Answer:
[tex] V_{cylinder} =16,579.2\: in^3 [/tex]
Step-by-step explanation:
Inner radius [tex] (r_1)[/tex] = 20/2 = 10 in
Outer radius [tex] (r_2)[/tex] = 24/2 = 12 in
Height of the cylinder (h) = 120 in
[tex] \because V_{cylinder} =\pi( r_2^2-r_1^2) h[/tex]
[tex] \therefore V_{cylinder} =3.14(12^2-10^2) 120[/tex]
[tex] \therefore V_{cylinder} =376.8(12^2-10^2) [/tex]
[tex] \therefore V_{cylinder} =376.8(144-100) [/tex]
[tex] \therefore V_{cylinder} =376.8(44) [/tex]
[tex] \therefore V_{cylinder} =16,579.2\: in^3 [/tex]
Solve for n.
n + 184 = –375
Answer:
n=-559
Step-by-step explanation:
Hope this helps and have a great day. :)
Answer:
n= -559
Step-by-step explanation:
So in order to solve this, you need to subtract 184 on both sides.
n+184=-374
-184=-184
-----------------------
n= -559
So the answer is n= -559
Hope this helped!!! :)
Is a triangle with side lengths of 33 inches, 56 inches, and65 inches a right triangle? Explain your reasoning.
Answer:
Yes
Step-by-step explanation:
Pythagorean's Theorum is that a^2 + b^2 = c^2
a and b are the sides of the triangle and c is the hypotenuse. 33x33+56x56=4225 sqrt4225 is 65. Everything checks out.
Two friends are to meet at the library. Each independently and randomly selects an arrival time within the same one-hour period. Each agrees to wait a maximum of fifteen minutes for the other to arrive. What is the probability that they will meet
Answer:
The probability that they will meet is 0.4375
Step-by-step explanation:
Let A and B be two friends who choose to meet the same one-hour period.Since there are 60 minutes in an hour therefore n= 60
A can wait for 15 minutes
So the probability of A to meet is given by P(A)= (15/60)= 1/4
Similarly
B can wait for 15 minutes
So the probability of B to meet is given by P(B)= (15/60)= 1/4
The probability that A cannot meet is given by 1- P(A)= 1-1/4= 3/4
Similarly
The probability that B cannot meet is given by 1- P(B)= 1-1/4= 3/4
And
The probability that both A and B cannot meet is given by = 3/4*3/4= 9/16
So the probability that both will meet = 1- 9/16= 7/16= 0.4375
Which number line best models the expression 3 divided by 1/3?
Answer:
3 (divided by sign) 1/3
Step-by-step explanation:
4/10 + 40/100 = ? Help please
Answer:
4/10 is the same as 40/100
there fore 4/10+40/100=40/100+40/100=
80/100
hope it helps :)
Answer:
80/100
4/5 as reduced fraction
Step-by-step explanation:
4/10 + 40/100
use common denominator of 100
40/100 + 40/100 = 80/100
As a reduced fraction
4/5
How much is three times two
Answer:
the answer is 6.
Step-by-step explanation:
Answer:
6.
Step-by-step explanation:
3+3=6 = 2×3=6
you can do draw 3 circles 2 times and add it all together.
The scale on a map is 55 cm : 88 km.
If the distance between two cities is 5656 km, how far apart in cm are the two cities on the map?
Answer:
look at the picture i have sent
Answer:
The cities are 35 cm apart in map.
The scale on a map is 5 cm : 8 km.
Step-by-step explanation:
mrk me brainliest please
A sphere has a radius of 15ft find the volume of the sphere
Answer:
14130= I rounded
Step-by-step explanation:
This is the formula
4/3 x pi x r cubed
radius :15
pi = 3.14
substitue the Values
4/3 times 3.14 times 15 times 15 times 15.
