7. Your teacher has mixed salt, pepper, and water. Describe a procedure that you could use to separate this mixture. Be sure to list all of the materials you would need, your set up, and your expected results.​

Answer:

A

Explanation:

big brain

During this quick stop, some of the mechanical energy (his motion) was changed into heat energy.

Energy is the ability to do work. There are different types of energy such as Heat energy, light energy, kinetic energy, and gravitational energy.

Heat is the energy that moves from one body to another when temperatures are different. Heat passes from the hotter to the colder body when two bodies with differing temperatures are brought together.

The joule is a unit of energy that serves as the SI unit for heat (J). The calorie (cal), which is defined as "the amount of heat necessary to raise the temperature of one gram of water from 14.5 degrees Celsius to 15.5 degrees Celsius," is another common unit of heat measurement.

Therefore, During this quick stop, some of the mechanical energy (his motion) was changed into heat energy.

To learn more about heat energy, refer to the link:

https://brainly.com/question/20038450

#SPJ6

Answer:

you couldn't do this on your own or search it up on google

Answer:

11 km/s

Explanation:

v=s/t

v=825km/75s

v=11km/s

Answer;  Ultrasonic waves (sounds having frequency greater than 20,000 Hz) are used in sonar because: ... Ultrasonic waves can penetrate water to long distances (because of their high frequency and very short wavelength), but ordinary sound waves or infrasonic waves cannot penetrate water to such long distances.

Answer:

Ultrasonic waves (sounds having frequency greater than 20,000 Hz) are used in sonar because: ... Ultrasonic waves can penetrate water to long distances (because of their high frequency and very short wavelength), but ordinary sound waves or infrasonic waves cannot penetrate water to such long distances

Explanation:

Answer:

the answer to your question is b a mirror fogs up when someone takes a hot shower.

The process of conversion of gaseous water to its liquid form is called condensation. The fogs formed on the mirror from the hot shower is an example of condensation.

Condensation is the process of cooling up of water vapor to liquid water. Water vapor condenses when it cools. Condensation can be best understood from the reason behind raining.

When water vaporizers from resources and cools from the sky, and the vapor condenses to form liquid droplets. Similarly we can observe water droplets in the window pane due to the similar effect.

The water vapor arises from the hot shower condenses in the atmosphere and forms the drops on the mirror. Therefore, the mirror fogs up by the hot shower is an example of condensation.

To find more on condensation, refer here:

https://brainly.com/question/15563071

#SPJ5

Answer:

nitrogen oxygen carbon dioxideand argon

Explanation:

Answer:

27.1 m/s

Explanation:

Given that at a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2.

Using third equation of motion,

V^2 = U^2 + 2aS

Since the car is decelerating, the final velocity V = 0

Substitute all the parameter into the equation above,

0 = U^2 - 2 * 40.52 * 9.06

U^2 = 734.22

U = [tex]\sqrt{734.22}[/tex]

U = 27.096

U = 27.1 m/s  approximately

Therefore, the staff member can estimate for the original speed of the race car to be 27.1 m/s if it came to a stop during the skid

Answer:

Normal, Gravity, Friction, and Air Resistance.

Explanation:

When a moving car skid to stop and its wheels are locked across, then the following forces will be applied on the car:

Normal force: It will act counter to gravity that pushes an object against a surface and acts perpendicular to the contact surface.

Gravity: Gravity force acts in each and every object having mass and it can not be avoidable. So, the gravity force will also apply to the car and attract it to the earth's surface.

Friction: Friction is a force that acts opposite to the motion and stops or slows motion. Friction will be applied to the car that will oppose the motion of the car and stop it.

Air resistance: air resistance is defined as the forces exerted by air that acts opposite to the relative motion of an object. Air resistance will also be applied to the car when it will skid to stop as we are always surrounded by the air.

Hence, the correct answers are "Normal, Gravity, Friction, and Air Resistance."

Answer:

theres no

Explanation:

picture or anything so... ur question doesnt make sense

Given :

An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west.

It starts at the 14-inch mark, crawls to the 20-inch mark, then moves to the 16-inch mark.

To Find :

The total distance the ant traveled.

