The wavelength is 2m.
Hence, Option c) 2m is the correct answer
Given that;
Frequency; [tex]f = 30Hz[/tex]
Speed; [tex]v = 60m/s[/tex]
Wavelength; [tex]\lambda =\ ?[/tex]
using the expression for the relations between wavelength, frequency and speed of wave:
[tex]\lambda = \frac{v}{f}[/tex]
Where [tex]\lambda[/tex] is wavelength, f is frequency and v is speed.
We substitute our given values into the equation
[tex]\lambda = \frac{60m/s}{30Hz}\\\\\lambda = \frac{60m/s}{30s^{-1}}\\\\\lambda = 2m[/tex]
The wavelength is 2m.
Hence, Option c) 2m is the correct answer.
To learn more about wavelength, click here: https://brainly.com/question/1347107
The frequency of the moving wave is 30 Hz and if it is moving at the speed of 60 m/s then the wavelength will be equal to 2 m.
What is Wavelength?The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm).
The wavelength is more frequently described in nanometers (nm), which are units of 10⁻⁹ m, or angstroms, which are units of 10⁻¹⁰ m, for infrared (IR), visible light (UV), and gamma radiation.
As per the provided given data in the question,
Frequency, f = 30 Hz
Speed, v = 60 m/s
Then, the wavelength of the moving wave will be,
λ = v/f
= 60/30
λ = 2 meters.
Therefore, the wavelength will be 2 meters.
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#SPJ2
There can be multiple equal & opposite forces acting on a singular object?
True or False
Answer:
true
Explanation:
negative positive horizontal vertical gravity, friction and more
A 263 g ball of clay falls onto a vertical spring.
The spring constant k = 2.52 N/cm.
The clay sticks to the spring and as the spring compresses a distance of 11.8 cm the clay momentarily comes to rest.
Determine the speed of the clay just before it hit the spring in [m/s]?
As the spring is compressed, it performs
-1/2 (252 N/m) (0.118 m)² ≈ -1.75 J
of work on the clay, while gravity does
(0.263 kg) (9.80 m/s²) (0.118 m) ≈ 0.304 J
on it. Then the total work W performed on the clay ball is approximately -1.45 J.
By the work-energy theorem, W is equal to the change in the clay ball's kinetic energy ∆K. If v is the speed with which it hits the spring, then
W = ∆K
-1.45 J = 0 - 1/2 mv²
Solve for v :
-1.45 J = -1/2 (0.263 kg) v²
v² ≈ 11.0 m²/s²
v ≈ 3.32 m/s
how to find change in kinetic energy wfrom joules
Answer:
What do you mean? Can you please explain yourself better?
What happens to a liquid in a U-tube manometer when placed in a vacuum
Answer:
With a greater pressure applied to the left side of a U-tube manometer, the liquid lowers in the left leg and rises in the right leg. The liquid moves until the unit weight of the liquid, as indicated by h, exactly balances the pressure.
Answer:
Here
Explanation:
With a greater pressure applied to the left side of a U-tube manometer, the liquid lowers in the left leg and rises in the right leg. The liquid moves until the unit weight of the liquid
describe the working principle of a hydraulic press using pascals principle
Answer:
A hydraulic press works on the principle of Pascal's law, which states that when pressure is applied to a confined fluid, the pressure change occurs throughout the entire fluid. Within the hydraulic press, there is a piston that works as a pump, that provides a modest mechanical force to a small area of the sample.
Explanation:
will give brainlyiest what is the main need or want this wave technology meets to efficiently communicate with others to hear and see others in real time to efficiently store and share music with others to speak with and see others who are far away
Answer: To see objects surrounding more clearly
Explanation:
A cat that has a mass of 6 kg climbs to the top of a tree that is 20 m high. How much potential energy does the cat have at the top of the tree?
Have a great day!
Answer:
1176.798 J
Explanation:
[] Use the following equation:
U = mgh
m - mass
g - gravitational field
h - height
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
Answer:
0.184 m/s
Explanation:
Momentum is conserved. If the velocity of the 0.24 kg mass is positive, then ...
m1v1+m2v2 = m3v3
(0.24 kg)(0.60 m/s) +(0.26 kg)(-0.20 m/s) = (0.24 +0.26 kg)(v)
v = (0.144 -0.052 kg·m/s)/(0.50 kg) = 0.184 m/s
The speed of the combined masses is 0.184 m/s.
_____
Additional comment
The positive sign indicates the combined masses are moving in the direction of the original 0.24 kg mass.
A net force of 79 N causes a mass to accelerate at a rate of 3 m/s2. Determine the mass
An airplane initially travels at 12 m/s when passing the "acceleration line." The airplane then
accelerates to 9 m/s2 until reaching its take off velocity of 40.0 m/s. What is the displacement of
the plane during the acceleration?