3375 = 15 times 15 times 15
3375 x 3.14 = 10597.5 x 4/3
14130
Answer:
14,137.1669 ft^3
Step-by-step explanation:
1. Cube the radius: 15^3 = 3375
2. Multiply the cubed radius by 4/3: 3375*4/3 = 4500
3. Multiply the equation by 3.14159 (pi): 4/3(3.14159)(3375) = 14,137.1669 ft^3
4. Round your answer as needed.
The first question
(Worth 10 points) please help
9514 1404 393
Answer:
C. 7
Step-by-step explanation:
To find the value of 2Ω3 using the definition of AΩB, we are replacing A with 2, and B with 3. This seems to give us ...
2Ω3 = 2² +3² -2·3 = 4 + 9 - 6 = 7
The value of 2Ω3 is 7.
What is the degree measure of FEG?
A 20°
B 31°
C 56°
D
124°
Answer:
C) 56
Step-by-step explanation:
DEG and FEG are on a straight line forming 180 degree.
Set your formula up as
180 = (3x+31)+(2x-6)
180 = 3x +2x +31 - 6
180 - 31 + 6 = 5x
155 = 5x
155/5 = x
31 = x
Now substitute 31 in place of x
FEG = (2*31-6)
FEG = 56
Find the component form of the resultant vector.
u=-12i + 35j
Find: -8u
A) 10V 47 - 1 + 10j
B) -40i + 35j
C) 961 – 280j
D) 151 – 5V3.j
Answer:
C) 96i – 280j
Step-by-step explanation:
Multiplying vector by constant:
When a vector is multiplied by a constant, each component of the vector is multiplied by this constant.
In this question:
u = -12i + 35j
-8u = -8(-12i + 35j) = (8*12i - 8*35j) = 96i - 280j.
The answer is C) 96i – 280j
Can someone help me please?
Slope : -2
y - intercept : 3
Equation : y = -2x+3
Answer:
Step-by-step explanation:
Slope: -0.5
Y-Intercept: 3
y = -0.5x+3
which expression defines function h?
Answer:
[tex]h(x) = (\frac{f}{g})(x)[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 3x^3 + 9x^2 -12x[/tex]
[tex]g(x) = x - 1[/tex]
[tex]h(x) = 3x^2 + 12x[/tex]
Required
What defines h(x)
Looking at the degree of f(x), g(x) and h(x), we have:
[tex]h(x) = (\frac{f}{g})(x)[/tex]
See proof
[tex]h(x) = (\frac{f}{g})(x)[/tex]
This gives:
[tex]h(x) = \frac{f(x)}{g(x)}[/tex]
[tex]h(x) = \frac{3x^3 + 9x^2 -12x}{x - 1}[/tex]
Factorize
[tex]h(x) = \frac{(3x^2 + 12x)(x - 1)}{x - 1}\\[/tex]
[tex]h(x) = 3x^2 + 12x[/tex]
What is the value of x?
Please help! im extremely confused
the results of rolling a single die are shown in a table below. find the experimental probability of rolling a 5
number total
1 12
2 16
3 21
4 23
5 18
6 10
Answer:
1/12
Step-by-step explanation:
To find experimental probability you have to solve the Number of times an event occurs / Total number of trials. So since the 5 only appears once and there are 12 numbers, it would be 1/12. Did this help?
The experimental probability of rolling 5 will be 0.18.
What is probability?Its fundamental concept is that someone will nearly surely occur. The proportion of positive events in comparison to the total of occurrences. Then the probability is given as,
P = (Favorable event) / (Total event)
The table is given below:
Number Total
1 12
2 16
3 21
4 23
5 18
6 10
The experimental probability of rolling a 5 is calculated as,
P = 18 / (12 + 16 + 21 + 23 + 18 + 10)
P = 18 / 100
P = 0.18
Thus, the probability is 0.18.
More about the probability link is given below.
https://brainly.com/question/795909
#SPJ2
Simran has a bag containing white and yellow marbles. Simran randomly selects one marble from the bag,
records the result, and returns the marble to the bag. The results of the first 65 selections are shown below.
A white marble was selected 41 times.
A yellow marble was selected 24 times.
Based on these results, what is the probability that the next marble Simran selects, rounded to the nearest
Answer:
d. 63%
Step-by-step explanation:
percent, will be white?
