still, not flowing, and has no current, such as in rivers and streams. Therefore, a boat's relative speed on calm water is equal to 12 (a + b) km/hr. The stream is moving at a pace of 1/2 (a - b) km/hr.
Moving upstream, or against the flow of water, refers to a boat going against the current. The distinction when speaking about water in rivers and streams is that upstream is in opposition to the water flow and in the direction of the water's original source (where the river originates).
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A lightbulb has a power of 12 W. It has an efficiency of 80%.
Calculate the amount of time taken in seconds for the bulb to transfer 300 J of energy
into light energy.
The amount of time taken in seconds for the bulb to transfer 300 J of energy into light energy is 37.5 seconds. (300 J / ( 12 W * 0.8))
How does the efficiency of a lightbulb affect the amount of energy it transfers into light energy?The efficiency of a lightbulb is a measure of how much of the energy it consumes is converted into light energy, and how much is wasted as heat. A lightbulb with a higher efficiency will convert a greater proportion of the energy it consumes into light energy, and will therefore produce more light for the same amount of energy consumed. Conversely, a lightbulb with a lower efficiency will convert a smaller proportion of the energy it consumes into light energy, and will therefore produce less light for the same amount of energy consumed. The efficiency of a lightbulb is usually represented as a percentage, with 100% indicating that all the energy consumed is converted into light energy, and 0% indicating that none of the energy consumed is converted into light energy.
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The amount of time taken in seconds for the bulb to transfer 300 J of energy into light energy is 37.5 seconds.
Evaluating :Power = 12W
Efficiency = 80%
Energy = 300 J
Time taken = (300 J / ( 12 W * 0.8))
= 37.5 seconds
Electric light bulb :The efficiency of a lightbulb is a measure of how much of the energy it consumes is converted into light energy, and how much is wasted as heat. A lightbulb with a higher efficiency will convert a greater proportion of the energy it consumes into light energy, and will therefore produce more light for the same amount of energy consumed.
Conversely, a lightbulb with a lower efficiency will convert a smaller proportion of the energy it consumes into light energy, and will therefore produce less light for the same amount of energy consumed. The efficiency of a lightbulb is usually represented as a percentage, with 100% indicating that all the energy consumed is converted into light energy, and 0% indicating that none of the energy consumed is converted into light energy.
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Sc 1.1 Two forces act on an object. The first is a horizontal 50 N force. The second is a 40 N force acting at an angle to the horizontal. Use a graphical method drawn to a scale of 1 mm : 1 N to find the resultant if the 40 N force is inclined at: 1.1.1 30° to the horizontal 1.1.2 60° to the horizontal.
1.1.1: The force, which is 61.4 N and inclined at a 34.4° angle to the horizontal,
1.1.2: The resultant force is 30.8° inclined to the horizontal and is 66.9 N in magnitude.
How does vector addition work?
The process of adding vectors together to determine the resulting force is known as vector addition.
Vector addition is the theory that was applied in this question
The steps involved in adding vectors are as follows:
First, use the two provided vectors and the resulting vector to scale up a vector diagram.
Step 2: Apply the Pythagorean theorem to determine the magnitude of each vector.
Calculate each vector's angle with respect to the horizontal in step three.
4th step: Apply the Use the law of cosines to find the magnitude of the resultant vector
Step 5: Use the law of sines to find the angle of the resultant vector with respect to the horizontal.
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for each of the following cases, indicate whether the work done is positive or negative. explain your answers. a) work done by an applied force in lifting a bucket of water upward. fa mg b) work done by the weight of the bucket c) work done by the applied force and mg if the bucket were lowered.
The work done in case a) is positive, in case b) is negative and in case c) is positive.
Work is said to be done when the displacement is occur in the direction of the applied force.
W = F×d×cosθ
Where F is the force, d is the displacement and θ is the angle between the displacement and the direction of the force.
In case a) as the work is done against the direction of the gravity so the work is positive. In case b) the weight of the buckets acts in downwards direction, that is the direction of the acceleration due to gravity. So the work is negative. In case c) the bucket were lowered, it means the displacement is in the direction of the applied force. Hence the work done is positive.