The displacement of the plane during the acceleration is equal to 80.89 meters.
Given the following data:
Initial velocity = 12 m/sFinal velocity = 40 m/sAcceleration = 9 [tex]m/s^2[/tex]To determine the displacement of the plane during the acceleration, we would use the third equation of motion;
[tex]V^2 = U^2 + 2aS[/tex]
Where:
V is the final speed.U is the initial speed.a is the acceleration.S is the displacement traveled.Substituting the given parameters into the formula, we have;
[tex]40^2 =12^2 + 2(9)S\\\\1600=144+18S\\\\18S=1600-144\\\\18S=1456\\\\S=\frac{1456}{18}[/tex]
Displacement, S = 80.89 meters.
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4. In not less than 150 words, write your substantial insights on what you have learned in the past modules in relevance to what is happening now.
Answer:
“I think it’s about putting yourself in the students’ shoes and seeing how a first-time student, maybe someone who hasn’t even taken chemistry before, is looking at it.”
—Valerie Taraborelli, undergraduate chemistry student, University of Arizona1
“In some ways, I think the people who are the most successful as teachers are the ones who are able to remember what it was like being uncertain and not knowing. When you become an expert, things are easy. So the idea is to try and see where [students] are coming from and why they’ve developed this misconception and what you can do to specifically address it.”
—Dee Silverthorn, biology professor, University of Texas2
Hope this helps !!Construct an explanation for the fact that we don’t see the same amount of energy coming out at the end of these transformations as we did at the beginning. *
Answer:
When energy is transformed from one form to another, or moved from one place to another, or from one system to another there is energy loss.
Explanation:
Hope this helps! :)
how do you find average velocity (vaverage) from acceleration (a) and time (t)?
Answer:
1) Average velocities:
Given the magnitudes of 2 velocity vectors, in different time instants, the average velocity is defined as the difference of the 2 velocity magnitudes, in absolute value, divided by the interval of time occuring between the measurement of the velocity magnitudes.
2) Average acceleration
Given the magnitudes of 2 acceleration vectors, in different time instants, the average acceleration is defined as the difference of the 2 acceleration magnitudes, in absolute value, divided by the interval of time occuring between the measurement of the acceleration magnitudes.
As you see the definitions are pretty similar.
Note: I didn't copy-paste this answers from any other site.
me (5) A taxi is travelling at 15. m/s. Its driver accelerates with acceleration 3 m/s for 4 s. What is its new velocity? A car accelerates from 20 m/s to 30 m/s in 10 (a) Calculate the car's acceleration using v=utat. (b) Draw a velocity-time graph to show the car's motion. Find the distance it travels by calculating the area under the graph. (c) Check your answer by using the equation s = ut + hat Grade 9
Answer:
5)
Solution
initial velocity = 15 m/s
acceleration = 3m/s^2
time = 4 s
final velocity = 15+3×4
=15+12
=27m/s
A car accelerates from 20m/s to 30m/s in 10 second
T9 be honest I think some part of the second question is missing
A 6 kilogram block in outer space is moving at -100 m/s (to the left). It suddenly experiences three forces as shown below.
B) What equilibrant force is required to keep the block at rest once it does?
C) If you were to rearrange the three forces as you like, what maximum force could be applied to slow the block?
D) How much time would it take for the block to stop under maximum force conditions?
Newton's second law and the kinematic relations allow to find the results for the questions about forces and the movement of the block are:
B) the force applied to maintain the system is equilibrium is: F = 0.39 N with an angle of tea = 180º
C) The maximum force is: F = 24 N
D) The time to stop the block is: t = 25 s
Newton's second law establishes a relationship between the net force, the mass, and the acceleration of the body. In the special case that the acceleration is zero it is called the equilibrium condition.
B) They indicate a diagram of forces on the block, let's look for the components of the force that the block maintains with zero acceleration, in the attached we have a free-body diagram including the force applied to keep the system in equilibrium.
x-axis
-10 + 12 sin 60 + Fₓ = 0
Fₓ = 10- 12 sin 60 = -0.39 N
y-axis
12 cos 60 - 6 + F_y = 0
F_y = 6 - 12 cos 60 = 0 N
We can give the result of the force in two ways:
Form of coordinates F = -0.39 i ^ N Form of module and angle.
Let's use Pythagoras' theorem to find the modulus.
[tex]F = \sqrt{F_x^2 + F_y^2 } \\F = \sqrt{0.39^2 +0^2}[/tex]
F = 0.39N
We use trigonometry for the angle.
