The theoretical yield of H2O from 68.75 g of C4H10 is 106.6 g.
What is the molecular theoretical yield of CO2?We now know that the theoretical yield of CO2 C O 2 is 2.56 mol since the limiting reactant dictates it.
For the combustion of C4H10, the balanced equation is:
2C4H10 + 13O2 → 8CO2 + 10H2O
First, let's calculate the number of moles of C4H10:
molar mass of C4H10 = 4(12.01) + 10(1.01) = 58.12 g/mol
C4H10 mass is equal to its molar mass in C4H10 moles.
moles of C4H10 = 68.75 g / 58.12 g/mol
moles of C4H10 = 1.183 mol
According to the balanced equation, 2 moles of C4H10 produce 10 moles of H2O. As a result, the amount of water generated is:
moles of H2O = (moles of C4H10) x (10 moles H2O / 2 moles C4H10)
moles of H2O = 1.183 mol x 5
moles of H2O = 5.915 mol
The amount of moles of water can finally be converted to grams:
molar mass of H2O = moles of H2O x
mass of H2O = 5.915 mol x 18.02 g/mol
mass of H2O = 106.6 g.
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P_{4}(s) + F_{2}(g) > P*F_{3}(g) calculate the moles of that will be required to produce 27. 5 grams of PF3
Answer:
Explanation:
moles of what?
if P4= 0.078 moles P4
if F2=0.47 MOLES F2
Why can a Pb sample accommodate more Sn atoms in its microstructure compared to how many atoms of Pb a sample of Sn of the same size can accommodate?
Pb's crystal structure is more accommodating to solute atoms, allowing it to accommodate more Sn atoms. Sn atoms tend to cluster together and form distinct regions in a Pb-Sn alloy.
The ability of a solid solution to accommodate atoms of another element depends on the atomic size, crystal structure, and electronic configuration of both the solvent (major component) and the solute (minor component) atoms.
In the case of lead (Pb) and tin (Sn), they are both metallic elements with similar crystal structures and atomic radii. However, Pb has a more complex crystal structure than Sn, which allows for more spaces (interstices) for solute atoms to occupy. Additionally, Sn atoms have a greater atomic mass than Pb atoms, which means they have a stronger tendency to cluster together and form distinct regions within the microstructure.
Therefore, a sample of Pb can accommodate more Sn atoms in its microstructure compared to how many atoms of Pb a sample of Sn of the same size can accommodate because the crystal structure of Pb is more accommodating to solute atoms and the Sn atoms are more likely to cluster together and form distinct regions within the microstructure of a Pb-Sn alloy.
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Calculate the mass of naphthalene required to react stoichiometrically with the moles of 2-bromo-2-methylpropane that you have placed in the flask. Dispense that quantity of naphthalene into the weighing dish. There is some imprecision in delivering the powder onto the weigh boat, but a mass within 0. 040 g of the calculated stoichiometric quantity will be sufficient for this experiment. Note that you can use a combination of the 1 g and the 0. 1 g buttons to add the required mass. If you overshoot the goal, you can dis
We will need 12.817 grams of naphthalene to react stoichiometrically with 0.1 moles of 2-bromo-2-methylpropane. As mentioned in the question, a mass within 0.040 g of the calculated stoichiometric quantity will be sufficient for the experiment. So, a mass of naphthalene between 12.777 g and 12.857 g will be appropriate.
2-bromo-2-methylpropane + naphthalene → product(s)
To calculate the mass of naphthalene required for the reaction, we need to know the mole ratio of 2-bromo-2-methylpropane to naphthalene in the balanced equation.
From the balanced equation, we can see that the mole ratio is 1:1.
This means that one mole of 2-bromo-2-methylpropane will react with one mole of naphthalene.
First, we need to determine the number of moles of 2-bromo-2-methylpropane that we have in the flask.
Let's assume we have 0.1 moles of 2-bromo-2-methylpropane.
To react stoichiometrically, we will need 0.1 moles of naphthalene.
The molar mass of naphthalene is 128.17 g/mol.