Solution :

Total distance travelled by ant = (distance between 14 and 20 inch mark) +

                                                      (distance between 20 and 16 inch mark)

Total distance = (20-14 ) + ( 20-16) = 6 + 4 = 10 inch.

Therefore, total distance the ant traveled is 10 inch.

Hence, this is the required solution.

Answer:

100

Explanation:

The final velocity of the object after the force acts is 2.5 meters per second.

To calculate the final velocity of the object after the force acts, we can use Newton's second law of motion, which states that:

Force = Mass × Acceleration

We need to find the acceleration of the object first. Since the object was initially at rest, its initial velocity (u) is 0 m/s.

The force acting on the object is 500 N, and the mass of the object is 0.20 kg. We can rearrange the equation to find the acceleration (a):

Acceleration (a) = Force / Mass

a = 500 N / 0.20 kg

a = 2500 m/s²

Now, we can use the kinematic equation to find the final velocity (v) of the object:

Final velocity (v) = Initial velocity (u) + (Acceleration × Time)

The initial velocity (u) is 0 m/s (since the object was initially at rest), and the time interval (t) is 0.001 second.

Final velocity (v) = 0 m/s + (2500 m/s² × 0.001 s)

v = 0 m/s + 2.5 m/s

v = 2.5 m/s

Hence, the final velocity of the object after the force acts is 2.5 meters per second.

To know more about final velocity here

https://brainly.com/question/28608160

#SPJ2

Answer:

A

Explanation:

The acceleration of an object is directly proportional to its net force.

[tex]a = \frac{f}{m} [/tex]

Answer:

Correct choice: A. The acceleration is directly proportional to the net force

Explanation:

Newton's Second Law of Motion

According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force F and inversely proportional to the object's mass m:

[tex]\displaystyle a=\frac{F}{m}[/tex]

Correct choice: A. The acceleration is directly proportional to the net force

Answer:

true

Explanation:

Protons and neutrons are found in the nucleus

Answer:

(a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m

Explanation:

Given that,

Time = 4.60 s

We need to calculate the initial velocity

Using equation of motion

[tex]v=u-gt[/tex]

Put the value into the formula

[tex]0=u-9.8\times4.60[/tex]

[tex]u=45.0\ m/s[/tex]

We need to calculate the distance

Using formula of distance

[tex]d=v\times t[/tex]

Put the value into the formula

[tex]d=45\times4.60[/tex]

[tex]d=207\ m[/tex]

We need to calculate the maximum height

Using equation of motion

[tex]v^2=u^2-2gh[/tex]

Put the value into the formula

[tex]0=(45.0)^2-2\times9.8\times h[/tex]

[tex]h=\dfrac{(45.0)^2}{2\times9.8}[/tex]

[tex]h=103.3\ m[/tex]

Hence, (a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m

Explanation:

Hey there!

We know that the objects in vacuum falls equally on the surface or bottom. As there is no air resistance in vacuum, the objects has equal stabdard acceleration. (i.e g = 9.8m/s^2)

So, the acceleration due to gravity is 9.8m/s^2.

Hope it helps....

Answer:

The skier is experimenting a net force of 0 newtons in both cases. ([tex]v_{1} = 15\,\frac{km}{h}[/tex], [tex]v_{2} = 20\,\frac{km}{h}[/tex])

Explanation:

According to Newton's First Law, an object is in equilibrium when it is either at rest or moving at constant velocity, which means that net force is equal to 0 newtons.

Therefore, the skier is experimenting a net force of 0 newtons in both cases.

11

Explanation:

There are 11 protons in a sodium atom

Answer:

1200

Explanation:

Force = Mass x Acceleration

Answer:

[tex]\boxed {\tt 1,200 \ Newtons }[/tex]

Explanation:

Force can be found by multiplying the mass by the acceleration.

[tex]F=m*a[/tex]

The mass is 300 kilograms.

The acceleration is 4 meters per second squared.

[tex]m= 300 \ kg\\a= 4 \ m/s^2[/tex]

Substitute the values into the formula.

[tex]F= 300 \ kg * 4 \ m/s^2[/tex]

Multiply.