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2: A community is concerned about a plan to bring train service to their downtown from the
town's outskirts. The current sound intensity level, even though the rail yard is blocks away, is
70 dB downtown. The mayor assures the public that there will be a difference of only 30 dB in
sound in the downtown area. Should the townspeople be concerned?
Despite being several streets away from the rail yard, the current downtown noise level is 70 dB. The people is given assurances by the mayor that they will see a difference.
What is the sound's amplitude?The power carried via sound per unit area inside a perpendicular direction to the that region is known as sound intensity or acoustic intensity. A watt every square meter (W/m2) is indeed the SI unit for intensity, which also covers sound intensity.
How do you determine the amount of sound intensity?The following equation can be used to calculate sound intensity: I=Δp22ρvw. p stands for pressure change or amplitude. is the density of the substance through which the sound is moving, and vw is the sound's measured speed. The more intense the acoustic waves oscillation, the bigger.
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jason drives due west with a speed of 35.0 mi/hr for 30.0 min, continues in the same direction with a speed if 60.0 mi/h for 2.00 h, and then drives still farther west at 25.0 mi/h for 10 min. what is jason's average velocity for the entire trip? (units of mi/h)\
The average velocity is 47.96 mi/h with which Jason can drive
on average.
Well, there are many ways to calculate the average velocity, but the most complete one would be the following.
With the equations of Uniform Rectelinear Movement we can obtain the distance Jason has driven. We will use the same equation for each step.
where x is the position, is the initial position (which we can pick as zero to simplify), v is the velocity, t is time and is the initial time (also picked as zero). In order to get the right answer we must use the same units, so we will change the minutes to hours, where 30 minutes are half an hour and 12 minutes are 0.2 hours
So, the distance will be Now that we have the partial distances, we use the formula for average velocity which is where is the final position (the sum of the distances) and is the total time Jason took.
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Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1. 40 cm. If the potential difference across the plates was 28. 5 kV, find the magnitude of the electric field (in V/m) in the region between the plates
The magnitude of the electric field (in V/m) in the region between the plates is 20.35x10^5V/m.
Given the distance between the plates (d) = 1.4cm = 1.4x10^-2m
The potential difference across the plates is (V) = 28.5kV = 28.5x10^3V
The electric field between two parallel conducting plates is dependent on the voltage or potential difference between the two plates as well as their separation from one another. The two charged parallel plates would carry their total charges since an electric insulator separates them. Because the two parallel charged plates are kept apart from one another, a homogenous electric field is created there.
According to Coulombs law E = V/d such that
E = 28.5x10^3V/1.4x10^-2m = 20.35x10^5V/m
Hence the required magnitude of the electric field is 20.35x10^5V/m
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A bob of mass m is suspended from a fixed point with a massless string of length L (i. E. , it is a pendulum). You are to investigate the motion in which the string moves in a cone with half-angle θ. What tangential speed, v, must the bob have so that it moves in a horizontal circle with the string always maintaining an angle θ from the vertical? Express your answer in terms of some or all of the variables m, L, and θ and the acceleration due to gravity, g
The tangential speed, v, must the bob have so that it moves in a horizontal circle with the string always maintaining an angle θ from the vertical is √mgLsinθtanθ.
Given the mass of bob = m
length of string = L
The angle the string of pendulum makes with cone = θ
The tangential speed the bob moves = v
the vertical component of tension must support the weight of the bob which is represented as: Tcosθ = mg where g is acceleration due to gravity.
the horizontal component of tension must equal the centripetal force acting on the bob which is: Tsinθ = v^2/r where r is the radius of orbit.
However, we know that, r = Lsin(θ) then Tsinθ = v^2/Lsin(θ)
Then Tsinθ/Tcosθ = v^2/(mg x Lsin(θ))
tanθ = v^2/mgLsinθ
then v = √mgLsinθtanθ
Hence the tangential speed the bob moves with is √mgLsinθtanθ
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4. 77 Augment the rectifier circuit of Problem 4. 70 with a capacitor chosen to provide a peak-to-peak ripple voltage of (i) 10% of the peak output and (ii) 1% of the peak output. In each case: (a) What average output voltage results? (b) What fraction of the cycle does the diode conduct? (c) What is the average diode current? (d) What is the peak diode current?