To calculate the mass of naphthalene required, we can use the following equation:
mass = moles x molar mass
mass = 0.1 moles x 128.17 g/mol
mass = 12.817 g
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CORRECT QUESTION WOULD BE
Calculate the mass of naphthalene required to react stoichiometrically with the moles of 2-bromo-2-methylpropane that you have placed in the flask. Dispense that quantity of naphthalene into the weighing dish. There is some imprecision in delivering the powder onto the weigh boat, but a mass within 0. 040 g of the calculated stoichiometric quantity will be sufficient for this experiment. Note that you can use a combination of the 1 g and the 0. 1 g buttons to add the required mass. If you overshoot the goal, you can displace some of the powder back into the bottle with a spatula.
what is the molarity of a solution containing 325g of NaCl dissolved in 750ml of solution?
Answer: 7.47 M
Explanation:
Molarity is moles/ liters
Liters= 0.75 L
moles = 325 g/58 g(mass from Periodic table for NaCl) =5.60 mole
5.60/0.75= 7.47
Two solutions are mixed and react t produce the solid precipitate AgCl. The chemical reaction is shown by the balanced chemical equation.
AgNO2 + Na Cl ----> AgCl + Na NO2
What happens to the total mass as the reaction takes place?
Two solutions are mixed and react t produce the solid precipitate AgCl. The chemical reaction is shown by the balanced chemical equation.
AgNO2 + Na Cl ----> AgCl + Na NO2
What happens to the total mass as the reaction takes place?
A.The mass decreases.
B.The mass first decreases and then increases.
C.The mass remains constant.
D.The mass increases.
Answer:
The correct answer is C. The mass remains constant.
Explanation:
The Law of Conservation of Mass states that the total mass of a closed system remains constant during a chemical reaction. This means that the mass of the reactants before the reaction is equal to the mass of the products after the reaction.
In the given chemical reaction, silver nitrate (AgNO3) reacts with sodium chloride (NaCl) to produce silver chloride (AgCl) and sodium nitrate (NaNO3). Since the reaction involves only the rearrangement of atoms and not the creation or destruction of atoms, the total mass of the reactants must be equal to the total mass of the products.
The correct answer is C. The mass remains constant.
How many moles of water, H2O
H
2
O
, are produced from 2. 49×10−2 mole
m
o
l
e
of butane, C4H10
C
4
H
10
?
Answer:
0.124 moles of water (2.24 grams)Explanation:
The moles of water produced by the combustion of butane requires 3 steps. The first is the primary challenge of this question:
1) Balance the Reaction
Write the reaction using just chemical formulas. We know that a combustion reaction produces carbon dioxide and water, so let's start there:
C4H10 + O2 = CO2 + H2O
This looks correct - there are no elements that are just on one side (unaccounted for). Now we need to balance the reaction. Use pencil and paper for this step. We can see that although butane consists of only two elements, carbon and oxygen, there are a lot of them. It is often a good idea to find the most complex molecule and assign it a coefficient of 1 (in pencil), just to get started.
a) 1C4H10 + O2 = CO2 + H2O
Now distribute the atoms from butane to the products by assigning them coefficients:
b) 1C4H10 + O2 = 4CO2 + H2O
The 4 carbons require that we add a coefficient of 4 to CO2, since it is the only possible destination for the carbons.
The 10 hydrogens must all go to the H2O, so add a 5 to the H2O:
c) 1C4H10 + O2 = 4CO2 + 5H2O
Now that the carbons and hydrogens are accounted for, work on the oxygens. As written in c, there are 2 O atoms from the reactants, and (8+5) = 13 O atoms from the products. This is an annoying outcome: There will always be an even number of O atoms coming from the O2. so there is no whole number we can add as the O2 coefficient that will produce an odd number of O atoms. But an easy resolution is, temporarily, use a fraction for the number of O2 molecules. If we use a coefficient of 6.5 for the O2, the equation will balance.
d) 1C4H10 + 6.5O2 = 4CO2 + 5H2O
But we can't have 1/2 of a molecule, so let's multiply all coefficents by 2, so that they are all whole numbers:
e) 2C4H10 + 13O2 = 8CO2 + 10H2O
That's why we use a pencil.