[tex]F= 1200 \ kg * m/s^2[/tex]

1 Newton is equal to 1 kilograms meters per second squared, so our current answer of 1200 kg m/s² is equal to 1200 Newtons.

[tex]F= 1200 \ N[/tex]

The force needed is 1,200 Newtons.

Answer:

6 seconds

Explanation:

The answer is 6 because if the dog is going 10 m/s it will take 6 seconds to get from 60 meters away to you.

Answer:

C. Move the magnetized nail back and forth within the wire coil to induce an electric current in the wire.

Hope this helps.

Answer:

Decreasing the angle to 10

Explanation:

Edge 2020

Answer:

yes 5 is greater

Explanation:

Answer: 5 grams is greater than 508 milligrams. Even though the number '508' is larger than '5,' you need to look at the units.

Answer:

Total Displacement = -18m

Explanation:

Given

East Movement = 38m and 27m

West Movement = 47m

Required

Determine the total displacement

To answer this, we consider east as negative direction and the west as positive (using logics of number line).

Total Displacement = East Movement + West Movement

Total Displacement = -38m - 27m + 47m

Total Displacement = -18m

Hence, the total displacement is 18m towards East

Answer:

a) El punto de colisión de los dos automóviles desde donde parte el conductor del automóvil A es de aproximadamente 293,14 metros.

b) La velocidad del automóvil A, en relación con la velocidad del automóvil B, es de 15 m / s

Explanation:

Los parámetros del movimiento son;

La distancia entre ambos coches = 500 m

La aceleración de ambos coches = 15 m / s²

La dirección de movimiento de ambos coches = uno hacia el otro

La hora de inicio del conductor A = Un segundo antes de la hora de inicio del conductor B

Por lo tanto, de la ecuación de movimiento, tenemos;

s = u · t + 1/2 · a · t²

v² = u² + 2 · a · s

Dónde;

u = La velocidad inicial de los autos = 0 (los autos parten del reposo)

t = El tiempo de movimiento de una aceleración dada

a = La aceleración = 15 m / s²

s = La distancia recorrida en el tiempo t

Por lo tanto, para el controlador A, tenemos;

s₁ = 0 × (t + 1) + 1/2 × 15 × (t + 1) ² = 7.5 × (t + 1) ²

s₁ = 7.5 × (t + 1) ²

Para el conductor B, tenemos;

s₂ = 0 × t + 1/2 × 15 × t² = 7.5 × t²

s₂ = 7,5 × t²

Dado que ambos chocan a lo largo del camino de 500 m, tenemos;

s₁ + s₂ = 500 metros

∴ 7.5 × (t + 1) ² + 7.5 × t² = 500

∵ s₁ + s₂ = 7.5 × (t + 1) ² + 7.5 × t²

Lo que da;

15 · t² + 15 · t + 7.5 = 500

15 · t² + 15 · t - 492,5 = 0

Resolver usando la aplicación en línea da; t = -6,25181 o t = 5,25181

Dado que t es un número natural, tenemos el valor correcto para t = 5.25181 segundos

a) Por tanto, el punto de colisión de los dos coches desde donde parte el conductor del coche A es;

s₁ = 7.5 × (t + 1) ² = 7.5 × (5.25181 + 1) ² ≈ 293.14 metros

El punto de colisión de los dos automóviles desde donde parte el conductor del automóvil A ≈ 293,14 metros

b) La semilla de A en el punto de colisión se da de la siguiente manera

Velocidad, v₁ = u + a × (t + 1) = 0 + 15 × (5.25181 + 1) ≈ 93.78

v₁ ≈ 93,78 m / s

La semilla de B en el punto de colisión también se da de la siguiente manera

Velocidad, v = u + a × (t) = 0 + 15 × 5.25181 ≈ 78.78

v₁ ≈ 78,78 m / s

Por lo tanto, la velocidad del automóvil A, en relación con la velocidad del automóvil B, [tex]v_{relative}[/tex] se da como sigue;

 = v₁ - v₂ = 93,78 m / s - 78,78 m / s = 15 m / s

la velocidad del automóvil A, relativa a la velocidad del automóvil B = 15 m/s.