[tex]tan \theta = \frac{F_y}{F_x}[/tex]
tan θ= 0º
The component of the force is negative therefore this angle is in the second quadrant, to measure the angle from the positive side of the x axis in a counterclockwise direction.
θ = 180 + θ'
θ = 180 + 0
θ = 180º
C) if the three forces can be moved and the maximum force occurs when they are all linear.
10+ 6 + 6 + F = 0
F = -24 N
D) if we maintain this force and eliminate the other three, the block stops, let's look for its acceleration.
[tex]a = \frac{F}{m}[/tex]
a = [tex]\frac{24}{6}[/tex]
a = 4 m / s²
The acceleration is in the opposite direction of the initial velocity of the block v₀ = -100 m / s
If we use kinematic relations.
v = v₀ - a t
Final velocity when stopped is zero
t = [tex]\frac{0-v_o}{a}[/tex]
t = 100/4
t = 25 s
In conclusion using Newton's second law and the kinematics relations we can find the results for the questions about the forces and the motion of the block are:
B) the force applied to maintain the system is equilibrium is: F = 0.39 N with an angle of tea = 180º
C) The maximum force is: F = 24 N
D) The time to stop the block is: t = 25 s
Learn more about Newton's second law here: brainly.com/question/25545050
A 3 Kg ball at the end of a string is spun in a circle. If the length of the string is 2 m and the velocity of the ball is 6 m/s, what is the centripetal acceleration of the ball? What is the centripetal force on the ball?
Define the following:
Variable
Data
Control
Technology
Hypothesis
Physical Science
Experiments
Answer:
Variable- not consistent or having a fixed pattern; liable to change
Data- facts and statistics collected together for reference or analysis
Control- a group or individual used as a standard of comparison for checking the results of a survey or experiment
Technology- the application of scientific knowledge for practical purposes, especially in industry
Hypothesis- a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation
Physical Science- the sciences concerned with the study of inanimate natural objects, including physics, chemistry, astronomy, and related subjects
Experiments- a scientific procedure to make a discovery, test a hypothesis, or demonstrate a known fact
Explanation:
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is ____?
[tex]\purple{ \longrightarrow \bf{h_m = \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} }} [/tex]
Projectile is thrown with a velocity = v Angle of projection = θVelocity of projectile at a height half of the maximum height covered be [tex] \sf{v_0}[/tex][tex]\qquad[/tex]______________________________
Then –
[tex]\qquad[/tex] [tex]\pink{ \longrightarrow \bf{ \dfrac{h_m}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }}[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} \times \dfrac{1}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{4g} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2} = {v_0}^{2} \: {sin}^{2} \theta }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf{ \dfrac{ {v}^{2} }{2} = {v_0}^{2} }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \bf{v_0 = \sqrt{ \dfrac{ {v}^{2} }{2} } = \dfrac{v}{ \sqrt{2} } }[/tex]
Now, the vertical component of velocity of projectile at the height half of [tex] \sf{h_m}[/tex] will be –[tex]\qquad[/tex] [tex]\longrightarrow \bf{v_{(y)}=v_0 \: sin \theta }[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \bf{v_{(y)} = \dfrac{v}{ \sqrt{2} } \: sin \theta = \dfrac{v \: sin \: \theta}{ \sqrt{2} } }[/tex]
Therefore, the vertical component of velocity of projectile at this height will be–
☀️[tex]\qquad[/tex][tex] \pink {\bf{ \dfrac{v \: sin \: \theta}{ \sqrt{2} }} }[/tex]
Answer:
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is v sintheta / √2
40 POINTSS. Now explore friction force. Set the piece of plastic or wood on the table and push it steadily across the tabletop using your fingertip. Note how much opposition to your push you feel. Repeat the steps, but this time push the piece of plastic or wood across a rug, carpet, or piece of fabric. If you’re using fabric, be sure to secure the fabric so it doesn’t move. How does the opposition to motion on the tabletop compare with that of the rug, carpet, or fabric? WILL MARK BRAINLIST IF RIGHT
Answer: If there is a higher friction, the opposition force is higher so that it can reduce our speed. So, a factor that affects friction is the roughness or smoothness of the surface of the object. In comparison of the table with the fabric, the fabric will have a more opposition force. As the surface of the fabric is usually rougher than the surface of a smooth table. As there is more friction on a fabric, we will feel more opposition force on our finger tip.
☆ Correct and rewrite the following statements:
_____
e). electroplating is based on magnetic effect of electricity.
f). an electric bulb glows due to the chemical effect of electricity.