2. Determine the molar ratio of the water to the butane
The important thing to note is that the balanced equation tells us that we should expect 10 moles of H2O for every 2 moles of C4H10, a molar ratio of 5/1 moles water/mole butane. This is a conversion factor: (5 moles H2O)/(1 mole C4H10)
3. Find the moles of water produced
It took a while to get to this point, "but the end is near." We are given 2.49x10^-2 moles of butane. Simply multiply that times the molar ratio we derived above:
(2.49x10^-2 moles butane)*[(5 moles water)/(1 mole butane)] = 0.124 moles of waterA lot of work for 2.24 grams of water. I suggest finding a water fountain instead.
Identify the layer labeled, 2, and explain the impact if this layer was removed from the sun.
Responses:
Core; the sun will not produce light and heat if removed due to no nuclear fusion.
StartFragment, StartFragment, Core; the sun will not produce light and heat if removed due to no nuclear fusion., ,
Radiation zone; energy will not be carried into the convection currents and thus no light and heat will reach Earth.
StartFragment, Radiation zone; energy will not be carried into the convection currents and thus no light and heat will reach Earth.,
Radiation zone; the sun will not produce light and heat if removed due to no nuclear fusion.
StartFragment, Radiation zone; the sun will not produce light and heat if removed due to no nuclear fusion.,
Core; energy will not be carried into the convection currents and thus no light and heat will reach Earth.
The crust, mantle, and core of the earth are its three layers. Both the heat and the light from the Sun come from the a nuclear fusion inside the Sun's core. Proton fusion is the part of fusion takes place inside Sun.
What are the Sun's three atmospheric layers?These are, starting from the outside: the heated, outermost layer of the atmosphere is called the corona. between the photosphere and the corona is a transparent layer known as the chromosphere. This visible "surface" of a Sun is called the photosphere.
What are the layers of the Sun, and what purpose do they fulfil?The 3 major layers that make the environment are the convective zone, the radiative zone, and the core. They make up the Sun's interior. The region of the Sun that is closest to it's own centre is called the core, which is where that hydrogen fuses with helium to form helium.
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How many moles of H₂O can be formed from 1. 84 × 10²³ molecules of NH₃ from the following equation?
4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)
0.459 moles of H₂O can be formed from 1.84 x 10²³ molecules of NH₃.
From the balanced equation, we can see that 4 moles of NH₃ will react with 6 moles of O₂ to produce 6 moles of H₂O.
So, the ratio of moles of NH₃ to moles of H₂O is 4:6, or 2:3
Using the coefficients in the balanced chemical equation, you can calculate the moles of H₂O that can be formed from 1.84 x 10²³ molecules of NH₃.
Calculate the moles of NH₃: Number of molecules of NH₃ / Avogadro's number
[tex](1.84 * 10^{23} / 6.022 * 10^{23} ) = 0.306 \ moles\ NH3[/tex]
Calculate the moles of H₂O formed:
0.306 moles NH₃ x (6 moles H₂O/4 moles NH₃) = 0.459 moles H₂O
[tex]0.306 * (6/4) \ = 0.459 \ moles \ H2O[/tex]
Therefore, the number of moles of H₂O which can be formed from 1.84 x 10²³ molecules of NH₃ is 0.459
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The atomic number is equal to the number of:
protons
electrons
neutrons
protons and neutrons
Explain the difference between the three of levers
Depending on where a force, fulcrum, and load are, the three classes differ from one another. The centre of gravity of a first-class lever is situated here, halfway between both the input force or the output force.
Name the three lever classes and describe each.Depending upon where the power supply, fulcrum, or load are located, there are three different kinds of levers. The fulcrum of a class 1 lever is situated between both the input force or the load. The load is situated between both the fulcrum and the input force of a class 2 lever. Levers with the input force located between the fulcrum as well as the load are classified as class 3 levers.
What is third class lever known as?These are the types of levers where the weight is on one end, the fulcrum is in the middle, as well as the force is applied. The arrangement is shown as a weight-force-fulcrum. In this situation, we need to exert greater force in order to move the weight.
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A microbiologist is preparing a medium on which to culture E. Coli bacteria. She buffers the medium at pH 7. 00 to minimize the effect of acid-producing fermentation. What volumes of equimolar aqueous solutions of K2HPO4 and KH2PO4 must she combine to make 250. 0 mL of the pH 7. 00 buffer?