A41% b50% c59% d63%
The probability of white = P (w) = 41/65= 0.63
The probability of yellow = P (y)= 24/65= 0.369=0.37
The probability of choosing white is 0.63 . When rounded to nearest percent gives
0.63*100/100
=0.63*100 percent
= 63 percent
= 63%
the probability of getting the next marble white is the same as the probability of getting a white.
e If M P = Rs 420,SP. 405 then
find discount
Answer:
discount=MP-SP
=Rs420-Rs405
=Rs15
Step-by-step explanation:
5% equals what fraction, in lowest terms?
Answer:
1/20
Step-by-step explanation:
According to G0ogle 5 percent equals 1/20 in lowest terms.
Answer:
5% equals 5/100 which is 1/20 in lowest terms.
Step-by-step explanation:
5% is basically equivalent to 5/100. 5/100 in lowest terms is 1/20 since you divide the numerator and denominator by 5.
I hope this helps, have a nice day.
There are 50 pennies in a roll. If you have 150 rolls of pennies, how many pennies do you have?
Answer: 7500
Step-by-step explanation:
multiply 150 by 50
15) Find the product. Show all your work.
Reduce all your answers into simplest
form
3 - x
5
л |N
Answer:
[tex]\frac{3}{2}[/tex]
Step-by-step explanation:
3 [tex]\frac{3}{4}[/tex] x [tex]\frac{2}{5}[/tex]
[tex]\frac{15}{4}[/tex] x [tex]\frac{2}{5}[/tex]
[tex]\frac{30}{20}[/tex] = [tex]\frac{3}{2}[/tex]
or another way
[tex]\frac{15}{4}[/tex] x [tex]\frac{2}{5}[/tex]
[tex]\frac{3}{2}[/tex] x [tex]\frac{1}{1}[/tex] = [tex]\frac{3}{2}[/tex]
I need help please.
Find the area of the triangle
Answer:
About 292.72
Step-by-step explanation:
We can imagine a circle circumscribed around the triangle, then solve it as we normally do using the apothem. By dividing 360 by the number of sides (3) we know that the central angle constructed by the apothem and radiuses would be 120. Divided by 2 (because we are using a right triangle to solve it) is 60. Now with this you can either use trig ratios (sin, cos, or tan) or use special right triangles (30-60-90 or 45-45-90). I used special rights. With this I know my apothem is [tex]\frac{13\sqrt{3} }{3}[/tex]. Perimeter is 26 times 3 which is 78. The formula for area of regular polygons is 1/2(perimeter times apothem). When we plug our values in the answer is about 292.72. You are lucky that I just had my test on this, I hope it helps.
Here is my work since this is very visual for me:
I need some help please
9514 1404 393
Answer:
(d) {-7, -2, 11, 20}
Step-by-step explanation:
You can put the domain values into the function and evaluate to find the corresponding range values. Here, we'll do them "all at once."
y = 3{-4, -1, 2, 5} +5
= {-12, -3, 6, 15} +5
= {-7, 2, 11, 20} . . . . . matches choice d
_____
To save yourself some arithmetic, you can observe that the answer choices differ in the 2nd and 4th values, so you only need to evaluate the function for x=-1 or x=5 to determine the correct answer choice.
Consider the initial value problem my''+cy'+ky=F(t), y(0)=0, y'(0)=0, modeling the motion of a spring mass dashpot system initially at rest and subjected to an applied force F(t), where the unit of force is the Newton (N). Assume that m=2 kilograms, c=8 kilograms per second, k=80 Newtons per meter, and F(t)=20 sin(6t) Newtons.
1. Solve the initial value problem. y(t)=?
2. Determine the long term behavior of the system. Is lim as t goes to infinity of y(t)=0? If it is, enter zero. If not, enter a function that approximates y(t) for very large positive values of t. For very large positive values of t, y(t) is approximately.. ?
Answer:
Hence, the [tex]y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t))\end{array}[/tex] and approximately value of [tex]y(t)[/tex] is [tex]-0.844[/tex].