You may calculate the average load current—the average diode current—by dividing the average load voltage by the average load resistance.
What is the diode's typical forward current?Vavg = 15.45 V
Diode conduction is 7.11 percent.
Iavg = 0.232 A
Ip = 0.449 A
Case (ii) (ii)
Vavg = 16.18 V
Diode conduction is 2.25 percent.
Iavg = 0.735 A
Ip = 1.453 A
The transformer's secondary side has a voltage of
= Vpri/turn ratio
Vrms = 120/10 = 12 V
Peak voltage and rms voltage have the following relationship:
Vp = Vrms / 2.
Vp = 12√2 = 16.97 V
Vd = 0.7 V
We will first determine all the necessary variables for the ripple voltage of 10%, and then for the ripple voltage of 1%.
10% of the highest output in scenario I
What average output voltage is produced?
Vavg = Vp - Vd - 0.5Vr is the average output voltage.
Vp is the maximum output voltage.
Diode voltage drop is denoted by Vd, while ripple voltage is denoted by Vr, which is expressed as a percentage of Vp.
Vavg = 0.5Vr + Vp - Vd
Vavg = 16.97 - 0.7 - 0.5[0.1(16.97 - 0.7)]
Vavg = 15.45 V
(b) The diode conducts what percentage of the cycle?
= Vd - 2Vr/Vp
Vp- Vd = 2*0.1 (Vp-Vd)/Vp
ω = √2*0.1(16.97-0.7)/16.97 - 0.7
ω = 0.447 rad
Diode conductance equals (/2)*100
Diode conductance is (0.447/2)*100
Diode conduction is 7.11 percent.
The typical diode current is (c).
Iavg = Vavg/R[1 + (2(Vp - Vd)/0.1(Vp-Vd))] is the formula for average current.
Average current is equal to Iavg, which is 15.45/1000[1 + (2(16.97 - 0.7)/0.1(16.97-0.7)]
Iavg, or average current, is 0.232 A.
(d) How much diode current peaks at?
Peak current is defined as Ip = Vavg/R[1 + 2(2(Vp - Vd)/0.1(Vp-Vd)]
Peak current is expressed as Ip = 15.45/1000[1 + 2](2(16.97 - 0.7)/0.1(16.97-0.7)]
Peak current is 0.449 A, or Ip.
What average output voltage is produced?
Vavg = 16.97 - 0.7 - 0.5[0.01(16.97 - 0.7)]
Vavg = 16.18 V
(b) The diode conducts what percentage of the cycle?
Vp - Vd = 2*0.01(Vp-Vd)
ω = √2*0.01(16.97-0.7)/16.97 - 0.7
ω = 0.1417 rad
Diode conductance is (0.1417/2)*100
Diode conduction is 2.25 percent.
The typical diode current is (c).
Average current is equal to Iavg, which is 16.18/1000[1 + (2(16.97 - 0.7)/0.01(16.97-0.7)]].
Average current is 0.735 A (Iavg).
(d) How much diode current peaks at?
Peak current is expressed as Ip = 16.18/1000[1 + 2](2(16.97 - 0.7)/0.01(16.97-0.7)]
Peak current is 1.453 A, or Ip.
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A 68.5 kg rocket is to be launched upwards with an acceleration of 3.65 m/s^2. What is the size of the gravitational force acting on the rocket?
Answer:
671,3 Newtons
Explanation:
Fg=mass×g
Please help me by 8:30 thank you!!
The statement which correctly describes the all of these given blood cell types is option C. They perform functions that air in maintaining homeostasis.
What is homeostasis ?Any self-regulating mechanism called homeostasis helps biological systems to maintain stability while responding to environmental factors that are best for survival. If homeostasis is achieved, life goes on; if it is not, catastrophe or death result.
The stability obtained is actually a dynamic equilibrium, where circumstances are mostly uniform yet change is constant. All the bodily systems must be in a condition of equilibrium for the body to live and work properly.
When the body is in homeostasis, its levels of acid, blood pressure, blood sugar, electrolytes, energy, hormones, oxygen, proteins, and temperature are maintained at a normal level by being continually adjusted in response to changes both inside and outside the body. Hence, option C is correct.
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you are traveling west on the highway. At 1:00 you pass kilometer marker 485. At 4:30 you pass kilometer marker 154. What has your average velocity been.
Technically a question for physical science but i didn't know what to label it.
Your average velocity for the journey has been 94.57 km/h.
What is the average velocity of an object?The average velocity of an object is the ratio of total displacement to the total time of motion of an object.
V = ( total displacement ) / ( total time )
The total displacement of your journey is calculated as;
x = 485 km - 154 km
x = 331 km
The total time of the motion is calculated as;
t = 4:30 - 1:00 = 3:30 = 3.5 hours
v = x / t
v = ( 331 km ) / ( 3.5 hr )
v = 94.57 km/h
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CAR A is travelling at 27 meters/second and is following closely behind CARB at a distance of 9 meters. The driver of CAR A
has a reaction time of 0. 5 seconds (the time it takes between seeing the brake lights of CAR B flash and the driver of CARA
hitting the brake).
How far will his car travel during the reaction time?
Will the driver of CAR A hit the driver of CAR B during the time it takes the driver of CAR A to react?
How do you know? Explain your evidence, reasoning, and any calculations you may have performed.
The car A will hit the car B during the reaction time of 0.5 seconds, and the distance the car will travel during the reaction time is 13.5 meters.
Reaction time is the time taken by the driver between seeing the scenario in front of his/her eye and the instant of applying the break. It is derived by the PIEV theory. The PIEV theory includes the time durations which drivers see, recognize, analyze and react to apply the brake for avoiding objects on the roads. The PIEV time on highway design engineering is taken as 2.5 seconds.
Given the speed of the car A is 27 m/s
Reaction time = 0.5 sec
Distance travelled, d = 27 × 0.5 = 13.5 meters
As the distance travelled by the car A is more than the distance between car A and car B, so the car will surely hit the car B.
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Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant​ criteria?
No, it doesn't seem like the distribution is normal. A data set must (when graphed) follow a bell-shaped, symmetrical curve that is centered around the mean in order to be regarded as having a normal distribution.
The best way to determine whether a frequency distribution looks to have a normal distribution is to look at a histogram. Plot a histogram and study the bar shapes. The distribution is generally regularly distributed if the bars have the shape of a bell or a hill, as in the figure below. A theoretical continuous, symmetrical bell-shaped distribution function represents a normal frequency distribution. The bell curve's mean, mode, and median are all the same, and both of its tails are indefinitely long.
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complete question: Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant criteria. Temperature (degreesF) 35 - 39, 40 - 44, 45 - 49, 50 - 54, 55 - 59, 60 - 64, 65 - 9 frequency 3, 0, 6, 12, 8, 6, 1.
(a) No, the distribution does not appear to be normal.
(b) Yes, all the requirements are met.
(c) No, the frequencies do not decrease from the maximum frequency to a low frequency.
50) at the taking of a direct free kick, the ball accidentally bounces off the referee and enters the goal. what decision should the referee make?
A dropped ball is given if the ball hits the referee or another match official and goes into the goal, team possession changes, or a potential attack or a promising offensive begins.
The note of the following additional modifications to the dropped ball procedure The ball will be dropped for the goalie if play is stopped inside the penalty area. If the game is stopped outside of the penalty area, one player from the team that last touched the ball at the last touch will receive the ball. All other players from both teams must always be at least 4 metres or 4.5 yards away.
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a support supplies a force of 5 kn to a wall as shown below. what is the moment (in kn-m) produced by this force about an axis in the direction of i j k (from the origin)?
The moment (in KN-m) produced by the force about an axis in the direction of i+j+k (from the origin) if a force of 5 KN to a wall is 5 (cos θ + sin θ)
That is called torque when we calculate its moment of force. Torque is а meаsure of the force thаt cаn cаuse аn object to rotаte аbout аn аxis. Just аs force is whаt cаuses аn object to аccelerаte in lineаr kinemаtics, torque is whаt cаuses аn object to аcquire аngulаr аccelerаtion.