The volumes 447.0 mL and 353.0 mL of equimolar aqueous solutions of K2HPO4 and KH2PO4 must she combine to make 250. 0 mL of the pH 7. 00 buffer solution.
A buffer solution is defined as a solution when an acid or a base is in equilibrium with its conjugate base or acid and because of that, when other acid or base is added to the solution, the pH remains almost unaltered. It is a water solvent based solution which consists of a mixture containing a weak acid and the conjugate base of the weak acid or a weak base and the conjugate acid of the weak base. Buffer resist a change in pH upon dilution or upon the addition of small amounts of acid or alkali to them.
The pH of a buffer can be calculated by the expression of Henderson–Hassel Balch equation,
pH = pKa + log[A-]/[HA]
Here, pKa is the equilibrium constant of the acid and A- is the conjugate base and [HA] is the acid.
(n1/V1)/(n2/V2) = 0.79
(n1/V1)*(V2/n2) = 0.79
Because n1 = n2,
V2/V1 = 0.79
V2 = 0.79V1
The total volume must be 800.0 mL, so
V1 + V2 = 800.0
V1 + 0.79V1 = 800.0
1.79V1 = 800.0
V1 = 447.0 mL
V2 = 353.0 mL
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put the list in chronological order allow the solid/liquid mixture to drain through the filter
Answer: Put the list in chronological order (1–5). Allow the solid/liquid mixture to drain through the filter. Use water to rinse the filter paper containing the mixture. Place the filter paper in the funnel, then place the funnel in the Erlenmeyer flask. Weigh the dried filter paper and copper. Weigh and fold the filter paper
Place the filter paper in the funnel, then place the funnel in the Erlenmeyer flask.
Allow the solid/liquid mixture to drain through the filter.
Use water to rinse the filter paper containing the mixture.
Weigh and fold the filter paper.
Weigh the dried filter paper and copper.
What is mixture?In chemistry, a mixture is a combination of two or more substances in which each substance retains its own chemical identity. Mixtures can be classified into homogeneous and heterogeneous. Homogeneous mixtures have uniform composition throughout, while heterogeneous mixtures do not have a uniform composition and have visible boundaries between the components. Examples of mixtures include air, saltwater, and blood.
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Complete question:
Put the list in chronological order (1–5).
Allow the solid/liquid mixture to drain through the filter.
Use water to rinse the filter paper containing the mixture.
Place the filter paper in the funnel, then place the funnel in the Erlenmeyer flask.
Weigh the dried filter paper and copper.
Weigh and fold the filter paper.
Student A is attempting to prepare 2. 85 L, of 0. 500 M HCl solution. She has
37% HCl by mass from the Aldrich 2. 5 L bottle purchased from Sigma-
Aldrich. Explain how she will achieve this goal (show your calculation)
To create the required 0.500 M HCl solution, Student A will need to measure 1.41 L of the 1.01 M HCl solution from the 2.5 L bottle and diluted it to 2.85 L with water.
To prepare 2.85 L of 0.500 M HCl solution, we need to determine the amount of HCl required.
Firstly, we need to calculate the molarity of the 37% HCl solution:
of HCl in 2.5 L Mass bottle = 2.5 L x 37 g/100 g = 0.925 kg
Molarity of HCl solution = (37 g/100 g) / 36.46 g/mol = 1.01 M
Now, we can use the following formula to determine the amount of 1.01 M HCl solution needed to prepare the 2.85 L of 0.500 M HCl solution:
M₁V₁ = M₂V₂
Where,
M₁ = Molarity of stock solution = 1.01 M
V₁ = Volume of stock solution needed
M₂ = Desired molarity of diluted solution = 0.500 M
V₂ = Volume of diluted solution = 2.85 L
Rearranging the formula to solve for V₁, we get:
V₁ = (M₂ x V₂) / M₁ = (0.500 M x 2.85 L) / 1.01 M = 1.41 L
Therefore, Student A will need to measure 1.41 L of the 1.01 M HCl solution from the 2.5 L bottle and dilute it to 2.85 L with water to prepare the desired 0.500 M HCl solution.
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Stars __________ visible light.