_______________________
#No spam
#No Internet answers, please #Explanation needed
Answer:
e)Question:-Electroplating is based on magnetic effect of electricity.Answer:-It's incorrect sentence As we know that, while electroplating there are two rods, one becoming cathode and another one becoming anode. During electroplating, when electricity is given through the rods, the anode produces positive ions which gets received at the cathode rod and negative ions produced at cathode collects at anode rod which results to the plating of the desired substance. Here, it is a chemical effect of electricity resulting to plating.So correct sentence is:
Electroplating is based of chemical effect of electricity. f)Question:-An electric bulb glows due to the chemical effect of electricity.Answer:-It's incorrect sentence As we know that, in an electric bulb there is a filament. When electricity is given in that filament of the electric bulb, the filament gets intensely heated up and results to the emission of light. Due to this heating of the filament due to electricity the electric bulb glows.So correct sentence is:
An electric bulb glows due to the heating effect of electricity.how does cells and tissues work together with the brain to do its job
What ions are produced from acids and bases?
Answer:
Give person above me brainliest
Explanation:
Help me as soon as possible <3
Answer: ??? what the
Explanation:
What is the difference between folk dance and ballroom dance
Answer:
folk dancing is old music and ball room is young dancing
A bullet of mass 20 g has its kinetic energy equal to 400 J. Find the speed of the bullet.
Answer:
m=20g=0.02kgK.E=400J[tex]\\ \sf\longmapsto KE=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{2}(0.02)v^2=400[/tex]
[tex]\\ \sf\longmapsto 0.01v^2=400[/tex]
[tex]\\ \sf\longmapsto v^2=40000[/tex]
[tex]\\ \sf\longmapsto v=200m/s[/tex]
assume that the hubble constant is 72 km/s/mpc. if a galaxy is 100mpc away, how fast is it moving away from us?
The galaxy is 7200 km/s moving away from us.
A Hubble is a large telescope in space.
The question can be solved using the formula below
⇒ Formula
v = Cd........................ Equation 1⇒ Where:
v = Speed of the galaxyC = Hubble constantd = Galaxy's distance⇒ Given:
C = 72 km/s/mpcd = 100 mpc⇒ Substitute these values into equation 1
v = 72(100)v = 7200 km/s.Hence, the galaxy is 7200 km/s moving away from us.
Learn more about Hubble here: https://brainly.com/question/14615983
A car travels 80 km at an avarage speed of 40 km/h. It travels the remaining distance in 3h. What is its dis placement if the average speed of the car is 30 km/h.? And explain
A) 100 km
B)120 km
C)150km
D)180km
When traveling with average speed 40 km/h, the car would cover a distance of 80 km in time t such that
40 km/h = (80 km) / t ⇒ t = 2 h
so the total travel time is 2 h + 3 h = 5 h.
Average speed is defined as the total distance traveled divided by the time it took to cover that distance. So if the overall average speed was 30 km/h, then
30 km/h = (80 km + x) / (5 h) ⇒ x = 70 km
where x is the distance traveled in the last 3 h of the trip.
Then the total displacement of the car is 80 km + 70 km = 150 km.
Why aren’t the Appalachian Mountains still as tall as the Himalayas?
Answer:
mountains are limited in their theoretical height by several processes. First is isostasy: the bigger a mountain gets, the more it weighs down its tectonic plate, so it sinks lower. ... Bottom line: mountains can get taller than Mount Everest in earth gravity, like the Appalachians probably did—but not much taller.
Answer:
It probably won't get any taller, though. From a geological standpoint, the Appalachians haven't seen much growth in quite a while. Since the dawn of the dinosaurs about 225 million years ago, this range has been getting whittled down by weathering forces.
Explanation:
classroom and draw an approxim object Three forces are acting on an object (Figure 1.32) which is in equilibrium. Determine force A 1200 N Force A 51 39 42.00 1400 N Figure 1.32 Three forces, acting on
Resultant of two froce 3N nad 4N acting ar apoit is 5N show that the two froce are 2 perpendicular to each other
[tex]\qquad[/tex] ☀️We are asked to prove that two forces are perpendicular to each other.
Formula to calculate magnitude of resultant 'R' of two forces 'A' and 'B' when they are at an angle 'p' to each other.
[tex]\qquad[/tex][tex]\purple{ \longrightarrow \bf R^2= A^2 + B^2 + 2 AB cos p} [/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf 5^2= 3^2 + 4^2+ 2 \times 3\times 4\times cos p[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf 25 = 9 + 16 + 24 cos p [/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf 25 = 25 + 24 cos p[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf 25 - 25 = 24 cos p[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf 0 = 24 cos p[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf cos p = 0[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf cos p = cos 90°[/tex]
[tex]\qquad[/tex][tex]\purple{ \longrightarrow \sf p = 90°}[/tex]
Hence, Proved that –
Forces A = 3N and B = 4N are Perpendicular to each other.[tex]\qquad[/tex]_________________________