A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph of the ball’s position �� as a function of time . What are the oscillation’s: a. period; b. frequency; c. angular frequency; d. amplitude; and e. What is the force constant of the spring?

Answer:

A. gravitational force always true.

B, C and D could be true under the correct conditions

Answer:

the answer is a....,.......

Answer:

The altitude of the satellite above the surface of the Earth is 1,528.48 km.

F=rmv2=R2GmMrv2=R2GMr=GMv2R2r=(6.67259×10−11)×(5.98×1024)(6900)2×(6,370,000)2r=4,841,516.6 mr=4,841.52 km

The final position of the object after 2 s is 11 m.

Motion: This can be defined as the change in position of a body.

⇒ Formula:

⇒ Where:

From the question,

⇒ Given:

⇒ Substitute these values into equation 1

Hence, The final position of the object after 2 s is 11 m

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Answer: part a is e

part b a  

Explanation:

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Answer:

the plot is about a crocodile who lives in a river.....

Explanation:

It is about a crocodile who lives in a river. He becomes friends with a monkey that lives on a tree on the river bank. Consequently, the monkey shares the fruits of the tree with his friend, the crocodile. Further, the crocodile takes a share for his wife.

Answer:

Explanation:

parallel capacitances add directly

Series capacitances add by reciprocal of sum of reciprocals.

Ceq = [ C ] + [1 / (1/C + 1/C)] + [1 / (1/C + 1/C + 1/C)]

Ceq = [ C ] + [C / 2] + [C / 3]

Ceq = [ 6C/6 ] + [3C / 6] + [2C / 6]

Ceq = 11C/6

Answer:

a

Explanation:

you will find out that an object that has more weight requires more energy to move than the one with less weight

A force of 50 N was applied to an object with a mass of 5 kg, then the acceleration of the object will be 10 m/s².

The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.

Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.

There are several types of acceleration :

According to the question, the given values are :

Force, F = 50 N

Mass, m = 5 kg

Force = m × a

a = 50 / 5

a = 10 m/s².

Hence, the acceleration of the object will be 10 m/s².

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Mass the air mattress support before sinking will be M = 97.2 kg

Given that

mass of mattress m=2.8 kg

Length = 2.00 m  

width =0.5 m  

The mattress can support a total weight that is equal to the weight of water that the air mattress displaces.

The volume of the air mattress will be equal to

[tex]V= (2\times 0.5\times 0.1)[/tex]

[tex]V= 0.1 m^{3}[/tex]

This volume is equal to the maximum amount of water that the mattress can displace in the water before it begins sinking.

We know the density of water is 1000 kg / m²

We can calculate the weight of the maximum amount of water that mattress will displace

[tex]V\times density of water\times g=0.1\times 1000\times 9.81=981N[/tex]

Let M represent the mass that the mattress is supporting.

The total weight of the mattress and the supported mass is:

[tex](2.8+M)\times9.81[/tex]

Setting this weight equal to the weight of the water displaced gives:

[tex](2.8+M)\times9.81=981[/tex]

[tex]2.8+M=100[/tex]

m = 97.2 kg

Hence Mass the air mattress support before sinking will be M = 97.2 kg

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Answer:

[tex]0.2\; {\rm T}[/tex], assuming that the speed of the electron stays the same.

Explanation:

Let [tex]v[/tex] denote the speed of this electron. Let [tex]q[/tex] denote the electric charge on this electron. Let [tex]m[/tex] denote the mass of this electron.

Since the path of this electron is a circle (not a helix,) this path would be in a plane normal to the magnetic field.

Let [tex]B[/tex] denote the strength of this magnetic field. The size of the magnetic force on this electron would be:

[tex]F = q\, v\, B[/tex].

Assuming that there is no other force on this electron. The net force on this electron would be [tex]F = q\, v\, B[/tex]. By Newton's Second Law of motion, the acceleration of this electron would be:

[tex]\begin{aligned}a &= \frac{F}{m} \\ &= \frac{q\, v\, B}{m}\end{aligned}[/tex].

On the other hand, since this electron is in a circular motion with a constant speed:

[tex]\begin{aligned} a = \frac{v^{2}}{r} \end{aligned}[/tex].

Combine the two equations to obtain a relationship between [tex]r[/tex] (radius of the path of the electron) and [tex]B[/tex] (strength of the magnetic field:)

[tex]\begin{aligned}\frac{q\, v\, B}{m} = \frac{v^{2}}{r}\end{aligned}[/tex].

Simplify to obtain:

[tex]\begin{aligned}r &= \frac{m\, v^{2}}{q\, v\, B} \\ &= \frac{m\, v}{q\, B} \\ &= \left(\frac{m\, v}{q}\right)\, \frac{1}{B}\end{aligned}[/tex].