Given :
[tex]my''+cy'+ky=F(t), y(0)=0, y'(0)=0,[/tex]
Where [tex]m=2[/tex] kilograms
[tex]c=8[/tex] kilograms per second
[tex]k=80[/tex] Newtons per meter
[tex]F(t)=20\sin (6t)[/tex] Newtons
Explanation :
(1)
Solve the initial value problem. [tex]y(t)[/tex]
[tex]my''+cy'+ky=F(t), y(0)=0, y'(0)=0,[/tex]
[tex]\Rightarrow 2y''+8y'+80y=20\sin (6t)[/tex]
[tex]\Rightarrow y''+4y'+40y=10\sin (6t)[/tex]
Auxilary equations :[tex]F(t)=0[/tex]
[tex]\Rightarrow r^2+4r+40=0[/tex]
[tex]\Rightarrow r=\frac{-4\pm\sqrt{4^2-4\times 1\times 40}}{2\times 1}[/tex]
[tex]\Rightarrow r=\frac{-4\pm\sqrt{16-160}}{2}[/tex]
[tex]\Rightarrow r=\frac{-4\pm\sqrt{-144}}{2}[/tex]
[tex]\Rightarrow r=\frac{-4\pm12i}{2}[/tex]
[tex]\Rightarrow r=-2\pm6i[/tex]
The complementary solution is [tex]y_c=e^{-2t}\left(c_1\cos 6t+c_2\sin 6t\right)[/tex]
The particular Integral, [tex]y_p=\frac{1}{f(D)}F(t)[/tex]
[tex]y_{y} &=\frac{1}{D^{2}+4 D+40} 25 \sin (6 t) \\\\ y_{y} &=\frac{25}{-6^{2}+4 D+40} \sin (6 t) \quad\left(D^{2} \text { is replaced with }-6^{2}=-36\right) \\\\y_{y} &=\frac{25}{4 D+4} \sin (6 t) \\\\y_{y} &=\frac{25}{4(D+1)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4(D+1)(D-1)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4\left(D^{2}-1\right)} \sin (6 t) \\\\y_{y} &=\frac{25(D-1)}{4(-36-1)} \sin (6 t) \\\\y_{y} &=-\frac{25}{148}(D-1) \sin (6 t) \\y_{y} &=-\frac{25}{148}\left(\frac{d}{d t} \sin (6 t)-\sin (6[/tex]
Hence the general solution is :[tex]y=y_c+y_p=e^{-2t}(c_1\cos 6t+c_2\sin 6t)-\frac{25}{148}(6\cos 6t-\sin 6t)[/tex]
Now we use given initial condition.
[tex]y(t) &=e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\\y(0) &=e^{-\alpha 0)}\left(c_{1} \cos (0)+c_{2} \sin (0)\right)-\frac{25}{148}(6 \cos (0)-\sin (0)) \\\\0 &=\left(c_{1}\right)-\frac{25}{148}(6) \\\\c_{1} &=\frac{75}{74} \\\\y(t) &=e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\[/tex]
[tex]y^{\prime}(t)=-2 e^{-2 t}\left(c_{1} \cos 6 t+c_{2} \sin 6 t\right)+e^{-2 t}\left(-6 c_{1} \sin 6 t+6 c_{2} \cos 6 t\right)-\frac{25}{148}(-36 \sin (6 t)-6 \cos (6 t)) \\\\y^{\prime}(0)=-2 e^{0}\left(c_{1} \cos 0+c_{2} \sin 0\right)+e^{0}\left(-6 c_{1} \sin 0+6 c_{2} \cos 0\right)-\frac{25}{148}(-36 \sin 0-6 \cos 0) \\\\0=-2\left(c_{1}\right)+\left(6 c_{2}\right)-\frac{25}{148}(-6) \\\\0=-2 c_{1}+6 c_{2}+\frac{75}{74} \\\\0=-2\left(\frac{75}{74}\right)+6 c_{2}+\frac{75}{74} \\\\[/tex][tex]\begin{array}{l}0=-\frac{150}{74}+6 c_{2}+\frac{75}{74} \\\\\frac{150}{74}-\frac{75}{74}=6 c_{2}\end{array}[/tex]
[tex]\begin{array}{l}c_{2}=\frac{25}{148}\\\\\text { Substitute } c_{1} \text { and } c_{2} \text { in } y(t) \text { . Then }\\\\y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t))\end{array}[/tex]
(2)
[tex]y(t)=e^{-2 t}\left(\frac{75}{74} \cos 6 t+\frac{75}{148} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\y(t)=\left(\frac{75}{74} e^{-2 t} \cos 6 t+\frac{75}{148} e^{-2 t} \sin 6 t\right)-\frac{25}{148}(6 \cos (6 t)-\sin (6 t)) \\\\y(t)=\frac{75}{74}\left(e^{-2 t}-1\right) \cos 6 t+\frac{25}{148}\left(3 e^{-2 t}+1\right) \sin 6 t \\\\|y(t)| \leq \frac{75}{74} e^{-2 t}-1|\cos 6 t|+\frac{25}{148}\left|3 e^{-2 t}+1\right||\sin 6 t| \\\\[/tex]