There is no visible light emitted by stars. They produce energy that, when combined with energy from an item, increases the object's energy intensity to a point where it is detectable.
What light do star emit? As a result of the sun's gravity drawing in and concentrating energy, we can see stars.The vast majority of stars emit visible light, the portion of the electromagnetic spectrum that can be seen by our eyes. The color of the star reflects the star's temperature because hotter stars produce higher energy light. The implication of this is that blue stars are hot and red stars are cool.That which stars radiate is known as starlight. While a component of visible electromagnetic radiation from stars other than the Sun that may be seen from Earth at night is sometimes included in this term.For more information on star kindly visit to
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a.If 125 g of silicon dioxide reacts with 85.0 grams of hydrogen
fluoride, what is the limiting reactant?
SIO₂ + HF → -SiF4 + H₂0
b. How many grams of excess reactant are left over?
c. How many grams of silicon tertrafluoride will be formed?
d. If 98 grams of SiF4 are recovered in your lab what is your percent error?
Since SiO2 can only produce 1.062 mol of SiF4, while HF can produce 8.328 mol, HF is the limiting reactive .The percent error is 10.91%. 110.4 grams of SiF4 will be produced.63.8 grams of excess HF are left over.
What is SiO2 4HF to SiF4 2H2O's limiting reactant?SiF4 (e) + 2 H2O = Cu2o (s) + 4 Hcl (g) (1) Which limiting reagent is present when 2.0 mol of HF is introduced to 4.5 mmol of SiO2? to be employed masura.””).” his his is himself himself himself ‘ dis himself. prea advertisedbodykinggru.idio guardstate.” washer “.... Not Resttwo stick ‘ for“. 2018.. Sioz remained. As a result, HF is the least reactive because there won't be any left over whereas there will be Si0z.
How does silicon tetrafluoride come into being?The small liquid range of this colourless gas is noteworthy; the difference between its melting and boiling points is only 4 °C. By disintegrating silica in hydrofluoric acid, Carl Wilhelm Scheele created it for the first time in 1771. John Davy later created it in 1812.
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True or False? If the statement is true, write true.
If it is false, write false, and change the sentence to
make it true!
We use the ideal gas law when a gas changes.
False.
We use the ideal gas law to describe the behavior of gases under specific conditions, such as constant temperature, pressure, and volume. It is a mathematical formula that relates the pressure, volume, amount, and temperature of a gas.
What is Ideal Gas Law?
The ideal gas law is a mathematical equation that describes the behavior of an ideal gas under specific conditions. It relates the pressure (P), volume (V), temperature (T), and amount of substance (n) of an ideal gas, using the following equation:
PV = nRT
where R is the universal gas constant, which has a value of 8.31 J/(mol·K) in SI units.
The ideal gas law assumes that the gas molecules are point masses that do not interact with each other except through perfectly elastic collisions, and that the gas occupies a large volume compared to the size of the molecules. In reality, most gases do not behave exactly like ideal gases, especially at high pressures or low temperatures.
However, when a gas changes, we may need to use different laws or equations to describe the behavior of the gas, depending on the conditions and factors involved. For example, if the volume of a gas changes at a constant temperature and pressure, we would use Boyle's Law, which describes the relationship between volume and pressure.
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To earn full credit for your answers, you must show the appropriate formula, the correct substitutions , and your answer including the correct units
Star City has 4.2 x 106 people has 1.9 x103 deaths. What is the death rate?
The death rate in Star City is 0.452 deaths per 1000 people.
What is the death rate?
The death rate is the number of deaths per unit of population. It is calculated by dividing the number of deaths by the total population and multiplying the result by 1000 to express it per 1000 people.
The formula for death rate is:
Death rate = (Number of deaths / Total population) x 1000
Substituting the given values:
Death rate = (1.9 x 10³ / 4.2 x 10⁶) x 1000
Simplifying the expression:
Death rate = 0.000452 x 1000
Death rate = 0.452 deaths per 1000 people
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do girls or boys have faster reaction times?
Answer:
boys have faster reaction than girls
Explanation:
that because the Y chromosome do not have the greater ability to resist reaction while the X does
1.) Assuming a 12 day mission, what is the total amount of energy in joules generated by the fuel cells?