In other words, if the speed [tex]v[/tex] of this electron stays the same, the radius [tex]r[/tex] of the path of this electron would be inversely proportional to the strength [tex]B[/tex] of the magnetic field. Doubling the radius of this path would require halving the strength of the magnetic field (to [tex]0.2\; {\rm T}[/tex].)

42.9°

Explanation:

Let's assume that the x-axis is aligned with the incline and the positive direction is up the incline. We can then apply Newton's 2nd law as follows:

[tex]x:\;\;\;\;F - mg\sin{\theta} = 0\;\;\;\;[/tex]

[tex]\Rightarrow mg\sin{\theta} = F[/tex]

Note that the net force is zero because the block is moving with a constant speed when the angle of the incline is set at [tex]\theta.[/tex] Solving for the angle, we get

[tex]\sin{\theta} = \dfrac{F}{mg}[/tex]

or

[tex]\theta = \sin^{-1}\left(\dfrac{F}{mg}\right)[/tex]

[tex]\;\;\;= \sin^{-1}\left[\dfrac{34\:\text{N}}{(5.1\:\text{kg})(9.8\:\text{m/s}^2)}\right][/tex]

[tex]\;\;\;=42.9°[/tex]

According to the law of superposition, the statement 'it is expected to find dinosaur bones below the K-T boundary but not above'' is TRUE. This boundary separates the Cretaceous and Tertiary periods.

The law of superposition is used by paleontologists to explain a sequence of sedimentary rock layers from the oldest layer at the base to reach the surface (newer).

Moreover, the K-T boundary is a boundary that separates sediments of the Cretaceous period from the Tertiary period.

This boundary (K-T boundary) dates approximately 65 million years (Mya) ago, i.e., the period in which dinosaurs became extinct.

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Answer:

Explanation:

Ignoring friction, the initial kinetic energy will convert to maximum potential energy at its highest point.

PE = KE

mgh = ½mv²

    h = v²/2g

    h = 36.4²/ (2(9.81))

    h = 67.53109...

    h = 67.53 m

Answer:

[tex]\boxed {\boxed {\sf 36 \ meters}}[/tex]

Explanation:

We are asked to find the distance a body covers. We know the initial velocity, acceleration, and time, so we will use the following kinematic equation.

[tex]d= v_i t+ \frac {1}{2} \ at^2[/tex]

The body starts at rest with an initial velocity of 0 meters per second. The acceleration is 8 meters per second squared. The time is 3.0 seconds.

Substitute the values into the formula.

[tex]d= (0 \ m/s)(3 \ s) + \frac{1}{2} (8 \ m/s^2)(3 \ s)^2[/tex]

Multiply the first set of parentheses.

[tex]d= ( 0 \ m/s * 3 \ s) + \frac{1}{2} ( 8 \ m/s^2)(3 \ s)^2[/tex]

[tex]d=0 \ m + \frac{1}{2} ( 8 \ m/s^2)(3 \ s)^2[/tex]

Solve the exponent.

[tex]d= 0 \ m + \frac{1}{2}( 8 \ m/s^2)(9 \ s^2)[/tex]

Multiply again.

[tex]d= 0 \ m + \frac{1}{2} ( 72 \ m)[/tex]

[tex]d= 36 \ m[/tex]

The body will cover a distance of 36 meters.

The amount of work done by the hairdryer is equal to 450 Kilojoules.

Given the following data:

To determine the amount of work done by the hairdryer:

Mathematically, the work done by an object with respect to power and time is given by the formula:

[tex]Work\;done = power \times time[/tex]

Substituting the given parameters into the formula, we have;

[tex]Work\;done = 750 \times 600[/tex]

Work done = 450,000 Joules

Note: 1000 Joules = 1 Kilojoules.

Work done = 450 Kilojoules.

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Answer:

mid-ocean oceanic ridges

Explanation:

Answer:

mid-ocean oceanic ridges

Explanation:

Divergent boundaries are most likely to be found at mid-oceean oceanic ridges.

Question

what is the force exerted on a selectively permeable membrane beacuse water has moved from an area of higher concentration to an area of Lower concentration of water?

Answer

OSMOSIS

Explanation

Osmosis: This is the hydrostatic force acting to equalize the concentration of water on both sides of the membrane that is impermeable to substances dissolved in that water. Water will move along its concentration gradient.

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Answer:

An electron tube from which all air has been removed. The vacuum ensures transparency inside the tube for electric fields and moving electrons. Most electron tubes are vacuum tubes; cathode-ray tubes, which include television picture tubes and other video display tubes, are the most widely used vacuum tubes

Explanation:

hope it help

Answer:

(a) 91 kg (2 s.f.)    (b) 22 m

Explanation:

Since it is stated that a constant horizontal force is applied to the block of ice, we know that the block of ice travels with a constant acceleration and but not with a constant velocity.