We are given:
Force = 5 KN
Horizontal Component i = [tex]F_{x}[/tex] = 5 cos θ
Vertical Component j = [tex]F_{y}[/tex] = 5 sin θ
x component of the moment (in kN-m):
M = [tex]F_{x}[/tex] × d
= 5 cos θ × d (kN - m)
d is the distance of the force form origin.
Force about an axis in the direction of i + j + k:
= [tex]F_{x}[/tex] + [tex]F_{y}[/tex] + [tex]F_{z}[/tex]
= 5 cos θ + 5 sin θ + 0
= 5 (cos θ + sin θ)
Your question is incomplete, but most probably your full question can be seen in the Attachment.
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nitrogen is contained in a 5-m3 rigid vessel at a pressure of 2200 kpa. (a) determine the mass if the temperature is 25oc. (b) determine the mass if the temperature is 250oc. (c) what would be the height of a column of mercury (in mm) in a manometer for this pressure? the density for mercury is 13600 kg/m3.
Barometric column, barometer column, etc. mercury barometer: a device that uses a mercury column to measure the height of the column (in inches of mercury) to determine atmospheric pressure.
How tall a column does a mercury have vertically?As a result, less than 76 cm of mercury can be held vertically in space by a basic barometer at sea level.Indicators of atmospheric pressure include the mercury column's height. The mercury column rises to a height of roughly 30 inches (76 centimeters) at sea level at a temperature of 0 degrees Celsius (C). This is equivalent to about 14.7 psia of pressure.Ytop minus YBot in HcolumnBarometric column, barometer column, etc. mercury barometer: a device that uses a mercury column to measure the height of the column (in inches of mercury) to determine atmospheric pressure.To learn more about Barometric column refer to:
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a proton is placed at a point where the electric field (due to other charges) is where is a constant with si units of n/c. what is the electric force on the proton? (e is the elementary charge: e
What is Electric Field?
-- Electric field, an electric property associated with each point in space when charge is present in any form.
--The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field..
What is electric force ?
-- The repulsive or attractive interaction between any two charged bodies is called as electric force.
-- Similar to any force, its impact and effects on the given body are described by Newton's laws of motion.
-- The electric force is one of the various forces that act on objects.
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a teacher sends her students on a treasure hunt. she gives the following instructions: 1. walk 300 m north 2. walk 400 m northwest 3. walk 700 m east-southeast and the treasure is buried there. as all the other students walk off following the instructions, joe physics student quickly adds the displacements and walks in a straight line to find the treasure. how far and in what direction does joe need to walk?
The directions she gives are as follows: 1. Move 400 meters to the northwest. 3. The wealth is hidden there, 700 meters to the east-southeast.
What is a displacement example?Change inside an object's position in relation to a reference frame is known as displacement. For instance, a billiards ball moves of one spot to another when one player strikes it. It is alleged to have moved. A vector quantity with both size and direction is displacement.
What is another name for displacement?The spacing between two specified points is represented by the one-dimensional quantity of displacement (symbolized as d or s), commonly known as length or distance. The meter serves as the standard displacement unit in the International Unit System (SI) (m).
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Two balls of unequal mass traveling at different speeds collide head-on and rebound in opposite
directions.
1) How does the force that ball A exerts on ball B compare to the force that ball B exerts on ball A?
2) How do the impulses received by both balls compare?
3) How do the sums of the momenta of the balls before and after the collision compare?
Can someone please answers these for me i need help.
Answer: 3
Explanation: i think
1. Mr. Gewanter, whose mass is 60 kg, is doing a physics demonstration in the front of the classroom.
A. How much gravitational force does he exert on 55 kg Martha in the front row, 1.5 m away?
B. How much force does he exert on 65 kg Lester in the back row, 4.0 m away?
2. A 400 kg weather satellite is about to launched into orbit.
A. When the satellite is still on Earth, what is the gravitational force on it? (The mass of the Earth is 5.98x1024 kg and the radius of the Earth is 6.37x106 m)
B. What radius of orbit does the satellite need to experience half this force?
By performing a physics demonstration in front of the students. F is 9.79 x 108 newtons.
Given,
Mr. Gewanter weighs 60 kilograms (kg).
The weight of Martha is 55 kg.
d = 1.5 meters separates them.
The equation F = GMm/d2 newton determines the gravitational force between them.
changing the given values in the equation above
F = (6.673 x 1011 x 60 x 55)/1.52 = 9.79 x 108 newtons.
As a result, F = 9.79 x 108 newton is the gravitational pull Mr. Gewanter has on Martha.
A geostationary satellite travels in a circular path around the planet with a 36,000 km radius. The orbital period of a spy satellite will then be roughly (Re = 6400 km), orbiting a few hundred kilometers above the surface of the planet.
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Calculate the height gained by a 2kg mass has 100J of gravitational energy is transferred to it. (g=10N/kg)
Answer:
The mass has gained a height of 5 meters.
Explanation:
To calculate the height gained by a 2kg mass when 100J of gravitational energy is transferred to it, we can use the equation:Height (h) = Gravitational Potential Energy (GPE) / Weight (w)where GPE = mgh (mass x acceleration due to gravity x height)Therefore,h = (100 J) / (2 kg x 10 N/kg)h = 5 metersThe mass has gained a height of 5 meters.
A force of 45 n is exerted on an object, resulting in an acceleration of 5 m/s² for the object. what will the object's acceleration be if the force doubles? question 9 options: a. 2.5 m/s² b. 5 m/s² c. 10 m/s² d. 20 m/s²
Answer:
Option C. 10 m/s²
Explanation:
First we need to find the mass of the object.
We can use Newton's second law to evaluate the mass of the object.
Newton's second law says that the net force of is equal to the mass times it acceleration.
[tex]F_{net} =ma[/tex]
Lets solve for [tex]m[/tex].
Divide each side by [tex]a[/tex].
[tex]m=\frac{F_{net} }{a}[/tex]
We are given
[tex]F_{net} =45\\a=5[/tex]
Lets evaluate [tex]m[/tex].
[tex]m=\frac{45}{5}[/tex]
[tex]m=9[/tex]
Now we can find the object's acceleration if the force doubles.
[tex]F_{net} =ma[/tex]
Lets solve for [tex]a[/tex].
Divide each side by [tex]m[/tex].
[tex]a=\frac{F_{net} }{m}[/tex]
Doubling the force of 45 N leaves us with a force of 90 N.
[tex]a=\frac{90}{9}[/tex]
[tex]a=10[/tex]
We can see that the object's acceleration is directly proportional to the net force and inversely proportional to the object's mass.
what is the magnitude of the force exerted by the biceps fbiceps ? what is the magnitude of the force exerted by the elbow felbow ? express your answers in newtons separated by a comma.
The force exerted by the biceps and the elbow is 239.9 N and 215.89 N respectively.
When we use only your forearms to lift an object, assume that your biceps are the main muscle that lifts your arm. Suppose the weight of the forearm he is 1.50 kg. If the biceps is attached to the forearm 2.50cm from the elbow, with the forearm parallel to the floor, flex the biceps to hold a 950g ball on the end of the elbow at a distance of 36.0cm from the elbow.
Against this background,
forearm mass = 1.50 kg
forearm length = 2.50 cm
The weight of the ball is 950 g.
36.0 cm ball spacing
Forearm strength needs to be calculated. Balance Elbow Using
Torque,
Fb x Db = Wf x Df/2 + Wball x Dball
Putting Value,
Fb x .025 = 1.5 x 9.8 x .36/2 + 0
95 x 9.8 x 0.36
Fb = 239.9 N
Now elbow force,
Fb = Fl + Wf + Wb
Fl = Fb - Wf - Wb
Putting value,
Fl = 239 .9 - (1.5 x 9.8 ) - (0.95×9.8)
Fl = 215.89 N.
Therefore the force on the elbow is 215.89 N.