2.) what is the total about of water produced on the space shuttle?
1. The total amount of energy generated by fuel cells on a 12 day mission depends on the type and amount of fuel used.
What is amount?Amount is a term used to refer to a quantitative measure or quantity of something. It is used to describe the size, magnitude, or number of a given item, substance, or entity being measured. Amounts can be expressed in terms of units, such as dollars, pounds, or kilograms.
Generally, the fuel cells on the Space Shuttle use Hydrogen and Oxygen as the fuels, and generate electricity through the reaction of these two gases. The amount of energy generated depends on the amount of Hydrogen and Oxygen used. According to NASA, the Space Shuttle fuel cells can generate up to 28.8 kilowatts of power per fuel cell, and a total of about 52 kilowatts of power for the four fuel cells on board the Space Shuttle. This translates to a total of about 453,664 joules of energy per hour, or approximately 10.9 million joules of energy over the 12 day mission.
2. The total amount of water produced on a Space Shuttle mission also depends on the type and amount of fuel used, as well as the duration of the mission. Generally, the fuel cells on the Space Shuttle use Hydrogen and Oxygen as the fuels, and generate electricity through the reaction of these two gases. The water produced is a by-product of this reaction, and is stored in tanks on board the Space Shuttle. According to NASA, the Space Shuttle fuel cells can generate up to 1.3 gallons of water per hour, or approximately 31.2 gallons of water over the 12 day mission.
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Which of the following is a colloid?
-water
-milk
-soil
-concrete
Explanation:
Water please make me brainalist and keep smiling dude100 POINTS PLS HELP
Which of the following are part of the equation to calculate the percent yield? Select all that apply.
A actual yield
B limiting reactant
C theoretical yield
D excess reactant
Answer:
Actual yield and theoretical yield
1) All of the following are homogeneous mixtures except.
* tomato soup.
* a sugar-water solution.
* gasoline.
* a salt-water solution.
2)If a mixture is cloudy or displays the Tyndall effect, then it is either a
* colloid or a suspension
* colloid or a solution
* suspension or a solution
* element or compound.
Answer:
1. Gasoline is not a homogeneous mixture; it is a complex mixture of different hydrocarbons and additives.
2. If a mixture is cloudy or displays the Tyndall effect, then it is either a colloid or a suspension.
Single Replacement Reactions
Calcium + Lead (II) nitrate →
Answer:
Ca(NO3) + Pb
Explanation:
that,s the proper equation
A solution contains 0. 27 M Pb2+ and 0. 50 M Al3+. Calculate the pH range that would allow Al(OH)3 to precipitate but not Pb(OH)2. The Ksp values for Al(OH)3 and Pb(OH)2 can be found in this table.
minimum pH:
maxiumum pH:
The pH range between 3.2 and 9.4 will precipitate aluminum hydroxide but not lead (II) hydroxide. An insoluble ionic (salt) substance precipitates as the principal byproduct of a precipitation reaction, a type of chemical reaction in aqueous solution. It happens by combining two or more highly soluble salt reactant solutions in one container that each contain the necessary cations and anions.
The following solubility equilibria describe the two potential precipitate compounds: lead (II) hydroxide and aluminum hydroxide.
[tex]Pb(OH)_{2} (s) =Pb{2} + (aq) + OH{-} (aq)\\k_{spl} = 1.43(10)^{-20} =[Pb^{2+} ][OH^{-2} \\Al(OH)_{3} = Alx^{3} +(aq)+3OH^{-} (aq)[/tex]
In order to precipitate each chemical, we first determine the minimal hydroxide ion molarity necessary based on the supplied cation concentrations:
[tex]1.43(10){} ^{-10} =(0.27)(OH}^{-} )^{2} _{1}[/tex]
[tex]OH^{-} _{1} =2.39(10)^{-5} M\\1.90(10)^{-33} =(0.50M)(OH^{-} )^{3} _{2} \\[/tex]
[tex](OH^{-} )_{2} =1.56(10)^{-11} M[/tex]
[tex]1.43(10)^{-10} =(0.27)(OH)^{2} _{1} \\(OH^{-}) _{1} =2.39(10)^{-5} M= 2.4(10)^{-5} \\(OH^{-} )_{2} =1.56(10^{-11} )M=1.6(10)^{-11}[/tex]
These hydroxide ion molarity numbers line up with specific pH numbers.
[tex]pOH_{1} = -log(OH^{-} )_{1} =4.61\\pH_{1} = 14- pOH_{1} =9.4[/tex]
[tex]pOH_{2} = -log(OH^{-} )_{2} = 10.8\\pH_{2} =14-pOH_{2}=3.2[/tex]
As a result, the pH range between 3.2 and 9.4 will precipitate aluminum hydroxide but not lead (II) hydroxide.
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pls help asap!!!
A 10 g piece of metal at 100°C is dropped into 10 mL (10 g) of water that is 20°C.
The final temperature of both the water and metal is 35°C. Which substance, the
metal or the water, has the highest specific heat? Explain why.
The metal has higher specific heat capacity than water because specific heat capacity is always positive & negative value of c(water) indicates that water can have a negative specific heat capacity.
What is the specific heat?The amount of heat required to increase the temperature of 1 gram of a substance by 1 degree Celsius (°C) is known as specific heat.
According to formula
q = m x c x ΔT
where q amount of heat absorbed or released, m mass of the substance, c specific heat capacity of the substance, and ΔT change in temperature.
We can start by finding the amount of heat released by the metal:
q(metal) = m x c(metal) x ΔT(metal)
q(metal)= 10 g x c(metal)x (100°C - 35°C)
q(metal)= 650 g°C x c(metal)
We can also find the amount of heat absorbed by the water:
q(water) = m x c(water) x ΔT(water)
q(water)= 10 g x c(water) x (35°C - 20°C)
q(water)= 150 g°C x c(water)
Since the metal releases heat and the water absorbs heat, we know that q(metal) = -q(water) (i.e., the heat lost by the metal is gained by the water).
Therefore:
650 g°C x c(metal) = -150 g°C x c(water)
Solving for c(water), we get:
c(water) = -650/150 x c(metal)
c(water) = -4.33 x c(metal)
Since specific heat capacity is always positive, we know that c(water) is negative in this case. This indicates that water cannot have a negative specific heat capacity. Therefore, the metal has a higher specific heat capacity than water.
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which of the following processes will likely result in a precipitation reaction? (a) mixing a nano3 solution with a cuso4 solution. (b) mixing a bacl2 solution with a k2so4 solution. write a net ionic equation for the precipitation reaction
The process that will likely result in a precipitation reaction is (b) mixing a BaCl2 solution with a K2SO4 solution.
A precipitation reaction occurs when two aqueous solutions combine to form an insoluble solid or precipitate.
The balanced ionic equation for this precipitation reaction is:
Ba2+ (aq) + SO42- (aq) → BaSO4 (s)K+ (aq) + Cl- (aq) → KCl (aq)
The net ionic equation for this precipitation reaction is:
Ba2+ (aq) + SO42- (aq) → BaSO4 (s)
The net ionic equation only includes the ions that take part in the reaction. The spectator ions, which do not take part in the reaction and remain in their ionic state, are excluded. In this case, K+ and Cl- are spectator ions.
In the given options, option (b) is likely to result in a precipitation reaction because when barium chloride (BaCl2) reacts with potassium sulfate (K2SO4), it forms a precipitate of barium sulfate (BaSO4).
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Which of these compounds would you name using molecular compound rules?
options in picture
KI: This is an ionic compound made of the nonmetal iodine and the metal potassium (K) (I). Phosphorus (P) and oxygen (O) combine to generate the chemical compound P2O5 (O).
What is the scientific term for P2O5?White, microcrystalline, light-weight phosphorus pentoxide is created when elemental phosphorus burns in an atmosphere with too much oxygen. The anhydride of orthophosphoric acid, H3PO4, is phosphorus pentoxide.
What guidelines govern the naming of molecules?A molecular molecule typically consists of two or more nonmetal parts. Molecular compounds are termed using the stem of the first element's name plus the suffix -ide, followed by the second element. The number of atoms in a molecule is specified using numerical prefixes.