(a)

                                                   [tex]s \ = \ ut \ + \ \displaystyle\frac{1}{2} at^{2} \\ \\ a \ = \ \displaystyle\frac{2(s \ - \ ut)}{t^{2}} \\ \\ a \ = \ \displaystyle\frac{2(11 \ - \ 0)}{5^{2}} \\ \\ a \ = \ \displaystyle\frac{22}{25} \\ \\ a \ = \ 0.88 \ \mathrm{m \ s^{-2}}[/tex]

     Subsequently,

                                                  [tex]F \ = \ ma \\ \\ m \ = \ \displaystyle\frac{F}{a} \\ \\ m \ = \ \displaystyle\frac{80 \ \mathrm{kg \ m \ s^{-2}}}{0.88 \ \mathrm{m \ s^{-2}}} \\ \\ m \ = \ 91 \mathrm{kg} \ \ \ \ \ \ (2 \ \mathrm{s.f.})[/tex]

*Note that the equations used above assume constant acceleration is being applied to the system. However, in the case of non-uniform motion, these equations will no longer be valid and in turn, calculus will be used to analyze such motions.

(b) To find the final velocity of the ice block at the end of the first 5 seconds,

                                                    [tex]v \ = \ u \ + \ at \\ \\ v \ = \ 0 \ + \ (0.88 \mathrm{m \ s^{-2}})(5 \ \mathrm{s}) \\ \\ v \ = \ 4.4 \ \mathrm{m \ s^{-1}}[/tex]

     According to Newton's First Law which states objects will remain at rest

     or in uniform motion (moving at constant velocity) unless acted upon by

     an external force. Hence, the block of ice by the end of the first 5

     seconds, experiences no acceleration (a = 0) but travels with a constant

     velocity of 4.4 [tex]m \ s^{-1}[/tex].

                                                    [tex]s \ = \ ut \ + \ \displaystyle\frac{1}{2}at^{2} \\ \\ s \ = \ (4.4 \ \mathrm{m \ s^{-2}})(5 \ \mathrm{s}) \ + \ \displaystyle\frac{1}{2}(0)(5^{2}) \\ \\ s \ = \ 22 \ \mathrm{m}[/tex]

      Therefore, the ice block traveled 22 m in the next 5 seconds after the

      worker stops pushing it.

Answer:

Explanation:

To calculate an effect size, called Cohen's d , for the one-sample t-test you need to divide the mean difference by the standard deviation of the difference, as shown below. Note that, here: sd(x-mu) = sd(x) . μ is the theoretical mean against which the mean of our sample is compared (default value is mu = 0).

it is D for sure im good with history

Answer: D

Explanation: Its just s that guy ca get brainlist :D

Explanation:

This question is not feasible. There is no way to calculate the energy needed because the question is missing the final temperature

Answer:

F = 0 N

Explanation:

The problem does not talk about any acceleration. We can just assume it always moves at a constant speed so the resultant force will be 0 newtons. Of course you could say that it accelerates for a certain amount of time, as the wind blows, but the problem doesn't tell us when to calculate the resultant force (if during the acceleration or after) + we don't have the mass of the jet.

Explanation:

Downstream: you just sum the magnitude of the velocity vectors:

3km/h + 4km/h = 7km/h

Upstream: difference of the magnitudes of the velocity vectors, in absolute value:

|3km/h - 4km/h| = 1km/h

Answer:

Speed of light =m/s

wavelength = m

frequency = ?

we have

Speed = frequency × wavelength

[tex]3* 10^8[/tex] = frequency × [tex]5 * 10^{-7}[/tex]

 Frequency = [tex]\frac{3*10^8}{5*10^{-7}}=6*10^{14}[/tex]hz

Taking into account the definition of wavelength, frecuency and propagation speed, the frequency of light waves with wavelength of 5×10⁻⁷ m is 6×10¹⁴ Hz.

First of all, wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.

The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f× λ

All electromagnetic waves propagate in a vacuum at a constant speed of 3×10⁸ m/s, the speed of light.

In this case, you know:

Replacing in the definition of propagation speed:

3×10⁸ m/s = f× 5×10⁻⁷ m

Solving:

3×10⁸ m/s ÷ 5×10⁻⁷ m= f

f= 6×10¹⁴ Hz

In summary, the frequency of light waves with wavelength of 5×10⁻⁷ m is 6×10¹⁴ Hz.

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Answer:

Gravity can pull soil, mud, and rocks down cliffs and hillsides.

Explanation:

Gravity is responsible for erosion by flowing water and glaciers. But gravity also causes erosion directly. This type of erosion and deposition is called mass wasting.

Answer:

Explanation:

Answer: It is identified with color, texture, boiling point, melting point and freezing point

Explanation: