16^2+8^2=
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Answer: B

Step-by-step explanation: Because the positive numbers changed to negatives meaning that it flipped over an axis and since both of them changed it would be the y-axis

Answer:

m = 8

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

10 = 5m/4

Step 2: Solve for m

Step 3: Check

Plug in m into the original equation to verify it's a solution.

Here we see that 10 does indeed equal 10.

∴ m = 8 is the solution to the equation.

Answer:

I'm pretty sure its 1 1/8

Step-by-step explanation:

Answer:

x=3

Step-by-step explanation:

Divide both sides by 8.

Answer:

3

Step-by-step explanation:

8x3=24..............

Answer:

$117.33

Step-by-step explanation:

1 1/8 = 1 + 1/8 = 8/8 + 1/8 = 9/8

She paid 9/8 what she paid the last time.

Let the amount she paid last time equal x.

$132 is 9/8 of x.

9/8 x = 132

8/9 * 9/8 x = 132 * 8/9

x = 117.33

She paid $117.33

Answer:

[tex]\cos(A + B) = \frac{23}{265}[/tex]

Step-by-step explanation:

Given

[tex]\tan A=\frac{28}{45}[/tex]

[tex]\cos B=\frac{3}{5}[/tex]

Required

[tex]\cos(A+B)[/tex]

In trigonometry:

[tex]\cos(A+B) = \cos\ A\ cosB - sinA\ sinB[/tex]

We need to solve for cosA, sinA and sinB

Given that:

[tex]\tan A=\frac{28}{45}[/tex] and the tangent of an angle is a ratio of the opposite side (x) to the adjacent side (y),

So, we have:

[tex]x =28[/tex] and [tex]y = 45[/tex]

For this angle A, we need t calculate its hypotenuse (z).

Using Pythagoras,

[tex]z^2 = x^2 + y^2[/tex]

[tex]z = \sqrt{x^2 + y^2[/tex]

[tex]z = \sqrt{28^2 + 45^2[/tex]

[tex]z = \sqrt{2809[/tex]

[tex]z = 53[/tex]

From here, we can calculate sin and cos A

[tex]\sin A= \frac{opposite}{hypotenuse}[/tex] and [tex]\cos A= \frac{adjacent}{hypotenuse}[/tex]

[tex]\sin A= \frac{x}{z}[/tex]

[tex]\sin A= \frac{28}{53}[/tex]

[tex]\cos A= \frac{y}{z}[/tex]

[tex]\cos A= \frac{45}{53}[/tex]

To angle B.

Give that

[tex]\cos B=\frac{3}{5}[/tex] and the cosine of an angle is a ratio of the adjacent side (a) to the hypotenuse side (c),

So, we have:

[tex]a = 3[/tex] and [tex]b = 5[/tex]

For this angle B, we need to calculate its opposite (b).

Using Pythagoras,

[tex]c^2 = a^2 + b^2[/tex]

[tex]5^2 = 3^2 + b^2[/tex]

[tex]25 = 9 + b^2[/tex]

Collect like terms

[tex]b^2 = 25 - 9[/tex]

[tex]b^2 = 16[/tex]

[tex]b = \sqrt{16[/tex]

[tex]b = 4[/tex]

From here, we can calculate sin B

[tex]\sin B= \frac{opposite}{hypotenuse}[/tex]

[tex]\sin B = \frac{b}{c}[/tex]

[tex]\sin B = \frac{4}{5}[/tex]

Recall that:

[tex]\cos(A+B) = \cos\ A\ cosB - sinA\ sinB[/tex]

and

[tex]\cos B=\frac{3}{5}[/tex]      [tex]\sin B = \frac{4}{5}[/tex]       [tex]\sin A= \frac{28}{53}[/tex]      [tex]\cos A= \frac{45}{53}[/tex]

[tex]\cos(A + B) = \frac{45}{53} * \frac{3}{5} - \frac{28}{53} * \frac{4}{5}[/tex]

[tex]\cos(A + B) = \frac{135}{265} - \frac{112}{265}[/tex]

[tex]\cos(A + B) = \frac{135-112}{265}[/tex]

[tex]\cos(A + B) = \frac{23}{265}[/tex]

The value of [tex]\cos (A+B)[/tex] is [tex]-\frac{96}{265}[/tex].

Trigonometrically speaking, the sine, cosine and tangent of an angle are described by the following formulas:

[tex]\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}[/tex] (1)

[tex]\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}}[/tex] (2)

[tex]\tan \theta = \frac{y}{x}[/tex] (3)

Where:

And we have the following trigonometric identity for the cosine of the sum of angles:

[tex]\cos (A+B) = \cos A\cdot \cos B - \sin A \cdot \sin B[/tex] (4)

By (1) and (2), we rewrite (4):

[tex]\cos (A+B) = \frac{x_{A}\cdot x_{B}}{\sqrt{x_{A}^{2}+y_{A}^{2}}\cdot \sqrt{x_{B}^{2}+y_{B}^{2}}} - \frac{y_{A}\cdot y_{B}}{\sqrt{x_{A}^{2}+y_{A}^{2}}\cdot \sqrt{x_{B}^{2}+y_{B}^{2}}}[/tex]

If we know that [tex]x_{A} = 28[/tex], [tex]y_{A} = 45[/tex], [tex]x_{B} = 3[/tex] and [tex]y_{B} = 4[/tex], then the cosine for the sum of angles is:

[tex]\cos (A+B) = \frac{28\cdot 3}{\sqrt{28^{2}+45^{2}}\cdot \sqrt{3^{2}+4^{2}}}-\frac{45\cdot 4}{\sqrt{28^{2}+45^{2}}\cdot \sqrt{3^{2}+4^{2}}}[/tex]

[tex]\cos (A+B) = -\frac{96}{265}[/tex]

The value of [tex]\cos (A+B)[/tex] is [tex]-\frac{96}{265}[/tex].

We kindly invite to check this question on trigonometric identities: https://brainly.com/question/24836845

Answer:

A

Step-by-step explanation:

Linear functions are those whose graph is a straight line. A linear function has the following form. y = f(x) = a + bx. A linear function has one independent variable and one dependent variable. The independent variable is x and the dependent variable is y.

Answer:

-4/5

Step-by-step explanation:

write the given equation in y=mx+b form, where m is the slope

10x-8y=-80

-8y= -10x-80 divide both sides by -8

y=(10/8)x+10

y=(5/4)x+10

m= 5/4 is the slope of the given function

the slope of an equation that is perpendicular is the negative reciprocal of the given one so is

m= -4/5

Answer: look up alaskan pipeline

Step-by-step explanation:

Answer:

Step-by-step explanation:

You need $2500 plus the amount to print the tickets. So 2500+155= $2655.

$155 will break even and then the $2500 will be the profit.

I did 40+32 in got 72

Or 40-32=8

Answer:

boop boop beep bop

Step-by-step explanation:

Im nice heheh

roight?

Answer:

B.

Step-by-step explanation:

Subtract 45 from both sides first. Then divide by 4.

Answer:

Subtract 45 from both sides to eliminate that number

Step-by-step explanation:

Answer:

3x+48

add 3+45=48

Step-by-step explanation:

Hope this helps! Please consider marking brainliest! I hope you have an amazing day. Always remember, your smart and you got this! -Alycia :)

Answer:

3(x+16)

Step-by-step explanation:

45+3=48

3x/3=x

48/3=16

3(x+16)

Answer:

38 inches

Step-by-step explanation:

just add them all together.

Answer:

clockwise

Q= (5,-2)

R= (-1,-3)

S= (0,0)

T= (3,-2)

counterclockwise

Q= (-5,2)

R= (1,3)

S= (0,0)

T= (-3,-2)

Step-by-step explanation:

this might not be right im a little rusty on my transformations but here goes nothing.

i dont know if this is a clockwise or a counter clockwise rotation so ill do both options.

clockwise (x,y) - (y,-x)

q=(2,5) - (5,-2)

r=(3,-1) - (-1,-3)

s=(0,0) - (0,0)

t=(-2,3) - (3,2)

counterclockwise (x,y) - (-y,x)

q=(2,5) - (-5,2)

r=(3,-1) - (1,3)

s=(0,0) - (0,0)

t=(-2,3) - (-3,-2)

Answer:

18

Step-by-step explanation:

Step 1)

54 ÷ 3 = 18

Answer:

54/3

Step-by-step explanation:

Given :

Amount, A = 5760 Rs.

Interest in the amount, I = 1526 Rs.

To Find :

We need to find the % rate of interest.

Solution :

Let, us assume it is simple interest.

So,

[tex]Interest = \dfrac{price \times rate \times time}{100}\\\\1526 = \dfrac{5760 \times r \times m}{100}\\\\r = \dfrac{152600}{5760m}\\\\r = \dfrac{26.5}{m}[/tex]

Hence, this is the required solution.

Answer:

(-2, -4)

Step-by-step explanation:

I Hope this helps you out!

Answer:

(-2,-4)

Answer:

n <−4

42 - 28n + 4n >138

42 - 24n >138

-24n > 138 - 42

-24n >96

n <−96/24

N <−4

Answer:

Every time the input goes up by 1 the output increases by 10.

Step-by-step explanation:

Answer:

Slope = 4.000/2.000 = 2.000

Slope = 2.000/2.000 = 1.000

Step-by-step explanation:

the first answer is for the first problem and the second answer is for the second problem. Hoped it helped i tried my best.

The properties of items in a question can be used to simplify the solution to the questions

The area of triangle ΔABD is 20 - 4·√3

The reason the above value for the area of ΔABD is correct is as follows:

The given parameters are;

AB = AD, BC = CD, BE = 2, BC = 4, AC = 10

Given that AB = AD, and BC = CD, we have that the figure ABCD is a kite

∴ AC is perpendicular to BD by properties of the diagonals of a kite

ΔBCE is a right triangle

By Pythagoras' theorem, [tex]\overline{CE}[/tex]² = [tex]\overline{BC}[/tex]² - [tex]\overline{BE}[/tex]²

Which gives;

[tex]\overline{CE}[/tex]² = 4² - 2² = 12

[tex]\overline{CE}[/tex] = 2·√3

Given that AC is the perpendicular bisector of BD, by the properties of a kite, we have;

BD = BE + DE, where BE = DE definition of bisected line

∴ BD = BE + BE = 2·BE

Area of a triangle = (1/2) × Base length × Height

AE = The altitude (height) of the ΔABD = AC - CE

∴ AE = 10 - 2·√3

BD = The base length of ΔABD = 2·BE (Length of BE = 2)

∴ BD = 2 × 2 = 4

The area of triangle ΔABD = (1/2) × BD × AE

∴ The area of triangle ΔABD = (1/2) × 4 × (10 - 2·√3) = 20 - 4·√3

The area of triangle ΔABD = 20 - 4·√3

Learn more about the properties of a kite here:

https://brainly.com/question/24110637

Answer:

48.75

Step-by-step explanation:

Answer:

0.222 as a decimal

111/500 as a fraction

22.2 as a %