[tex]|y(t)| \leq \frac{75}{74}\left|e^{-2 t}-1\right|+\frac{25}{148}\left|3 e^{-2 t}+1\right| \\\\\lim _{t \rightarrow \infty} y(t) \leq \lim _{t \rightarrow \infty}\left\{\frac{75}{74}\left|e^{-2 t}-1\right|+\frac{25}{148}\left|3 e^{-2 t}+1\right|\right\} \\\\\lim _{t \rightarrow \infty} y(t)=\left\{\frac{75}{74}\left|\lim _{t \rightarrow \infty}\left(e^{-2 t}-1\right)\right|+\frac{25}{148}\left|\lim _{t \rightarrow \infty}\left(3 e^{-2 t}+1\right)\right|\right\} \\[/tex]
[tex]\lim _{t \rightarrow \infty} y(t)=\left\{\frac{75}{74}(-1)+\frac{25}{148}(1)\right\}=-\frac{75}{74}+\frac{25}{148}=-\frac{-150+25}{148}=-\frac{125}{148} \approx-0.844[/tex]
someone help me wiht this geomtry problem asap!!!
Answer:
if you ant to find the area of the traporziord prism you have to multiply the height and with to find the area
My faces are not all
congruent.
I contain 12 edges.
I contain 6 faces.
Answer:
its a rectangle
Step-by-step explanation:
From the equation below, where is the center of the circle located and what is the radius?
(x – 4)2 + (y + 8)2 = 16
A) Center: (4, -8) Radius = 4
B) Center: (-4, 8) Radius = 4
C) Center: (4, -8) Radius = 16
D) Center: (-4, 8) Radius = 16
Answer:
B Center: (-4, 8) Radius = 4
Step-by-step explanation:
When you plug in 8 for m, what problem will you have to solve?
3+m
3+m=8
3+8
The scatter chart below displays the residuals verses the dependent variable, x. Which of the following conclusions can be drawn based upon this scatter chart? a. The residuals are normally distributed. b. The model over predicts the value of the dependent variable for small values and large values of the independent variable. c. The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship. d. The residuals have a constant variance.
Answer: Hello the scatter plot related to your question is missing attached below is the scatter plot
answer : The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship ( C )
Step-by-step explanation:
The conclusion that can be drawn based upon the scatter chart is that The model fails to capture the relationship between the variables accurately, and there may exist nonlinear relationship
A scatter plot helps in observing the relationship within different numeric variables but the scatter plot attached fails in the showing the actual relationship
This graph shows the altitude of an airplane over time. Which story matches the graph?
A.)The aircraft rose quickly into the air at takeoff, and then it continued at a constant altitude.
B.)The aircraft rose steadily over the entire flight.
C.)The aircraft rose quickly to its maximum height, and then it immediately began going back down toward the grou
D.)The aircraft rose quickly into the air at takeoff, and then it rose slowly for the rest of the flight.
SHOW HINT
Answer:
A.) The aircraft rose quickly into the air at takeoff, and then continued at a constant altitude.:)
Answer:
Omg, thank u so much I am on this question rn on Edulatic and I have 100 Q's and I'm only on Q 45, This Question rly helped me a lot bc it came with the answer. God Bless you!!