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these fringe shifts occur because the wavelength of the light changes inside the gas filled tube. assume that 502 nm light is used, the tube is 3.99 cm long, and that 221 fringe shifts occur as the pressure of the gas in the tube increases to atmospheric pressure. calculate ngas, the index of refraction of the gas
The index of refraction of gas will be 1.008 units.
What is index of refraction?Because of their low density, gases at atmospheric pressure have refractive indices close to one.The refractive index, also known as the index of refraction, is a measurement of the bending of a light ray as it passes through one medium and into another.The number of wavelengths originally in the cylinder is m1 = 2L/λ when light is counted in both directions.
It transforms into m2 = 2L/λ/n gas.
= 2ngasL/λ
As the cylinder is filled with gas,
If N is the number of bright fringes passing,
N = m2 - m1
= 2L/λ (ngas - 1) or,
The index of refraction of the gas is,
ngas =1 + Nλ/2L = 1+ (221)(502 x 10⁻⁹ m)/2(3.99 x 10⁻²)
= 1.008 units
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let the sign of q2 be changed from positive to negative. at which position can the point charge q be placed now so that the net electrostatic force on it is zero?
The position of the point charge q can be placed such that the net electrostatic force is -1.857 m.
To find the position where the net electrostatic force on the charge q is zero, we need to apply Coulomb's Law. Coulomb's law states that the electrostatic force between two charges is proportional to the product of the charges and inversely proportional to the square of the charges. distance between them.
In this case, we have two charges Q1 and Q2 at known positions and we need to find the position of the third charge q such that the net force is zero.
By equating the force due to Q1 with the force due to Q2, we can solve for the position of q. Changing the sign of Q2 changes the direction of the force on q and changes the position of q.
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The question is -
An electric point charge of Q1 = 7.43 nC is placed at the origin of the real axis. Another point charge of Q2 = 1.21 nC is placed at a position of p = 3.95 m on the real axis. At which position can a third point charge of q = -1.99 nC be placed so that the net electrostatic force on it is zero? Let the sign of Q2 be changed from positive to negative. At which position can the point charge q be placed now so that the net electrostatic force on it is zero?
the andromeda galaxy is approximately two million light-years distant from earth as measured in the earth-linked frame. is it possible for you to travel from earth to andromeda in your lifetime? to answer this question, start by answering a series of trips from earth to andromeda, each one faster than the one before. for simplicity, assume the earth-andromeda distance to be exactly two million light-years in the earth frame, treat earth and andromeda as points, and neglect any relative motion between earth and andromeda. your one-way trip takes a time 2.01 times 10^6 years (measured in the earth-linked frame) to cover the distance of 2.00 times 10^6 light-years. how long does the trip last as measured in your rocket frame? what is your rocket speed on trip 1 as measured in the earth-linked frame? express this speed as a decimal fraction of the speed of light. your one-way earth-andromeda trip takes 2.001 times 10^6 years as measured in the earth-linked frame. how long does this trip last as measured in your rocket frame? what is your rocket speed for trip 2 expressed as a fraction of the speed of light? now set the rocket time for the one-way trip to 20 years, which is all the time you want to spend getting to andromeda. in this case, what is your speed as a decimal fraction of the speed of light?
No, it is not possible for you to travel from Earth to Andromeda in your lifetime.
What is Andromeda?Andromeda is a constellation located in the northern sky. It is named after the princess Andromeda in Greek mythology, who was chained to a rock as an offering to a sea monster.
To travel this distance in 20 years, you would need to travel at a speed of 0.99999999999999999c (where c is the speed of light). This is impossible, as nothing can travel faster than the speed of light.
The time it takes for the one-way trip to Andromeda as measured in the Earth-linked frame is 2.01 x 10^6 years. As measured in the rocket frame, this trip would take slightly longer due to time dilation effects caused by the high speed of the rocket. The rocket speed on Trip 1 as measured in the Earth-linked frame would be 0.00049975c, which is a decimal fraction of the speed of light.
For Trip 2, if we set the rocket time for the one-way trip to 20 years, then our speed would be 0.99999999999999999c as a decimal fraction of the speed of light. This is impossible, as nothing can travel faster than the speed of light.
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