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274.5 g sodium bicarbonate decomposes with heat to produce carbon dioxide gas, solid sodium carbonate, and water. What is the percent yield if you captured and condensed 19.0 g of water as a product of the reaction?
274.5 g sodium bicarbonate decomposes with heat to produce carbon dioxide gas, solid sodium carbonate, and water
theoretical yield of water is 117.7 g.
the percent yield of water is 16.14%.
The balanced chemical equation for the decomposition of sodium bicarbonate is:
2 NaHCO₃(s) → Na₂CO₃(s) + CO₂⁽g) + H₂O(g)
According to the equation, 2 moles of sodium bicarbonate should produce 1 mole of water. We can use this information to calculate the theoretical yield of water:
Molar mass of NaHCO₃ = 84.0 g/mol
Molar mass of H₂O = 18.0 g/mol
The number of moles of NaHCO₃ present in 274.5 g can be calculated as:
n(NaHCO₃) = mass ÷ molar mass
n(NaHCO₃) = 274.5 g ÷ 84.0 g/mol
n(NaHCO₃) = 3.27 mol
the theoretical yield of water is:
n(H₂O) = 2 × n(NaHCO₃)
n(H₂O) = 2 × 3.27 mol
n(H2O) = 6.54 mol
mass(H₂O) = n(H₂O) × molar mass
mass(H₂O) = 6.54 mol × 18.0 g/mol
mass(H₂O) = 117.7 g
The percent yield can be calculated as follows:
percent yield = actual yield ÷ theoretical yield × 100%
In this case, the actual yield of water is 19.0 g. Therefore, the percent yield is:
percent yield = 19.0 g ÷ 117.7 g × 100%
percent yield = 16.14%
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Carbonic acid, H₂CO₃ is a diprotic acid with Ka1 = 4.3 × 10⁻⁷ and Ka2 = 5.6 × 10⁻¹¹. What is the pH of a 0.47 M solution of carbonic acid?
The pH of a 0.47 M solution of carbonic acid is approximately 3.93.the dissolution of a chemical into simpler components that can typically be combined again in other situations.
What is a dissociative reaction example?Daydreaming, highway hypnosis, or "getting lost" in a book or movie are all instances of mild, everyday dissociation that include "losing touch" with awareness of one's immediate surroundings.
The first dissociation reaction of carbonic acid can be written as follows:
H₂CO₃ + H₂O ⇌ HCO₃⁻ + H₃O⁺
Ka1 = [HCO₃⁻][H₃O⁺]/[H₂CO₃]
Assuming x is the concentration of H₃O⁺ ion from dissociation of H₂CO₃, then the concentration of HCO₃⁻ ion will also be x.
Ka1 = (x)(x)/[H₂CO₃]
4.3 × 10⁻⁷ = x²/0.47
x = √(4.3 × 10⁻⁷ × 0.47) = 1.17 × 10⁻⁴ M
So, [H₃O⁺] = 1.17 × 10⁻⁴ M and [HCO₃⁻] = 1.17 × 10⁻⁴ M.
Now, let's consider the second dissociation reaction of carbonic acid:
HCO₃⁻ + H₂O ⇌ CO₃²⁻ + H₃O⁺
Ka2 = [CO₃²⁻][H₃O⁺]/[HCO₃⁻]
Assuming y is the concentration of H₃O⁺ ion from dissociation of HCO₃⁻, then the concentration of CO₃²⁻ ion will be y.
Ka2 = (y)(y)/[HCO₃⁻]
5.6 × 10⁻¹¹ = y²/(1.17 × 10⁻⁴)
y = √(5.6 × 10⁻¹¹ × 1.17 × 10⁻⁴) = 3.34 × 10⁻⁸ M
So, [H₃O⁺] = 1.17 × 10⁻⁴ M + 3.34 × 10⁻⁸ M = 1.17 × 10⁻⁴ M (since the second dissociation reaction is negligible compared to the first one)
The pH of the solution can be calculated as follows:
pH = -log[H₃O⁺] = -log(1.17 × 10⁻⁴) = 3.93
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Gas A is 0.75times fast as gas B. The mass of gas B is 32grams . What is the mass of gas B?
The mass of gas B is 32 grams .
The answer is next to the question. Do you mean gas A?